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Hirzebruch–Riemann–Roch theorem

Hirzebruch–Riemann–Roch theorem is a mathematics topic covered in the lgStudy science library. This page brings together a partial reference excerpt, illustrations, worked examples, real-world applications and a short study plan, so you can understand Hirzebruch–Riemann–Roch theorem rather than just read about it. In short: In mathematics, the Hirzebruch–Riemann–Roch theorem, named after Friedrich Hirzebruch, Bernhard Riemann, and Gustav Roch, is Hirzebruch's 1954 result generalizing the classical Riemann–Roch theorem on Riemann surfaces to all complex algebraic varieties of higher dimensions. The result paved the way for the Grothendieck–Hirzebruch–Riemann–Roch theorem proved about three years later.

Key takeaways

  • Hirzebruch–Riemann–Roch theorem belongs to mathematics; place it in that map before memorising details.
  • Learn the definition first, then one example that makes the definition concrete.
  • Connect Hirzebruch–Riemann–Roch theorem to a quantity you can measure, compute or draw — that is where exam questions come from.
  • Reproduce the core statement of Hirzebruch–Riemann–Roch theorem from memory before moving on to harder problems.

Reference excerpt

In mathematics, the Hirzebruch–Riemann–Roch theorem, named after Friedrich Hirzebruch, Bernhard Riemann, and Gustav Roch, is Hirzebruch's 1954 result generalizing the classical Riemann–Roch theorem on Riemann surfaces to all complex algebraic varieties of higher dimensions. The result paved the way for the Grothendieck–Hirzebruch–Riemann–Roch theorem proved about three years later.

Statement of Hirzebruch–Riemann–Roch theorem The Hirzebruch–Riemann–Roch theorem applies to any holomorphic vector bundle E on a compact complex manifold X, to calculate the holomorphic Euler characteristic of E in sheaf cohomology, namely the alternating sum

χ ( X , E ) = ∑ i = 0 n ( − 1 ) i dim C ⁡ H i ( X , E ) {\displaystyle \chi (X,E)=\sum _{i=0}^{n}(-1)^{i}\dim _{\mathbb {C} }H^{i}(X,E)}

of the dimensions as complex vector spaces, where n is the complex dimension of X. Hirzebruch's theorem states that χ(X, E) is computable in terms of the Chern classes ck(E) of E, and the Todd classes td j ⁡ ( X ) {\displaystyle \operatorname {td} _{j}(X)} of the holomorphic tangent bundle of X. These all lie in the cohomology ring of X; by use of the fundamental class (or, in other words, integration over X) we can obtain numbers from classes in H 2 n ( X ) . {\displaystyle H^{2n}(X).} The Hirzebruch formula asserts that

χ ( X , E ) = ∑ j = 0 n ch n − j ⁡ ( E ) td j ⁡ ( X ) , {\displaystyle \chi (X,E)=\sum _{j=0}^{n}\operatorname {ch} _{n-j}(E)\operatorname {td} _{j}(X),}

using the Chern character ch(E) in cohomology. In other words, the products are formed in the cohomology ring of all the 'matching' degrees that add up to 2n. Formulated differently, it gives the equality

χ ( X , E ) = ∫ X ch ⁡ ( E ) td ⁡ ( X ) {\displaystyle \chi (X,E)=\int _{X}\operatorname {ch} (E)\operatorname {td} (X)}

where td ⁡ ( X ) {\displaystyle \operatorname {td} (X)} is the Todd class of the tangent bundle of X. Significant special cases are when E is a complex line bundle, and when X is an algebraic surface (Noether's formula). Weil's Riemann–Roch theorem for vector bundles on curves, and the Riemann–Roch theorem for algebraic surfaces (see below), are included in its scope. The formula also expresses in a precise way the vague notion that the Todd classes are in some sense reciprocals of the Chern Character.

Riemann Roch theorem for curves For curves, the Hirzebruch–Riemann–Roch theorem is essentially the classical Riemann–Roch theorem. To see this, recall that for each divisor D on a curve there is an invertible sheaf O(D) (which corresponds to a line bundle) such that the linear system of D is more or less the space of sections of O(D). For curves the Todd class is 1 + c 1 ( T ( X ) ) / 2 , {\displaystyle 1+c_{1}(T(X))/2,} and the Chern character of a sheaf O(D) is just 1+c1(O(D)), so the Hirzebruch–Riemann–Roch theorem states that

h 0 ( O ( D ) ) − h 1 ( O ( D ) ) = c 1 ( O ( D ) ) + c 1 ( T ( X ) ) / 2 {\displaystyle h^{0}({\mathcal {O}}(D))-h^{1}({\mathcal {O}}(D))=c_{1}({\mathcal {O}}(D))+c_{1}(T(X))/2\ \ \ } (integrated over X). But h0(O(D)) is just l(D), the dimension of the linear system of D, and by Serre duality h1(O(D)) = h0(O(K − D)) = l(K − D) where K is the canonical divisor. Moreover, c1(O(D)) integrated over X is the degree of D, and c1(T(X)) integrated over X is the Euler class 2 − 2g of the curve X, where g is the genus. So we get the classical Riemann Roch theorem

ℓ ( D ) − ℓ ( K − D ) = deg ( D ) + 1 − g . {\displaystyle \ell (D)-\ell (K-D)={\text{deg}}(D)+1-g.}

For vector bundles V, the Chern character is rank(V) + c1(V), so we get Weil's Riemann Roch theorem for vector bundles over curves:

… excerpt ends here. Continue reading the full article.

Worked examples

Example 1 — a first encounter with Hirzebruch–Riemann–Roch theorem

Start with the simplest possible case. Write down what Hirzebruch–Riemann–Roch theorem claims or describes in one sentence, then invent the smallest concrete situation in which that sentence is true. In mathematics, the smallest case is usually a single object, a single equation or a single measurement. Check that every symbol or term in your sentence has a meaning in that case.

Example 2 — changing one variable

Take the situation from Example 1 and change exactly one quantity: double it, halve it, or set it to zero. Predict what should happen to Hirzebruch–Riemann–Roch theorem before you calculate. Comparing your prediction with the result is the fastest way to find out whether you understand the idea or only the words.

Example 3 — an exam-style question

Typical questions about Hirzebruch–Riemann–Roch theorem ask you to (a) state it precisely, (b) apply it to given data, and (c) explain a limitation. Practise writing all three answers in under five minutes; the third part is what separates a full-mark answer from an average one.

Applications of Hirzebruch–Riemann–Roch theorem

In research
Hirzebruch–Riemann–Roch theorem appears in mathematics research whenever the underlying quantities have to be modelled precisely. Papers usually cite it as a starting assumption and then explore where it breaks down.
In technology and industry
Engineering practice reuses Hirzebruch–Riemann–Roch theorem in design rules, simulations and safety margins. Knowing the idea lets you read a specification sheet and understand why the numbers look the way they do.
In the classroom
Hirzebruch–Riemann–Roch theorem is common in secondary-school and first-year university syllabi. It links to neighbouring topics Bernhard Riemann, Theorems in algebraic geometry, Theorems in complex geometry, so understanding it makes those chapters shorter.
In everyday life
Look for Hirzebruch–Riemann–Roch theorem outside the textbook — in sport, cooking, traffic, electronics or the sky above you. An example you found yourself is remembered far longer than one you were given.
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How to study Hirzebruch–Riemann–Roch theorem in 20 minutes

  1. Read the reference excerpt below once, without taking notes.
  2. Close the page and write down what Hirzebruch–Riemann–Roch theorem means in your own words.
  3. Compare your version with the excerpt and mark what you missed.
  4. Work through the three examples above with pen and paper.
  5. Explain Hirzebruch–Riemann–Roch theorem out loud to somebody else — or to Teacher Smith in the lgStudy chat.

Frequently asked questions

What is Hirzebruch–Riemann–Roch theorem in simple terms?

In mathematics, the Hirzebruch–Riemann–Roch theorem, named after Friedrich Hirzebruch, Bernhard Riemann, and Gustav Roch, is Hirzebruch's 1954 result generalizing the classical Riemann–Roch theorem on Riemann surfaces to all complex algebraic varieties of higher dimensions. The result paved the way…

Why does Hirzebruch–Riemann–Roch theorem matter?

Because it connects several mathematics ideas at once: it gives you a definition you can apply, a quantity you can calculate, and a way to check whether a result is plausible.

How should I study Hirzebruch–Riemann–Roch theorem?

Read the excerpt, restate it from memory, then work through the examples and applications listed on this page. The five-step study plan above takes about twenty minutes.

What does this page cover?

It gives you a compact reference excerpt plus original lgStudy explanations, examples, applications and study material on Hirzebruch–Riemann–Roch theorem.

Tags

  • Bernhard Riemann
  • Theorems in algebraic geometry
  • Theorems in complex geometry
  • Topological methods of algebraic geometry

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