ArticleslgStudy

mathematics

Hellmann–Feynman theorem

Hellmann–Feynman theorem is a mathematics topic covered in the lgStudy science library. This page brings together a partial reference excerpt, illustrations, worked examples, real-world applications and a short study plan, so you can understand Hellmann–Feynman theorem rather than just read about it. In short: In quantum mechanics, the Hellmann–Feynman theorem relates the derivative of the total energy with respect to a parameter to the expectation value of the derivative of the Hamiltonian with respect to that same parameter. According to the theorem, once the spatial distribution of the electrons has been determined by solving the Schrödinger equation, all the forces in the system can be calculated using classical elect…

Key takeaways

  • Hellmann–Feynman theorem belongs to mathematics; place it in that map before memorising details.
  • Learn the definition first, then one example that makes the definition concrete.
  • Connect Hellmann–Feynman theorem to a quantity you can measure, compute or draw — that is where exam questions come from.
  • Reproduce the core statement of Hellmann–Feynman theorem from memory before moving on to harder problems.

Reference excerpt

In quantum mechanics, the Hellmann–Feynman theorem relates the derivative of the total energy with respect to a parameter to the expectation value of the derivative of the Hamiltonian with respect to that same parameter. According to the theorem, once the spatial distribution of the electrons has been determined by solving the Schrödinger equation, all the forces in the system can be calculated using classical electrostatics. The theorem has been proven independently by many authors, including Paul Güttinger (1932), Wolfgang Pauli (1933), Hans Hellmann (1937) and Richard Feynman (1939). The theorem states

d E λ d λ = ⟨ ψ λ | d H ^ λ d λ | ψ λ ⟩ , {\displaystyle {\frac {\mathrm {d} E_{\lambda }}{\mathrm {d} {\lambda }}}={\bigg \langle }\psi _{\lambda }{\bigg |}{\frac {\mathrm {d} {\hat {H}}_{\lambda }}{\mathrm {d} \lambda }}{\bigg |}\psi _{\lambda }{\bigg \rangle },}

where

H ^ λ {\displaystyle {\hat {H}}_{\lambda }} is a Hermitian operator depending upon a continuous parameter λ , {\displaystyle \lambda ,}

| ψ λ ⟩ {\displaystyle |\psi _{\lambda }\rangle } , is an eigenstate (eigenfunction) of the Hamiltonian, depending implicitly upon λ , {\displaystyle \lambda ,}

E λ {\displaystyle E_{\lambda }\,} is the energy (eigenvalue) of the state | ψ λ ⟩ {\displaystyle |\psi _{\lambda }\rangle } , i.e. H ^ λ | ψ λ ⟩ = E λ | ψ λ ⟩ . {\displaystyle {\hat {H}}_{\lambda }|\psi _{\lambda }\rangle =E_{\lambda }|\psi _{\lambda }\rangle .}

Note that for systems with degenerate states, a refined version of the Hellmann–Feynman theorem is needed.

Proof This proof of the Hellmann–Feynman theorem requires that the wave function be an eigenfunction of the Hamiltonian under consideration; however, it is also possible to prove more generally that the theorem holds for non-eigenfunction wave functions which are stationary (partial derivative is zero) for all relevant variables (such as orbital rotations). The Hartree–Fock wavefunction is an important example of an approximate eigenfunction that still satisfies the Hellmann–Feynman theorem. Notable example of where the Hellmann–Feynman is not applicable is for example finite-order Møller–Plesset perturbation theory, which is not variational. The proof also employs an identity of normalized wavefunctions – that derivatives of the overlap of a wave function with itself must be zero. Using Dirac's bra–ket notation these two conditions are written as

H ^ λ | ψ λ ⟩ = E λ | ψ λ ⟩ , {\displaystyle {\hat {H}}_{\lambda }|\psi _{\lambda }\rangle =E_{\lambda }|\psi _{\lambda }\rangle ,}

⟨ ψ λ | ψ λ ⟩ = 1 ⇒ d d λ ⟨ ψ λ | ψ λ ⟩ = 0. {\displaystyle \langle \psi _{\lambda }|\psi _{\lambda }\rangle =1\Rightarrow {\frac {\mathrm {d} }{\mathrm {d} \lambda }}\langle \psi _{\lambda }|\psi _{\lambda }\rangle =0.}

The proof then follows through an application of the derivative product rule to the expectation value of the Hamiltonian viewed as a function of λ {\displaystyle \lambda } :

… excerpt ends here. Continue reading the full article.

Worked examples

Example 1 — a first encounter with Hellmann–Feynman theorem

Start with the simplest possible case. Write down what Hellmann–Feynman theorem claims or describes in one sentence, then invent the smallest concrete situation in which that sentence is true. In mathematics, the smallest case is usually a single object, a single equation or a single measurement. Check that every symbol or term in your sentence has a meaning in that case.

Example 2 — changing one variable

Take the situation from Example 1 and change exactly one quantity: double it, halve it, or set it to zero. Predict what should happen to Hellmann–Feynman theorem before you calculate. Comparing your prediction with the result is the fastest way to find out whether you understand the idea or only the words.

Example 3 — an exam-style question

Typical questions about Hellmann–Feynman theorem ask you to (a) state it precisely, (b) apply it to given data, and (c) explain a limitation. Practise writing all three answers in under five minutes; the third part is what separates a full-mark answer from an average one.

Applications of Hellmann–Feynman theorem

In research
Hellmann–Feynman theorem appears in mathematics research whenever the underlying quantities have to be modelled precisely. Papers usually cite it as a starting assumption and then explore where it breaks down.
In technology and industry
Engineering practice reuses Hellmann–Feynman theorem in design rules, simulations and safety margins. Knowing the idea lets you read a specification sheet and understand why the numbers look the way they do.
In the classroom
Hellmann–Feynman theorem is common in secondary-school and first-year university syllabi. It links to neighbouring topics Intermolecular forces, Richard Feynman, Theorems in quantum mechanics, so understanding it makes those chapters shorter.
In everyday life
Look for Hellmann–Feynman theorem outside the textbook — in sport, cooking, traffic, electronics or the sky above you. An example you found yourself is remembered far longer than one you were given.
Ask Teacher Smith questions about this articleOpens your AI tutor with a question about “Hellmann–Feynman theorem” →

Affiliate

Preply — study more efficiently by working with a personal tutor. 50% off.

How to study Hellmann–Feynman theorem in 20 minutes

  1. Read the reference excerpt below once, without taking notes.
  2. Close the page and write down what Hellmann–Feynman theorem means in your own words.
  3. Compare your version with the excerpt and mark what you missed.
  4. Work through the three examples above with pen and paper.
  5. Explain Hellmann–Feynman theorem out loud to somebody else — or to Teacher Smith in the lgStudy chat.

Frequently asked questions

What is Hellmann–Feynman theorem in simple terms?

In quantum mechanics, the Hellmann–Feynman theorem relates the derivative of the total energy with respect to a parameter to the expectation value of the derivative of the Hamiltonian with respect to that same parameter. According to the theorem, once the spatial distribution of the electrons has b…

Why does Hellmann–Feynman theorem matter?

Because it connects several mathematics ideas at once: it gives you a definition you can apply, a quantity you can calculate, and a way to check whether a result is plausible.

How should I study Hellmann–Feynman theorem?

Read the excerpt, restate it from memory, then work through the examples and applications listed on this page. The five-step study plan above takes about twenty minutes.

What does this page cover?

It gives you a compact reference excerpt plus original lgStudy explanations, examples, applications and study material on Hellmann–Feynman theorem.

Tags

  • Intermolecular forces
  • Richard Feynman
  • Theorems in quantum mechanics

Keep exploring