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Hasse–Davenport relation

Hasse–Davenport relation is a science topic covered in the lgStudy science library. This page brings together a partial reference excerpt, illustrations, worked examples, real-world applications and a short study plan, so you can understand Hasse–Davenport relation rather than just read about it. In short: The Hasse–Davenport relations, introduced by Davenport and Hasse (1935), are two related identities for Gauss sums, one called the Hasse–Davenport lifting relation, and the other called the Hasse–Davenport product relation. The Hasse–Davenport lifting relation is an equality in number theory relating Gauss sums over different fields.

Key takeaways

  • Hasse–Davenport relation belongs to science; place it in that map before memorising details.
  • Learn the definition first, then one example that makes the definition concrete.
  • Connect Hasse–Davenport relation to a quantity you can measure, compute or draw — that is where exam questions come from.
  • Reproduce the core statement of Hasse–Davenport relation from memory before moving on to harder problems.

Reference excerpt

The Hasse–Davenport relations, introduced by Davenport and Hasse (1935), are two related identities for Gauss sums, one called the Hasse–Davenport lifting relation, and the other called the Hasse–Davenport product relation. The Hasse–Davenport lifting relation is an equality in number theory relating Gauss sums over different fields. Weil (1949) used it to calculate the zeta function of a Fermat hypersurface over a finite field, which motivated the Weil conjectures. Gauss sums are analogues of the gamma function over finite fields, and the Hasse–Davenport product relation is the analogue of Gauss's multiplication formula

Γ ( z ) Γ ( z + 1 k ) Γ ( z + 2 k ) ⋯ Γ ( z + k − 1 k ) = ( 2 π ) k − 1 2 k 1 / 2 − k z Γ ( k z ) . {\displaystyle \Gamma (z)\;\Gamma \left(z+{\frac {1}{k}}\right)\;\Gamma \left(z+{\frac {2}{k}}\right)\cdots \Gamma \left(z+{\frac {k-1}{k}}\right)=(2\pi )^{\frac {k-1}{2}}\;k^{1/2-kz}\;\Gamma (kz).\,\!}

In fact the Hasse–Davenport product relation follows from the analogous multiplication formula for p-adic gamma functions together with the Gross–Koblitz formula of Gross & Koblitz (1979).

Hasse–Davenport lifting relation Let F be a finite field with q elements, and Fs be the field such that [Fs:F] = s, that is, s is the dimension of the vector space Fs over F. Let α {\displaystyle \alpha } be an element of F s {\displaystyle F_{s}} . Let χ {\displaystyle \chi } be a multiplicative character from F to the complex numbers. Let N F s / F ( α ) {\displaystyle N_{F_{s}/F}(\alpha )} be the norm from F s {\displaystyle F_{s}} to F {\displaystyle F} defined by

N F s / F ( α ) := α ⋅ α q ⋯ α q s − 1 . {\displaystyle N_{F_{s}/F}(\alpha ):=\alpha \cdot \alpha ^{q}\cdots \alpha ^{q^{s-1}}.\,}

Let

χ ′ {\displaystyle \chi '} be the multiplicative character on F s {\displaystyle F_{s}} which is the composition of χ {\displaystyle \chi } with the norm from Fs to F, that is

χ ′ ( α ) := χ ( N F s / F ( α ) ) {\displaystyle \chi '(\alpha ):=\chi (N_{F_{s}/F}(\alpha ))}

Let ψ be some nontrivial additive character of F, and let

ψ ′ {\displaystyle \psi '} be the additive character on F s {\displaystyle F_{s}} which is the composition of ψ {\displaystyle \psi } with the trace from Fs to F, that is

ψ ′ ( α ) := ψ ( T r F s / F ( α ) ) {\displaystyle \psi '(\alpha ):=\psi (Tr_{F_{s}/F}(\alpha ))}

Let

τ ( χ , ψ ) = ∑ x ∈ F χ ( x ) ψ ( x ) {\displaystyle \tau (\chi ,\psi )=\sum _{x\in F}\chi (x)\psi (x)}

be the Gauss sum over F, and let

τ ( χ ′ , ψ ′ ) {\displaystyle \tau (\chi ',\psi ')} be the Gauss sum over F s {\displaystyle F_{s}} . Then the Hasse–Davenport lifting relation states that

… excerpt ends here. Continue reading the full article.

Worked examples

Example 1 — a first encounter with Hasse–Davenport relation

Start with the simplest possible case. Write down what Hasse–Davenport relation claims or describes in one sentence, then invent the smallest concrete situation in which that sentence is true. In science, the smallest case is usually a single object, a single equation or a single measurement. Check that every symbol or term in your sentence has a meaning in that case.

Example 2 — changing one variable

Take the situation from Example 1 and change exactly one quantity: double it, halve it, or set it to zero. Predict what should happen to Hasse–Davenport relation before you calculate. Comparing your prediction with the result is the fastest way to find out whether you understand the idea or only the words.

Example 3 — an exam-style question

Typical questions about Hasse–Davenport relation ask you to (a) state it precisely, (b) apply it to given data, and (c) explain a limitation. Practise writing all three answers in under five minutes; the third part is what separates a full-mark answer from an average one.

Applications of Hasse–Davenport relation

In research
Hasse–Davenport relation appears in science research whenever the underlying quantities have to be modelled precisely. Papers usually cite it as a starting assumption and then explore where it breaks down.
In technology and industry
Engineering practice reuses Hasse–Davenport relation in design rules, simulations and safety margins. Knowing the idea lets you read a specification sheet and understand why the numbers look the way they do.
In the classroom
Hasse–Davenport relation is common in secondary-school and first-year university syllabi. It links to neighbouring topics Cyclotomic fields, so understanding it makes those chapters shorter.
In everyday life
Look for Hasse–Davenport relation outside the textbook — in sport, cooking, traffic, electronics or the sky above you. An example you found yourself is remembered far longer than one you were given.
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How to study Hasse–Davenport relation in 20 minutes

  1. Read the reference excerpt below once, without taking notes.
  2. Close the page and write down what Hasse–Davenport relation means in your own words.
  3. Compare your version with the excerpt and mark what you missed.
  4. Work through the three examples above with pen and paper.
  5. Explain Hasse–Davenport relation out loud to somebody else — or to Teacher Smith in the lgStudy chat.

Frequently asked questions

What is Hasse–Davenport relation in simple terms?

The Hasse–Davenport relations, introduced by Davenport and Hasse (1935), are two related identities for Gauss sums, one called the Hasse–Davenport lifting relation, and the other called the Hasse–Davenport product relation. The Hasse–Davenport lifting relation is an equality in number theory relati…

Why does Hasse–Davenport relation matter?

Because it connects several science ideas at once: it gives you a definition you can apply, a quantity you can calculate, and a way to check whether a result is plausible.

How should I study Hasse–Davenport relation?

Read the excerpt, restate it from memory, then work through the examples and applications listed on this page. The five-step study plan above takes about twenty minutes.

What does this page cover?

It gives you a compact reference excerpt plus original lgStudy explanations, examples, applications and study material on Hasse–Davenport relation.

Tags

  • Cyclotomic fields

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