In statistical mechanics, the hard hexagon model is a 2-dimensional lattice model of a gas, where particles are allowed to be on the vertices of a triangular lattice but no two particles may be adjacent. The model was solved by Rodney Baxter (1980), who found that it was related to the Rogers–Ramanujan identities.
The partition function of the hard hexagon model The hard hexagon model occurs within the framework of the grand canonical ensemble, where the total number of particles (the "hexagons") is allowed to vary naturally, and is fixed by a chemical potential. In the hard hexagon model, all valid states have zero energy, and so the only important thermodynamic control variable is the ratio of chemical potential to temperature μ/(kT). The exponential of this ratio, z = exp(μ/(kT)) is called the activity and larger values correspond roughly to denser configurations. For a triangular lattice with N sites, the grand partition function is
Z ( z ) = ∑ n z n g ( n , N ) = 1 + N z + 1 2 N ( N − 7 ) z 2 + ⋯ {\displaystyle \displaystyle {\mathcal {Z}}(z)=\sum _{n}z^{n}g(n,N)=1+Nz+{\tfrac {1}{2}}N(N-7)z^{2}+\cdots }
where g(n, N) is the number of ways of placing n particles on distinct lattice sites such that no 2 are adjacent. The function κ is defined by
κ ( z ) = lim N → ∞ Z ( z ) 1 / N = 1 + z − 3 z 2 + ⋯ {\displaystyle \kappa (z)=\lim _{N\rightarrow \infty }{\mathcal {Z}}(z)^{1/N}=1+z-3z^{2}+\cdots }
so that log(κ) is the free energy per unit site. Solving the hard hexagon model means (roughly) finding an exact expression for κ as a function of z. The mean density ρ is given for small z by
ρ = z d log ( κ ) d z = z − 7 z 2 + 58 z 3 − 519 z 4 + 4856 z 5 + ⋯ . {\displaystyle \rho =z{\frac {d\log(\kappa )}{dz}}=z-7z^{2}+58z^{3}-519z^{4}+4856z^{5}+\cdots .}
The vertices of the lattice fall into 3 classes numbered 1, 2, and 3, given by the 3 different ways to fill space with hard hexagons. There are 3 local densities ρ1, ρ2, ρ3, corresponding to the 3 classes of sites. When the activity is large the system approximates one of these 3 packings, so the local densities differ, but when the activity is below a critical point the three local densities are the same. The critical point separating the low-activity homogeneous phase from the high-activity ordered phase is z c = ( 11 + 5 5 ) / 2 = ϕ 5 = 11.09017.... {\displaystyle z_{c}=(11+5{\sqrt {5}})/2=\phi ^{5}=11.09017....} with golden ratio φ. Above the critical point the local densities differ and in the phase where most hexagons are on sites of type 1 can be expanded as
ρ 1 = 1 − z − 1 − 5 z − 2 − 34 z − 3 − 267 z − 4 − 2037 z − 5 − ⋯ {\displaystyle \rho _{1}=1-z^{-1}-5z^{-2}-34z^{-3}-267z^{-4}-2037z^{-5}-\cdots }
ρ 2 = ρ 3 = z − 2 + 9 z − 3 + 80 z − 4 + 965 z − 5 − ⋯ . {\displaystyle \rho _{2}=\rho _{3}=z^{-2}+9z^{-3}+80z^{-4}+965z^{-5}-\cdots .}
Solution The solution is given for small values of z < zc by
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