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Graham's law

Graham's law is a science topic covered in the lgStudy science library. This page brings together a partial reference excerpt, illustrations, worked examples, real-world applications and a short study plan, so you can understand Graham's law rather than just read about it. In short: Graham's law of effusion (also called Graham's law of diffusion) was formulated by Scottish physical chemist Thomas Graham in 1848. Graham found experimentally that the rate of effusion of a gas is inversely proportional to the square root of the molar mass of its particles.

Graham's law — main illustration
Graham's law — illustration

Key takeaways

  • Graham's law belongs to science; place it in that map before memorising details.
  • Learn the definition first, then one example that makes the definition concrete.
  • Connect Graham's law to a quantity you can measure, compute or draw — that is where exam questions come from.
  • Reproduce the core statement of Graham's law from memory before moving on to harder problems.

Reference excerpt

Graham's law of effusion (also called Graham's law of diffusion) was formulated by Scottish physical chemist Thomas Graham in 1848. Graham found experimentally that the rate of effusion of a gas is inversely proportional to the square root of the molar mass of its particles. This formula is stated as

rate 1 rate 2 = M 2 M 1 , {\displaystyle {\frac {{\text{rate}}_{1}}{{\text{rate}}_{2}}}={\sqrt {\frac {M_{2}}{M_{1}}}},}

where

rate1 is the rate of effusion for the first gas (volume or number of moles per unit time), rate2 is the rate of effusion for the second gas, M1 is the molar mass of gas 1, M2 is the molar mass of gas 2. Graham's law states that the rate of diffusion or of effusion of a gas is inversely proportional to the square root of its molecular weight. Thus, if the molecular weight of one gas is four times that of another, it would diffuse through a porous plug or escape through a small pinhole in a vessel at half the rate of the other (heavier gases diffuse more slowly). A complete theoretical explanation of Graham's law was provided years later by the kinetic theory of gases. Graham's law provides a basis for separating isotopes by diffusion—a method that came to play a crucial role in the development of the atomic bomb. Graham's law is most accurate for molecular effusion which involves the movement of one gas at a time through a hole. It is only approximate for diffusion of one gas in another or in air, as these processes involve the movement of more than one gas. In the same conditions of temperature and pressure, the molar mass is proportional to the mass density. Therefore, the rates of diffusion of different gases are inversely proportional to the square roots of their mass densities:

rate ∝ 1 ρ , {\displaystyle {\text{rate}}\propto {\frac {1}{\sqrt {\rho }}},}

where ρ is the mass density.

Examples First example: Let gas 1 be H2, and gas 2 be O2. This example is solving for the ratio between the rates of the two gases:

rate ( H 2 ) rate ( O 2 ) = M ( O 2 ) M ( H 2 ) = 32 2 = 16 = 4. {\displaystyle {\frac {{\text{rate}}({\ce {H2}})}{{\text{rate}}({\ce {O2}})}}={\sqrt {\frac {M({\ce {O2}})}{M({\ce {H2}})}}}={\frac {\sqrt {32}}{\sqrt {2}}}={\sqrt {16}}=4.}

Therefore, hydrogen molecules effuse four times faster than oxygen molecules. Graham's law can also be used to approximately determine the molecular weight of a gas if one gas is a known species and there is a specific ratio between the rates of two gases (as in the previous example). The equation can be solved for the unknown molecular weight:

M 2 = ( rate 1 rate 2 ) 2 M 1 . {\displaystyle M_{2}=\left({\frac {{\text{rate}}_{1}}{{\text{rate}}_{2}}}\right)^{2}M_{1}.}

Graham's law was the basis for separating uranium-235 from uranium-238 found in natural uraninite (uranium ore) during the Manhattan Project to build the first atomic bomb. The United States government built a gaseous diffusion plant at the Clinton Engineer Works in Oak Ridge, Tennessee, at the cost of $479 million (equivalent to $6.61 billion in 2024). In this plant, yellowcake, uranium concentrate recovered from the leaching of uranium ore, was first converted to volatile uranium hexafluoride. UF6 was then heated in the vapor state and repeatedly forced to diffuse through porous barriers, each time becoming a little more enriched in the slightly lighter uranium-235 isotope. Second example: An unknown gas diffuses 0.25 times as fast as He. What is the molar mass of the unknown gas? Using the formula of gaseous diffusion, we can set up the equation

… excerpt ends here. Continue reading the full article.

Illustrations

Graham's law: Thomas Graham
Thomas Graham

Worked examples

Example 1 — a first encounter with Graham's law

Start with the simplest possible case. Write down what Graham's law claims or describes in one sentence, then invent the smallest concrete situation in which that sentence is true. In science, the smallest case is usually a single object, a single equation or a single measurement. Check that every symbol or term in your sentence has a meaning in that case.

Example 2 — changing one variable

Take the situation from Example 1 and change exactly one quantity: double it, halve it, or set it to zero. Predict what should happen to Graham's law before you calculate. Comparing your prediction with the result is the fastest way to find out whether you understand the idea or only the words.

Example 3 — an exam-style question

Typical questions about Graham's law ask you to (a) state it precisely, (b) apply it to given data, and (c) explain a limitation. Practise writing all three answers in under five minutes; the third part is what separates a full-mark answer from an average one.

Applications of Graham's law

In research
Graham's law appears in science research whenever the underlying quantities have to be modelled precisely. Papers usually cite it as a starting assumption and then explore where it breaks down.
In technology and industry
Engineering practice reuses Graham's law in design rules, simulations and safety margins. Knowing the idea lets you read a specification sheet and understand why the numbers look the way they do.
In the classroom
Graham's law is common in secondary-school and first-year university syllabi. It links to neighbouring topics Gas laws, so understanding it makes those chapters shorter.
In everyday life
Look for Graham's law outside the textbook — in sport, cooking, traffic, electronics or the sky above you. An example you found yourself is remembered far longer than one you were given.
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How to study Graham's law in 20 minutes

  1. Read the reference excerpt below once, without taking notes.
  2. Close the page and write down what Graham's law means in your own words.
  3. Compare your version with the excerpt and mark what you missed.
  4. Work through the three examples above with pen and paper.
  5. Explain Graham's law out loud to somebody else — or to Teacher Smith in the lgStudy chat.

Frequently asked questions

What is Graham's law in simple terms?

Graham's law of effusion (also called Graham's law of diffusion) was formulated by Scottish physical chemist Thomas Graham in 1848. Graham found experimentally that the rate of effusion of a gas is inversely proportional to the square root of the molar mass of its particles.

Why does Graham's law matter?

Because it connects several science ideas at once: it gives you a definition you can apply, a quantity you can calculate, and a way to check whether a result is plausible.

How should I study Graham's law?

Read the excerpt, restate it from memory, then work through the examples and applications listed on this page. The five-step study plan above takes about twenty minutes.

What does this page cover?

It gives you a compact reference excerpt plus original lgStudy explanations, examples, applications and study material on Graham's law.

Tags

  • Gas laws

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