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Grothendieck–Riemann–Roch theorem

Grothendieck–Riemann–Roch theorem is a mathematics topic covered in the lgStudy science library. This page brings together a partial reference excerpt, illustrations, worked examples, real-world applications and a short study plan, so you can understand Grothendieck–Riemann–Roch theorem rather than just read about it. In short: In mathematics, specifically in algebraic geometry, the Grothendieck–Riemann–Roch theorem is a far-reaching result on coherent cohomology. It is a generalisation of the Hirzebruch–Riemann–Roch theorem, about complex manifolds, which is itself a generalisation of the classical Riemann–Roch theorem for line bundles on compact Riemann surfaces.

Grothendieck–Riemann–Roch theorem — main illustration
Grothendieck–Riemann–Roch theorem — illustration

Key takeaways

  • Grothendieck–Riemann–Roch theorem belongs to mathematics; place it in that map before memorising details.
  • Learn the definition first, then one example that makes the definition concrete.
  • Connect Grothendieck–Riemann–Roch theorem to a quantity you can measure, compute or draw — that is where exam questions come from.
  • Reproduce the core statement of Grothendieck–Riemann–Roch theorem from memory before moving on to harder problems.

Reference excerpt

In mathematics, specifically in algebraic geometry, the Grothendieck–Riemann–Roch theorem is a far-reaching result on coherent cohomology. It is a generalisation of the Hirzebruch–Riemann–Roch theorem, about complex manifolds, which is itself a generalisation of the classical Riemann–Roch theorem for line bundles on compact Riemann surfaces. Riemann–Roch type theorems relate Euler characteristics of the cohomology of a vector bundle with their topological degrees, or more generally their characteristic classes in (co)homology or algebraic analogues thereof. The classical Riemann–Roch theorem does this for curves and line bundles, whereas the Hirzebruch–Riemann–Roch theorem generalises this to vector bundles over manifolds. The Grothendieck–Riemann–Roch theorem sets both theorems in a relative situation of a morphism between two manifolds (or more general schemes) and changes the theorem from a statement about a single bundle, to one applying to chain complexes of sheaves. The theorem has been very influential, not least for the development of the Atiyah–Singer index theorem. Conversely, complex analytic analogues of the Grothendieck–Riemann–Roch theorem can be proved using the index theorem for families. Alexander Grothendieck gave a first proof in a 1957 manuscript, later published. Armand Borel and Jean-Pierre Serre wrote up and published Grothendieck's proof in 1958. Later, Grothendieck and his collaborators simplified and generalized the proof.

Formulation Let X be a smooth quasi-projective scheme over a field. Under these assumptions, the Grothendieck group K 0 ( X ) {\displaystyle K_{0}(X)} of bounded complexes of coherent sheaves is canonically isomorphic to the Grothendieck group of bounded complexes of finite-rank vector bundles. Using this isomorphism, consider the Chern character (a rational combination of Chern classes) as a functorial transformation:

c h : K 0 ( X ) → A ( X , Q ) , {\displaystyle \mathrm {ch} \colon K_{0}(X)\to A(X,\mathbb {Q} ),}

where A d ( X , Q ) {\displaystyle A_{d}(X,\mathbb {Q} )} is the Chow group of cycles on X of dimension d modulo rational equivalence, tensored with the rational numbers. In case X is defined over the complex numbers, the latter group maps to the topological cohomology group:

H 2 dim ⁡ ( X ) − 2 d ( X , Q ) . {\displaystyle H^{2\dim(X)-2d}(X,\mathbb {Q} ).}

Now consider a proper morphism f : X → Y {\displaystyle f\colon X\to Y} between smooth quasi-projective schemes and a bounded complex of sheaves F ∙ {\displaystyle {{\mathcal {F}}^{\bullet }}} on X . {\displaystyle X.}

The Grothendieck–Riemann–Roch theorem relates the pushforward map

f ! = ∑ ( − 1 ) i R i f ∗ : K 0 ( X ) → K 0 ( Y ) {\displaystyle f_{!}=\sum (-1)^{i}R^{i}f_{*}\colon K_{0}(X)\to K_{0}(Y)}

(alternating sum of higher direct images) and the pushforward

f ∗ : A ( X ) → A ( Y ) , {\displaystyle f_{*}\colon A(X)\to A(Y),}

by the formula

c h ( f ! F ∙ ) t d ( Y ) = f ∗ ( c h ( F ∙ ) t d ( X ) ) . {\displaystyle \mathrm {ch} (f_{!}{\mathcal {F}}^{\bullet })\mathrm {td} (Y)=f_{*}(\mathrm {ch} ({\mathcal {F}}^{\bullet })\mathrm {td} (X)).}

Here t d ( X ) {\displaystyle \mathrm {td} (X)} is the Todd genus of (the tangent bundle of) X. Thus the theorem gives a precise measure for the lack of commutativity of taking the push forwards in the above senses and the Chern character and shows that the needed correction factors depend on X and Y only. In fact, since the Todd genus is functorial and multiplicative in exact sequences, we can rewrite the Grothendieck–Riemann–Roch formula as

… excerpt ends here. Continue reading the full article.

Illustrations

Grothendieck–Riemann–Roch theorem illustration

Worked examples

Example 1 — a first encounter with Grothendieck–Riemann–Roch theorem

Start with the simplest possible case. Write down what Grothendieck–Riemann–Roch theorem claims or describes in one sentence, then invent the smallest concrete situation in which that sentence is true. In mathematics, the smallest case is usually a single object, a single equation or a single measurement. Check that every symbol or term in your sentence has a meaning in that case.

Example 2 — changing one variable

Take the situation from Example 1 and change exactly one quantity: double it, halve it, or set it to zero. Predict what should happen to Grothendieck–Riemann–Roch theorem before you calculate. Comparing your prediction with the result is the fastest way to find out whether you understand the idea or only the words.

Example 3 — an exam-style question

Typical questions about Grothendieck–Riemann–Roch theorem ask you to (a) state it precisely, (b) apply it to given data, and (c) explain a limitation. Practise writing all three answers in under five minutes; the third part is what separates a full-mark answer from an average one.

Applications of Grothendieck–Riemann–Roch theorem

In research
Grothendieck–Riemann–Roch theorem appears in mathematics research whenever the underlying quantities have to be modelled precisely. Papers usually cite it as a starting assumption and then explore where it breaks down.
In technology and industry
Engineering practice reuses Grothendieck–Riemann–Roch theorem in design rules, simulations and safety margins. Knowing the idea lets you read a specification sheet and understand why the numbers look the way they do.
In the classroom
Grothendieck–Riemann–Roch theorem is common in secondary-school and first-year university syllabi. It links to neighbouring topics Bernhard Riemann, Theorems in algebraic geometry, Topological methods of algebraic geometry, so understanding it makes those chapters shorter.
In everyday life
Look for Grothendieck–Riemann–Roch theorem outside the textbook — in sport, cooking, traffic, electronics or the sky above you. An example you found yourself is remembered far longer than one you were given.
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How to study Grothendieck–Riemann–Roch theorem in 20 minutes

  1. Read the reference excerpt below once, without taking notes.
  2. Close the page and write down what Grothendieck–Riemann–Roch theorem means in your own words.
  3. Compare your version with the excerpt and mark what you missed.
  4. Work through the three examples above with pen and paper.
  5. Explain Grothendieck–Riemann–Roch theorem out loud to somebody else — or to Teacher Smith in the lgStudy chat.

Frequently asked questions

What is Grothendieck–Riemann–Roch theorem in simple terms?

In mathematics, specifically in algebraic geometry, the Grothendieck–Riemann–Roch theorem is a far-reaching result on coherent cohomology. It is a generalisation of the Hirzebruch–Riemann–Roch theorem, about complex manifolds, which is itself a generalisation of the classical Riemann–Roch theorem f…

Why does Grothendieck–Riemann–Roch theorem matter?

Because it connects several mathematics ideas at once: it gives you a definition you can apply, a quantity you can calculate, and a way to check whether a result is plausible.

How should I study Grothendieck–Riemann–Roch theorem?

Read the excerpt, restate it from memory, then work through the examples and applications listed on this page. The five-step study plan above takes about twenty minutes.

What does this page cover?

It gives you a compact reference excerpt plus original lgStudy explanations, examples, applications and study material on Grothendieck–Riemann–Roch theorem.

Tags

  • Bernhard Riemann
  • Theorems in algebraic geometry
  • Topological methods of algebraic geometry

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