Haruki's Theorem says that given three intersecting circles that only intersect each other at two points that the lines connecting the inner intersecting points to the outer satisfy:
s 1 ⋅ s 3 ⋅ s 5 = s 2 ⋅ s 4 ⋅ s 6 {\displaystyle s_{1}\cdot s_{3}\cdot s_{5}=s_{2}\cdot s_{4}\cdot s_{6}}
where s 1 , s 2 , s 3 , s 4 , s 5 , s 6 {\displaystyle s_{1},s_{2},s_{3},s_{4},s_{5},s_{6}} are the measure of segments connecting the inner and outer intersection points. The theorem is named after the Japanese mathematician Hiroshi Haruki.
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