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Gibbs–Thomson equation

Gibbs–Thomson equation is a mathematics topic covered in the lgStudy science library. This page brings together a partial reference excerpt, illustrations, worked examples, real-world applications and a short study plan, so you can understand Gibbs–Thomson equation rather than just read about it. In short: The Gibbs–Thomson effect, in common physics usage, refers to variations in vapor pressure or chemical potential across a curved surface or interface. The existence of a positive interfacial energy will increase the energy required to form small particles with high curvature, and these particles will exhibit an increased vapor pressure.

Key takeaways

  • Gibbs–Thomson equation belongs to mathematics; place it in that map before memorising details.
  • Learn the definition first, then one example that makes the definition concrete.
  • Connect Gibbs–Thomson equation to a quantity you can measure, compute or draw — that is where exam questions come from.
  • Reproduce the core statement of Gibbs–Thomson equation from memory before moving on to harder problems.

Reference excerpt

The Gibbs–Thomson effect, in common physics usage, refers to variations in vapor pressure or chemical potential across a curved surface or interface. The existence of a positive interfacial energy will increase the energy required to form small particles with high curvature, and these particles will exhibit an increased vapor pressure. See Ostwald–Freundlich equation. More specifically, the Gibbs–Thomson effect refers to the observation that small crystals that are in equilibrium with their liquid, melt at a lower temperature than large crystals. In cases of confined geometry, such as liquids contained within porous media, this leads to a depression in the freezing point / melting point that is inversely proportional to the pore size, as given by the Gibbs–Thomson equation.

Introduction The technique is closely related to using gas adsorption to measure pore sizes, but uses the Gibbs–Thomson equation rather than the Kelvin equation. They are both particular cases of the Gibbs Equations of Josiah Willard Gibbs: the Kelvin equation is the constant temperature case, and the Gibbs–Thomson equation is the constant pressure case. This behaviour is closely related to the capillary effect and both are due to the change in bulk free energy caused by the curvature of an interfacial surface under tension. The original equation only applies to isolated particles, but with the addition of surface interaction terms (usually expressed in terms of the contact wetting angle) can be modified to apply to liquids and their crystals in porous media. As such it has given rise to various related techniques for measuring pore size distributions. (See Thermoporometry and cryoporometry.) The Gibbs–Thomson effect lowers both melting and freezing point, and also raises boiling point. However, simple cooling of an all-liquid sample usually leads to a state of non-equilibrium super cooling and only eventual non-equilibrium freezing. To obtain a measurement of the equilibrium freezing event, it is necessary to first cool enough to freeze a sample with excess liquid outside the pores, then warm the sample until the liquid in the pores is all melted, but the bulk material is still frozen. Then, on re-cooling the equilibrium freezing event can be measured, as the external ice will then grow into the pores. This is in effect an "ice intrusion" measurement (cf. mercury intrusion), and as such in part may provide information on pore throat properties. The melting event can be expected to provide more accurate information on the pore body.

For particles For an isolated spherical solid particle of diameter d {\displaystyle d} in its own liquid, the Gibbs–Thomson equation for the structural melting point depression can be written:

Δ T m = T m B − T m ( d ) = T m B 4 σ s l H f ρ s d {\displaystyle \Delta \,T_{m}=T_{mB}-T_{m}(d)=T_{mB}{\frac {4\sigma _{sl}}{H_{f}\rho _{s}d}}}

where:

TmB = bulk melting temperature σsl = solid–liquid interface energy (per unit area) Hf = bulk enthalpy of fusion (per gram of material) ρs = density of solid d = nanoparticle size

For liquids in pores Very similar equations may be applied to the growth and melting of crystals in the confined geometry of porous systems. However the geometry term for the crystal-liquid interface may be different, and there may be additional surface energy terms to consider, which can be written as a wetting angle term cos ⁡ ϕ {\displaystyle \cos \phi \,} . The angle is usually considered to be near 180°. In cylindrical pores there is some evidence that the freezing interface may be spherical, while the melting interface may be cylindrical, based on preliminary measurements for the measured ratio for Δ T f / Δ T m {\displaystyle \Delta \,T_{f}/\Delta \,T_{m}} in cylindrical pores. Thus for a spherical interface between a non-wetting crystal and its own liquid, in an infinite cylindrical pore of diameter x {\displaystyle x} , the structural melting point depression is given by:

Δ T m ( x ) = T m B − T m ( x ) = − T m B 4 σ s l cos ⁡ ϕ H f ρ s x {\displaystyle \Delta \,T_{m}(x)=T_{mB}-T_{m}(x)=-T_{mB}{\frac {4\sigma \,_{sl}\cos \phi \,}{H_{f}\rho \,_{s}x}}}

Simplified equation The Gibbs–Thomson equation may be written in a compact form:

… excerpt ends here. Continue reading the full article.

Worked examples

Example 1 — a first encounter with Gibbs–Thomson equation

Start with the simplest possible case. Write down what Gibbs–Thomson equation claims or describes in one sentence, then invent the smallest concrete situation in which that sentence is true. In mathematics, the smallest case is usually a single object, a single equation or a single measurement. Check that every symbol or term in your sentence has a meaning in that case.

Example 2 — changing one variable

Take the situation from Example 1 and change exactly one quantity: double it, halve it, or set it to zero. Predict what should happen to Gibbs–Thomson equation before you calculate. Comparing your prediction with the result is the fastest way to find out whether you understand the idea or only the words.

Example 3 — an exam-style question

Typical questions about Gibbs–Thomson equation ask you to (a) state it precisely, (b) apply it to given data, and (c) explain a limitation. Practise writing all three answers in under five minutes; the third part is what separates a full-mark answer from an average one.

Applications of Gibbs–Thomson equation

In research
Gibbs–Thomson equation appears in mathematics research whenever the underlying quantities have to be modelled precisely. Papers usually cite it as a starting assumption and then explore where it breaks down.
In technology and industry
Engineering practice reuses Gibbs–Thomson equation in design rules, simulations and safety margins. Knowing the idea lets you read a specification sheet and understand why the numbers look the way they do.
In the classroom
Gibbs–Thomson equation is common in secondary-school and first-year university syllabi. It links to neighbouring topics Surface science, Thermodynamic equations, so understanding it makes those chapters shorter.
In everyday life
Look for Gibbs–Thomson equation outside the textbook — in sport, cooking, traffic, electronics or the sky above you. An example you found yourself is remembered far longer than one you were given.
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How to study Gibbs–Thomson equation in 20 minutes

  1. Read the reference excerpt below once, without taking notes.
  2. Close the page and write down what Gibbs–Thomson equation means in your own words.
  3. Compare your version with the excerpt and mark what you missed.
  4. Work through the three examples above with pen and paper.
  5. Explain Gibbs–Thomson equation out loud to somebody else — or to Teacher Smith in the lgStudy chat.

Frequently asked questions

What is Gibbs–Thomson equation in simple terms?

The Gibbs–Thomson effect, in common physics usage, refers to variations in vapor pressure or chemical potential across a curved surface or interface. The existence of a positive interfacial energy will increase the energy required to form small particles with high curvature, and these particles wil…

Why does Gibbs–Thomson equation matter?

Because it connects several mathematics ideas at once: it gives you a definition you can apply, a quantity you can calculate, and a way to check whether a result is plausible.

How should I study Gibbs–Thomson equation?

Read the excerpt, restate it from memory, then work through the examples and applications listed on this page. The five-step study plan above takes about twenty minutes.

What does this page cover?

It gives you a compact reference excerpt plus original lgStudy explanations, examples, applications and study material on Gibbs–Thomson equation.

Tags

  • Surface science
  • Thermodynamic equations

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