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Jordan's lemma

Jordan's lemma is a mathematics topic covered in the lgStudy science library. This page brings together a partial reference excerpt, illustrations, worked examples, real-world applications and a short study plan, so you can understand Jordan's lemma rather than just read about it. In short: In complex analysis, Jordan's lemma is a result frequently used in conjunction with the residue theorem to evaluate contour integrals and improper integrals. The lemma is named after the French mathematician Camille Jordan.

Jordan's lemma — main illustration
Jordan's lemma — illustration

Key takeaways

  • Jordan's lemma belongs to mathematics; place it in that map before memorising details.
  • Learn the definition first, then one example that makes the definition concrete.
  • Connect Jordan's lemma to a quantity you can measure, compute or draw — that is where exam questions come from.
  • Reproduce the core statement of Jordan's lemma from memory before moving on to harder problems.

Reference excerpt

In complex analysis, Jordan's lemma is a result frequently used in conjunction with the residue theorem to evaluate contour integrals and improper integrals. The lemma is named after the French mathematician Camille Jordan.

Statement Consider a complex-valued, continuous function f, defined on a semicircular contour

C R = { R e i θ ∣ θ ∈ [ 0 , π ] } {\displaystyle C_{R}=\{Re^{i\theta }\mid \theta \in [0,\pi ]\}}

of positive radius R lying in the upper half-plane, centered at the origin. If the function f is of the form

f ( z ) = e i a z g ( z ) , z ∈ C , {\displaystyle f(z)=e^{iaz}g(z),\quad z\in C,}

with a positive parameter a, then Jordan's lemma states the following upper bound for the contour integral:

| ∫ C R f ( z ) d z | ≤ π a M R where M R := max θ ∈ [ 0 , π ] | g ( R e i θ ) | . {\displaystyle \left|\int _{C_{R}}f(z)\,dz\right|\leq {\frac {\pi }{a}}M_{R}\quad {\text{where}}\quad M_{R}:=\max _{\theta \in [0,\pi ]}\left|g\left(Re^{i\theta }\right)\right|.}

with equality when g vanishes everywhere, in which case both sides are identically zero. An analogous statement for a semicircular contour in the lower half-plane holds when a < 0.

Remarks If f is continuous on the semicircular contour CR for all large R and

then by Jordan's lemma lim R → ∞ ∫ C R f ( z ) d z = 0. {\displaystyle \lim _{R\to \infty }\int _{C_{R}}f(z)\,dz=0.}

For the case a = 0, see the estimation lemma. Compared to the estimation lemma, the upper bound in Jordan's lemma does not explicitly depend on the length of the contour CR.

Application of Jordan's lemma

Jordan's lemma yields a simple way to calculate the integral along the real axis of functions f(z) = ei a z g(z) holomorphic on the upper half-plane and continuous on the closed upper half-plane, except possibly at a finite number of non-real points z1, z2, …, zn. Consider the closed contour C, which is the concatenation of the paths C1 and C2 shown in the picture. By definition,

∮ C f ( z ) d z = ∫ C 1 f ( z ) d z + ∫ C 2 f ( z ) d z . {\displaystyle \oint _{C}f(z)\,dz=\int _{C_{1}}f(z)\,dz+\int _{C_{2}}f(z)\,dz\,.}

Since on C2 the variable z is real, the second integral is real:

∫ C 2 f ( z ) d z = ∫ − R R f ( x ) d x . {\displaystyle \int _{C_{2}}f(z)\,dz=\int _{-R}^{R}f(x)\,dx\,.}

The left-hand side may be computed using the residue theorem to get, for all R larger than the maximum of |z1|, |z2|, …, |zn|,

∮ C f ( z ) d z = 2 π i ∑ k = 1 n Res ⁡ ( f , z k ) , {\displaystyle \oint _{C}f(z)\,dz=2\pi i\sum _{k=1}^{n}\operatorname {Res} (f,z_{k})\,,}

where Res(f, zk) denotes the residue of f at the singularity zk. Hence, if f satisfies condition (*), then taking the limit as R tends to infinity, the contour integral over C1 vanishes by Jordan's lemma and we get the value of the improper integral

… excerpt ends here. Continue reading the full article.

Worked examples

Example 1 — a first encounter with Jordan's lemma

Start with the simplest possible case. Write down what Jordan's lemma claims or describes in one sentence, then invent the smallest concrete situation in which that sentence is true. In mathematics, the smallest case is usually a single object, a single equation or a single measurement. Check that every symbol or term in your sentence has a meaning in that case.

Example 2 — changing one variable

Take the situation from Example 1 and change exactly one quantity: double it, halve it, or set it to zero. Predict what should happen to Jordan's lemma before you calculate. Comparing your prediction with the result is the fastest way to find out whether you understand the idea or only the words.

Example 3 — an exam-style question

Typical questions about Jordan's lemma ask you to (a) state it precisely, (b) apply it to given data, and (c) explain a limitation. Practise writing all three answers in under five minutes; the third part is what separates a full-mark answer from an average one.

Applications of Jordan's lemma

In research
Jordan's lemma appears in mathematics research whenever the underlying quantities have to be modelled precisely. Papers usually cite it as a starting assumption and then explore where it breaks down.
In technology and industry
Engineering practice reuses Jordan's lemma in design rules, simulations and safety margins. Knowing the idea lets you read a specification sheet and understand why the numbers look the way they do.
In the classroom
Jordan's lemma is common in secondary-school and first-year university syllabi. It links to neighbouring topics Lemmas in mathematical analysis, Theorems in complex analysis, so understanding it makes those chapters shorter.
In everyday life
Look for Jordan's lemma outside the textbook — in sport, cooking, traffic, electronics or the sky above you. An example you found yourself is remembered far longer than one you were given.

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How to study Jordan's lemma in 20 minutes

  1. Read the reference excerpt below once, without taking notes.
  2. Close the page and write down what Jordan's lemma means in your own words.
  3. Compare your version with the excerpt and mark what you missed.
  4. Work through the three examples above with pen and paper.
  5. Explain Jordan's lemma out loud to somebody else — or to Teacher Smith in the lgStudy chat.

Frequently asked questions

What is Jordan's lemma in simple terms?

In complex analysis, Jordan's lemma is a result frequently used in conjunction with the residue theorem to evaluate contour integrals and improper integrals. The lemma is named after the French mathematician Camille Jordan.

Why does Jordan's lemma matter?

Because it connects several mathematics ideas at once: it gives you a definition you can apply, a quantity you can calculate, and a way to check whether a result is plausible.

How should I study Jordan's lemma?

Read the excerpt, restate it from memory, then work through the examples and applications listed on this page. The five-step study plan above takes about twenty minutes.

What does this page cover?

It gives you a compact reference excerpt plus original lgStudy explanations, examples, applications and study material on Jordan's lemma.

Tags

  • Lemmas in mathematical analysis
  • Theorems in complex analysis

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