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Kirchhoff's diffraction formula

Kirchhoff's diffraction formula is a physics topic covered in the lgStudy science library. This page brings together a partial reference excerpt, illustrations, worked examples, real-world applications and a short study plan, so you can understand Kirchhoff's diffraction formula rather than just read about it. In short: Kirchhoff's diffraction formula (also called Fresnel–Kirchhoff diffraction formula) approximates light intensity and phase in optical diffraction: light fields in the boundary regions of shadows. The approximation can be used to model light propagation in a wide range of configurations, either analytically or using numerical modelling.

Kirchhoff's diffraction formula — main illustration
Kirchhoff's diffraction formula — illustration

Key takeaways

  • Kirchhoff's diffraction formula belongs to physics; place it in that map before memorising details.
  • Learn the definition first, then one example that makes the definition concrete.
  • Connect Kirchhoff's diffraction formula to a quantity you can measure, compute or draw — that is where exam questions come from.
  • Reproduce the core statement of Kirchhoff's diffraction formula from memory before moving on to harder problems.

Reference excerpt

Kirchhoff's diffraction formula (also called Fresnel–Kirchhoff diffraction formula) approximates light intensity and phase in optical diffraction: light fields in the boundary regions of shadows. The approximation can be used to model light propagation in a wide range of configurations, either analytically or using numerical modelling. It gives an expression for the wave disturbance when a monochromatic spherical wave is the incoming wave of a situation under consideration. This formula is derived by applying the Kirchhoff integral theorem, which uses the Green's second identity to derive the solution to the homogeneous scalar wave equation, to a spherical wave with some approximations. The Huygens–Fresnel principle can be derived by the Fresnel–Kirchhoff diffraction formula.

Derivation of Kirchhoff's diffraction formula Kirchhoff's integral theorem, sometimes referred to as the Fresnel–Kirchhoff integral theorem, uses Green's second identity to derive the solution of the homogeneous scalar wave equation at an arbitrary spatial position P in terms of the solution of the wave equation and its first order derivative at all points on an arbitrary closed surface S {\displaystyle S} as the boundary of some volume including P. The solution provided by the integral theorem for a monochromatic source is

U ( P ) = 1 4 π ∫ S [ U ∂ ∂ n ( e i k s s ) − e i k s s ∂ U ∂ n ] d S , {\displaystyle U({\textbf {P}})={\frac {1}{4\pi }}\int _{S}\left[U{\frac {\partial }{\partial {\textbf {n}}}}\left({\frac {e^{iks}}{s}}\right)-{\frac {e^{iks}}{s}}{\frac {\partial U}{\partial {\textbf {n}}}}\right]dS,}

where U {\displaystyle U} is the spatial part of the solution of the homogeneous scalar wave equation (i.e., V ( r , t ) = U ( r ) e − i ω t {\displaystyle V(\mathbf {r} ,t)=U(\mathbf {r} )e^{-i\omega t}} as the homogeneous scalar wave equation solution), k is the wavenumber, and s is the distance from P to an (infinitesimally small) integral surface element, and ∂ f ∂ n {\displaystyle {\frac {\partial f}{\partial {\textbf {n}}}}} denotes a derivative of a function f {\displaystyle f} along the normal unit vector n {\displaystyle {\textbf {n}}} of an integral surface element d S {\displaystyle dS} (i.e., a normal derivative), i.e., ∂ f ∂ n = ∇ f ⋅ n {\displaystyle {\frac {\partial f}{\partial {\textbf {n}}}}=\nabla f\cdot {\textbf {n}}} . Note that the surface normal unit vector n {\displaystyle {\textbf {n}}} is toward the inside of the enclosed volume in this integral; if the more usual outer-pointing normal is used, the integral will have the opposite sign. And also note that, in the integral theorem shown here, n {\displaystyle {\textbf {n}}} and P are vector quantities while other terms are scalar quantities. (In below sections, these vector quantities are often written n and P as italic for writing simplicity.) For the below sections, following assumptions are made.

The distance between a point source of waves and an integral area, the distance between the integral area and an observation point P, and the dimension of opening (aperture) S are much greater than the wave wavelength λ {\displaystyle \lambda } . Waves on the aperture is same to waves that would be present if there was no obstacle (e.g., a screen having the aperture) for the waves.

… excerpt ends here. Continue reading the full article.

Illustrations

Kirchhoff's diffraction formula: Geometric arrangement used to express Kirchhoff's formula in a form similar to Huygens–Fresnel
Geometric arrangement used to express Kirchhoff's formula in a form similar to Huygens–Fresnel

Worked examples

Example 1 — a first encounter with Kirchhoff's diffraction formula

Start with the simplest possible case. Write down what Kirchhoff's diffraction formula claims or describes in one sentence, then invent the smallest concrete situation in which that sentence is true. In physics, the smallest case is usually a single object, a single equation or a single measurement. Check that every symbol or term in your sentence has a meaning in that case.

Example 2 — changing one variable

Take the situation from Example 1 and change exactly one quantity: double it, halve it, or set it to zero. Predict what should happen to Kirchhoff's diffraction formula before you calculate. Comparing your prediction with the result is the fastest way to find out whether you understand the idea or only the words.

Example 3 — an exam-style question

Typical questions about Kirchhoff's diffraction formula ask you to (a) state it precisely, (b) apply it to given data, and (c) explain a limitation. Practise writing all three answers in under five minutes; the third part is what separates a full-mark answer from an average one.

Applications of Kirchhoff's diffraction formula

In research
Kirchhoff's diffraction formula appears in physics research whenever the underlying quantities have to be modelled precisely. Papers usually cite it as a starting assumption and then explore where it breaks down.
In technology and industry
Engineering practice reuses Kirchhoff's diffraction formula in design rules, simulations and safety margins. Knowing the idea lets you read a specification sheet and understand why the numbers look the way they do.
In the classroom
Kirchhoff's diffraction formula is common in secondary-school and first-year university syllabi. It links to neighbouring topics Diffraction, Gustav Kirchhoff, Physical optics, so understanding it makes those chapters shorter.
In everyday life
Look for Kirchhoff's diffraction formula outside the textbook — in sport, cooking, traffic, electronics or the sky above you. An example you found yourself is remembered far longer than one you were given.

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How to study Kirchhoff's diffraction formula in 20 minutes

  1. Read the reference excerpt below once, without taking notes.
  2. Close the page and write down what Kirchhoff's diffraction formula means in your own words.
  3. Compare your version with the excerpt and mark what you missed.
  4. Work through the three examples above with pen and paper.
  5. Explain Kirchhoff's diffraction formula out loud to somebody else — or to Teacher Smith in the lgStudy chat.

Frequently asked questions

What is Kirchhoff's diffraction formula in simple terms?

Kirchhoff's diffraction formula (also called Fresnel–Kirchhoff diffraction formula) approximates light intensity and phase in optical diffraction: light fields in the boundary regions of shadows. The approximation can be used to model light propagation in a wide range of configurations, either anal…

Why does Kirchhoff's diffraction formula matter?

Because it connects several physics ideas at once: it gives you a definition you can apply, a quantity you can calculate, and a way to check whether a result is plausible.

How should I study Kirchhoff's diffraction formula?

Read the excerpt, restate it from memory, then work through the examples and applications listed on this page. The five-step study plan above takes about twenty minutes.

What does this page cover?

It gives you a compact reference excerpt plus original lgStudy explanations, examples, applications and study material on Kirchhoff's diffraction formula.

Tags

  • Diffraction
  • Gustav Kirchhoff
  • Physical optics
  • Waves

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