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Funk transform

Funk transform is a mathematics topic covered in the lgStudy science library. This page brings together a partial reference excerpt, illustrations, worked examples, real-world applications and a short study plan, so you can understand Funk transform rather than just read about it. In short: In the mathematical field of integral geometry, the Funk transform (also known as Minkowski–Funk transform, Funk–Radon transform or spherical Radon transform) is an integral transform defined by integrating a function on great circles of the sphere. It was introduced by Paul Funk in 1911, based on the work of Minkowski (1904).

Key takeaways

  • Funk transform belongs to mathematics; place it in that map before memorising details.
  • Learn the definition first, then one example that makes the definition concrete.
  • Connect Funk transform to a quantity you can measure, compute or draw — that is where exam questions come from.
  • Reproduce the core statement of Funk transform from memory before moving on to harder problems.

Reference excerpt

In the mathematical field of integral geometry, the Funk transform (also known as Minkowski–Funk transform, Funk–Radon transform or spherical Radon transform) is an integral transform defined by integrating a function on great circles of the sphere. It was introduced by Paul Funk in 1911, based on the work of Minkowski (1904). It is closely related to the Radon transform. The original motivation for studying the Funk transform was to describe Zoll metrics on the sphere.

Definition The Funk transform is defined as follows. Let ƒ be a continuous function on the d-1-sphere Sd-1 in Rd. Then, for a unit vector x, let

F f ( x ) = ∫ u ∈ C ( x ) f ( u ) d s ( u ) {\displaystyle Ff(\mathbf {x} )=\int _{\mathbf {u} \in C(\mathbf {x} )}f(\mathbf {u} )\,ds(\mathbf {u} )}

where the integral is carried out with respect to the arclength ds of the great circle C(x) consisting of all unit vectors perpendicular to x:

C ( x ) = { u ∈ S d − 1 ∣ u ⋅ x = 0 } . {\displaystyle C(\mathbf {x} )=\{\mathbf {u} \in S^{d-1}\mid \mathbf {u} \cdot \mathbf {x} =0\}.}

Inversion The Funk transform annihilates all odd functions, and so it is natural to confine attention to the case when ƒ is even. In that case, the Funk transform takes even (continuous) functions to even continuous functions, and is furthermore invertible.

Spherical harmonics Every square-integrable function f ∈ L 2 ( S 2 ) {\displaystyle f\in L^{2}(S^{2})} on the sphere can be decomposed into spherical harmonics Y n k {\displaystyle Y_{n}^{k}}

f = ∑ n = 0 ∞ ∑ k = − n n f ^ ( n , k ) Y n k . {\displaystyle f=\sum _{n=0}^{\infty }\sum _{k=-n}^{n}{\hat {f}}(n,k)Y_{n}^{k}.}

Then the Funk transform of f reads

F f = ∑ n = 0 ∞ ∑ k = − n n P n ( 0 ) f ^ ( n , k ) Y n k {\displaystyle Ff=\sum _{n=0}^{\infty }\sum _{k=-n}^{n}P_{n}(0){\hat {f}}(n,k)Y_{n}^{k}}

where P 2 n + 1 ( 0 ) = 0 {\displaystyle P_{2n+1}(0)=0} for odd values and

P 2 n ( 0 ) = ( − 1 ) n 1 ⋅ 3 ⋅ 5 ⋯ 2 n − 1 2 ⋅ 4 ⋅ 6 ⋯ 2 n = ( − 1 ) n ( 2 n − 1 ) ! ! ( 2 n ) ! ! {\displaystyle P_{2n}(0)=(-1)^{n}\,{\frac {1\cdot 3\cdot 5\cdots 2n-1}{2\cdot 4\cdot 6\cdots 2n}}=(-1)^{n}\,{\frac {(2n-1)!!}{(2n)!!}}}

for even values. This result was shown by Funk (1913).

Helgason's inversion formula Another inversion formula is due to Helgason (1999). As with the Radon transform, the inversion formula relies on the dual transform F* defined by

… excerpt ends here. Continue reading the full article.

Worked examples

Example 1 — a first encounter with Funk transform

Start with the simplest possible case. Write down what Funk transform claims or describes in one sentence, then invent the smallest concrete situation in which that sentence is true. In mathematics, the smallest case is usually a single object, a single equation or a single measurement. Check that every symbol or term in your sentence has a meaning in that case.

Example 2 — changing one variable

Take the situation from Example 1 and change exactly one quantity: double it, halve it, or set it to zero. Predict what should happen to Funk transform before you calculate. Comparing your prediction with the result is the fastest way to find out whether you understand the idea or only the words.

Example 3 — an exam-style question

Typical questions about Funk transform ask you to (a) state it precisely, (b) apply it to given data, and (c) explain a limitation. Practise writing all three answers in under five minutes; the third part is what separates a full-mark answer from an average one.

Applications of Funk transform

In research
Funk transform appears in mathematics research whenever the underlying quantities have to be modelled precisely. Papers usually cite it as a starting assumption and then explore where it breaks down.
In technology and industry
Engineering practice reuses Funk transform in design rules, simulations and safety margins. Knowing the idea lets you read a specification sheet and understand why the numbers look the way they do.
In the classroom
Funk transform is common in secondary-school and first-year university syllabi. It links to neighbouring topics Integral geometry, Integral transforms, so understanding it makes those chapters shorter.
In everyday life
Look for Funk transform outside the textbook — in sport, cooking, traffic, electronics or the sky above you. An example you found yourself is remembered far longer than one you were given.
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How to study Funk transform in 20 minutes

  1. Read the reference excerpt below once, without taking notes.
  2. Close the page and write down what Funk transform means in your own words.
  3. Compare your version with the excerpt and mark what you missed.
  4. Work through the three examples above with pen and paper.
  5. Explain Funk transform out loud to somebody else — or to Teacher Smith in the lgStudy chat.

Frequently asked questions

What is Funk transform in simple terms?

In the mathematical field of integral geometry, the Funk transform (also known as Minkowski–Funk transform, Funk–Radon transform or spherical Radon transform) is an integral transform defined by integrating a function on great circles of the sphere. It was introduced by Paul Funk in 1911, based on…

Why does Funk transform matter?

Because it connects several mathematics ideas at once: it gives you a definition you can apply, a quantity you can calculate, and a way to check whether a result is plausible.

How should I study Funk transform?

Read the excerpt, restate it from memory, then work through the examples and applications listed on this page. The five-step study plan above takes about twenty minutes.

What does this page cover?

It gives you a compact reference excerpt plus original lgStudy explanations, examples, applications and study material on Funk transform.

Tags

  • Integral geometry
  • Integral transforms

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