In mathematics, an integrating factor is a function that is chosen to facilitate the solving of a given equation involving differentials. It is commonly used to solve non-exact ordinary differential equations, but is also used within multivariable calculus when multiplying through by an integrating factor allows an inexact differential to be made into an exact differential (which can then be integrated to give a scalar field). This is especially useful in thermodynamics where temperature becomes the integrating factor that makes entropy an exact differential.
Use An integrating factor is any expression that a differential equation is multiplied by to facilitate integration. For example, the nonlinear second order equation
d 2 y d t 2 = A y 2 / 3 {\displaystyle {\frac {d^{2}y}{dt^{2}}}=Ay^{2/3}}
admits d y d t {\textstyle {\frac {dy}{dt}}} as an integrating factor:
d 2 y d t 2 d y d t = A y 2 / 3 d y d t . {\displaystyle {\frac {d^{2}y}{dt^{2}}}{\frac {dy}{dt}}=Ay^{2/3}{\frac {dy}{dt}}.}
To integrate, note that both sides of the equation may be expressed as derivatives by going backwards with the chain rule:
d d t ( 1 2 ( d y d t ) 2 ) = d d t ( A 3 5 y 5 / 3 ) . {\displaystyle {\frac {d}{dt}}\left({\frac {1}{2}}\left({\frac {dy}{dt}}\right)^{2}\right)={\frac {d}{dt}}\left(A{\frac {3}{5}}y^{5/3}\right).}
Therefore,
( d y d t ) 2 = 6 A 5 y 5 / 3 + C 0 . {\displaystyle \left({\frac {dy}{dt}}\right)^{2}={\frac {6A}{5}}y^{5/3}+C_{0}.}
where C 0 {\displaystyle C_{0}} is a constant. This form may be more useful, depending on application. Performing a separation of variables will give
∫ y ( 0 ) y ( t ) d y 6 A 5 y 5 / 3 + C 0 = t {\displaystyle \int _{y(0)}^{y(t)}{\frac {dy}{\sqrt {{\frac {6A}{5}}y^{5/3}+C_{0}}}}=t}
This is an implicit solution which involves a nonelementary integral. This same method is used to solve the period of a simple pendulum.
Solving first order linear ordinary differential equations Integrating factors are useful for solving ordinary differential equations that can be expressed in the form
y ′ + P ( x ) y = Q ( x ) {\displaystyle y'+P(x)y=Q(x)}
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