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Hawkins–Simon condition

Hawkins–Simon condition is a mathematics topic covered in the lgStudy science library. This page brings together a partial reference excerpt, illustrations, worked examples, real-world applications and a short study plan, so you can understand Hawkins–Simon condition rather than just read about it. In short: The Hawkins–Simon condition refers to a result in mathematical economics, attributed to David Hawkins and Herbert A. Simon, that guarantees the existence of a non-negative output vector that solves the equilibrium relation in the input–output model where demand equals supply.

Key takeaways

  • Hawkins–Simon condition belongs to mathematics; place it in that map before memorising details.
  • Learn the definition first, then one example that makes the definition concrete.
  • Connect Hawkins–Simon condition to a quantity you can measure, compute or draw — that is where exam questions come from.
  • Reproduce the core statement of Hawkins–Simon condition from memory before moving on to harder problems.

Reference excerpt

The Hawkins–Simon condition refers to a result in mathematical economics, attributed to David Hawkins and Herbert A. Simon, that guarantees the existence of a non-negative output vector that solves the equilibrium relation in the input–output model where demand equals supply. More precisely, it states a condition for [ I − A ] {\displaystyle [\mathbf {I} -\mathbf {A} ]} under which the input–output system

[ I − A ] ⋅ x = d {\displaystyle [\mathbf {I} -\mathbf {A} ]\cdot \mathbf {x} =\mathbf {d} }

has a solution x ^ ≥ 0 {\displaystyle \mathbf {\hat {x}} \geq 0} for any d ≥ 0 {\displaystyle \mathbf {d} \geq 0} . Here I {\displaystyle \mathbf {I} } is the identity matrix and A {\displaystyle \mathbf {A} } is called the input–output matrix or Leontief matrix after Wassily Leontief, who empirically estimated it in the 1940s. Together, they describe a system in which

∑ j = 1 n a i j x j + d i = x i i = 1 , 2 , … , n {\displaystyle \sum _{j=1}^{n}a_{ij}x_{j}+d_{i}=x_{i}\quad i=1,2,\ldots ,n}

where a i j {\displaystyle a_{ij}} is the amount of the ith good used to produce one unit of the jth good, x j {\displaystyle x_{j}} is the amount of the jth good produced, and d i {\displaystyle d_{i}} is the amount of final demand for good i. Rearranged and written in vector notation, this gives the first equation. Define [ I − A ] = B {\displaystyle [\mathbf {I} -\mathbf {A} ]=\mathbf {B} } , where B = [ b i j ] {\displaystyle \mathbf {B} =\left[b_{ij}\right]} is an n × n {\displaystyle n\times n} matrix with b i j ≤ 0 , i ≠ j {\displaystyle b_{ij}\leq 0,i\neq j} . Then the Hawkins–Simon theorem states that the following two conditions are equivalent

(i) There exists an x ≥ 0 {\displaystyle \mathbf {x} \geq 0} such that B ⋅ x > 0 {\displaystyle \mathbf {B} \cdot \mathbf {x} >0} . (ii) All the successive leading principal minors of B {\displaystyle \mathbf {B} } are positive, that is

… excerpt ends here. Continue reading the full article.

Worked examples

Example 1 — a first encounter with Hawkins–Simon condition

Start with the simplest possible case. Write down what Hawkins–Simon condition claims or describes in one sentence, then invent the smallest concrete situation in which that sentence is true. In mathematics, the smallest case is usually a single object, a single equation or a single measurement. Check that every symbol or term in your sentence has a meaning in that case.

Example 2 — changing one variable

Take the situation from Example 1 and change exactly one quantity: double it, halve it, or set it to zero. Predict what should happen to Hawkins–Simon condition before you calculate. Comparing your prediction with the result is the fastest way to find out whether you understand the idea or only the words.

Example 3 — an exam-style question

Typical questions about Hawkins–Simon condition ask you to (a) state it precisely, (b) apply it to given data, and (c) explain a limitation. Practise writing all three answers in under five minutes; the third part is what separates a full-mark answer from an average one.

Applications of Hawkins–Simon condition

In research
Hawkins–Simon condition appears in mathematics research whenever the underlying quantities have to be modelled precisely. Papers usually cite it as a starting assumption and then explore where it breaks down.
In technology and industry
Engineering practice reuses Hawkins–Simon condition in design rules, simulations and safety margins. Knowing the idea lets you read a specification sheet and understand why the numbers look the way they do.
In the classroom
Hawkins–Simon condition is common in secondary-school and first-year university syllabi. It links to neighbouring topics Theorems in linear algebra, so understanding it makes those chapters shorter.
In everyday life
Look for Hawkins–Simon condition outside the textbook — in sport, cooking, traffic, electronics or the sky above you. An example you found yourself is remembered far longer than one you were given.
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How to study Hawkins–Simon condition in 20 minutes

  1. Read the reference excerpt below once, without taking notes.
  2. Close the page and write down what Hawkins–Simon condition means in your own words.
  3. Compare your version with the excerpt and mark what you missed.
  4. Work through the three examples above with pen and paper.
  5. Explain Hawkins–Simon condition out loud to somebody else — or to Teacher Smith in the lgStudy chat.

Frequently asked questions

What is Hawkins–Simon condition in simple terms?

The Hawkins–Simon condition refers to a result in mathematical economics, attributed to David Hawkins and Herbert A. Simon, that guarantees the existence of a non-negative output vector that solves the equilibrium relation in the input–output model where demand equals supply.

Why does Hawkins–Simon condition matter?

Because it connects several mathematics ideas at once: it gives you a definition you can apply, a quantity you can calculate, and a way to check whether a result is plausible.

How should I study Hawkins–Simon condition?

Read the excerpt, restate it from memory, then work through the examples and applications listed on this page. The five-step study plan above takes about twenty minutes.

What does this page cover?

It gives you a compact reference excerpt plus original lgStudy explanations, examples, applications and study material on Hawkins–Simon condition.

Tags

  • Theorems in linear algebra

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