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Kármán–Howarth equation

Kármán–Howarth equation is a mathematics topic covered in the lgStudy science library. This page brings together a partial reference excerpt, illustrations, worked examples, real-world applications and a short study plan, so you can understand Kármán–Howarth equation rather than just read about it. In short: In isotropic turbulence the Kármán–Howarth equation (after Theodore von Kármán and Leslie Howarth 1938), which is derived from the Navier–Stokes equations, is used to describe the evolution of non-dimensional longitudinal autocorrelation. Mathematical description Consider a two-point velocity correlation tensor for homogeneous turbulence R i j ( r , t ) = u i ( x , t ) u j ( x + r , t ) ¯ . {\displaystyle R_{ij}(\ma…

Key takeaways

  • Kármán–Howarth equation belongs to mathematics; place it in that map before memorising details.
  • Learn the definition first, then one example that makes the definition concrete.
  • Connect Kármán–Howarth equation to a quantity you can measure, compute or draw — that is where exam questions come from.
  • Reproduce the core statement of Kármán–Howarth equation from memory before moving on to harder problems.

Reference excerpt

In isotropic turbulence the Kármán–Howarth equation (after Theodore von Kármán and Leslie Howarth 1938), which is derived from the Navier–Stokes equations, is used to describe the evolution of non-dimensional longitudinal autocorrelation.

Mathematical description Consider a two-point velocity correlation tensor for homogeneous turbulence

R i j ( r , t ) = u i ( x , t ) u j ( x + r , t ) ¯ . {\displaystyle R_{ij}(\mathbf {r} ,t)={\overline {u_{i}(\mathbf {x} ,t)u_{j}(\mathbf {x} +\mathbf {r} ,t)}}.}

For isotropic turbulence, this correlation tensor can be expressed in terms of two scalar functions, using the invariant theory of full rotation group, first derived by Howard P. Robertson in 1940,

R i j ( r , t ) = u ′ 2 { [ f ( r , t ) − g ( r , t ) ] r i r j r 2 + g ( r , t ) δ i j } , f ( r , t ) = R 11 u ′ 2 , g ( r , t ) = R 22 u ′ 2 {\displaystyle R_{ij}(\mathbf {r} ,t)=u'^{2}\left\{[f(r,t)-g(r,t)]{\frac {r_{i}r_{j}}{r^{2}}}+g(r,t)\delta _{ij}\right\},\quad f(r,t)={\frac {R_{11}}{u'^{2}}},\quad g(r,t)={\frac {R_{22}}{u'^{2}}}}

where u ′ {\displaystyle u'} is the root mean square turbulent velocity and u 1 , u 2 , u 3 {\displaystyle u_{1},\ u_{2},\ u_{3}} are turbulent velocity in all three directions. Here, f ( r ) {\displaystyle f(r)} is the longitudinal correlation and g ( r ) {\displaystyle g(r)} is the lateral correlation of velocity at two different points. From continuity equation, we have

∂ R i j ∂ r j = 0 ⇒ g ( r , t ) = f ( r , t ) + r 2 ∂ ∂ r f ( r , t ) {\displaystyle {\frac {\partial R_{ij}}{\partial r_{j}}}=0\quad \Rightarrow \quad g(r,t)=f(r,t)+{\frac {r}{2}}{\frac {\partial }{\partial r}}f(r,t)}

Thus f ( r , t ) {\displaystyle f(r,t)} uniquely determines the two-point correlation function. Theodore von Kármán and Leslie Howarth derived the evolution equation for f ( r , t ) {\displaystyle f(r,t)} from Navier–Stokes equation as

… excerpt ends here. Continue reading the full article.

Worked examples

Example 1 — a first encounter with Kármán–Howarth equation

Start with the simplest possible case. Write down what Kármán–Howarth equation claims or describes in one sentence, then invent the smallest concrete situation in which that sentence is true. In mathematics, the smallest case is usually a single object, a single equation or a single measurement. Check that every symbol or term in your sentence has a meaning in that case.

Example 2 — changing one variable

Take the situation from Example 1 and change exactly one quantity: double it, halve it, or set it to zero. Predict what should happen to Kármán–Howarth equation before you calculate. Comparing your prediction with the result is the fastest way to find out whether you understand the idea or only the words.

Example 3 — an exam-style question

Typical questions about Kármán–Howarth equation ask you to (a) state it precisely, (b) apply it to given data, and (c) explain a limitation. Practise writing all three answers in under five minutes; the third part is what separates a full-mark answer from an average one.

Applications of Kármán–Howarth equation

In research
Kármán–Howarth equation appears in mathematics research whenever the underlying quantities have to be modelled precisely. Papers usually cite it as a starting assumption and then explore where it breaks down.
In technology and industry
Engineering practice reuses Kármán–Howarth equation in design rules, simulations and safety margins. Knowing the idea lets you read a specification sheet and understand why the numbers look the way they do.
In the classroom
Kármán–Howarth equation is common in secondary-school and first-year university syllabi. It links to neighbouring topics Equations of fluid dynamics, Turbulence, so understanding it makes those chapters shorter.
In everyday life
Look for Kármán–Howarth equation outside the textbook — in sport, cooking, traffic, electronics or the sky above you. An example you found yourself is remembered far longer than one you were given.
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How to study Kármán–Howarth equation in 20 minutes

  1. Read the reference excerpt below once, without taking notes.
  2. Close the page and write down what Kármán–Howarth equation means in your own words.
  3. Compare your version with the excerpt and mark what you missed.
  4. Work through the three examples above with pen and paper.
  5. Explain Kármán–Howarth equation out loud to somebody else — or to Teacher Smith in the lgStudy chat.

Frequently asked questions

What is Kármán–Howarth equation in simple terms?

In isotropic turbulence the Kármán–Howarth equation (after Theodore von Kármán and Leslie Howarth 1938), which is derived from the Navier–Stokes equations, is used to describe the evolution of non-dimensional longitudinal autocorrelation. Mathematical description Consider a two-point velocity corre…

Why does Kármán–Howarth equation matter?

Because it connects several mathematics ideas at once: it gives you a definition you can apply, a quantity you can calculate, and a way to check whether a result is plausible.

How should I study Kármán–Howarth equation?

Read the excerpt, restate it from memory, then work through the examples and applications listed on this page. The five-step study plan above takes about twenty minutes.

What does this page cover?

It gives you a compact reference excerpt plus original lgStudy explanations, examples, applications and study material on Kármán–Howarth equation.

Tags

  • Equations of fluid dynamics
  • Turbulence

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