In algebraic geometry, Lang's theorem, introduced by Serge Lang, states: if G is a connected smooth algebraic group over a finite field F q {\displaystyle \mathbf {F} _{q}} , then, writing σ : G → G , x ↦ x q {\displaystyle \sigma :G\to G,\,x\mapsto x^{q}} for the Frobenius, the morphism of varieties
G → G , x ↦ x − 1 σ ( x ) {\displaystyle G\to G,\,x\mapsto x^{-1}\sigma (x)} is surjective. Note that the kernel of this map (i.e., G = G ( F q ¯ ) → G ( F q ¯ ) {\displaystyle G=G({\overline {\mathbf {F} _{q}}})\to G({\overline {\mathbf {F} _{q}}})} ) is precisely G ( F q ) {\displaystyle G(\mathbf {F} _{q})} . The theorem implies that H 1 ( F q , G ) = H e ´ t 1 ( Spec F q , G ) {\displaystyle H^{1}(\mathbf {F} _{q},G)=H_{\mathrm {{\acute {e}}t} }^{1}(\operatorname {Spec} \mathbf {F} _{q},G)} vanishes, and, consequently, any G-bundle on Spec F q {\displaystyle \operatorname {Spec} \mathbf {F} _{q}} is isomorphic to the trivial one. Also, the theorem plays a basic role in the theory of finite groups of Lie type. It is not necessary that G is affine. Thus, the theorem also applies to abelian varieties (e.g., elliptic curves.) In fact, this application was Lang's initial motivation. If G is affine, the Frobenius σ {\displaystyle \sigma } may be replaced by any surjective map with finitely many fixed points (see below for the precise statement.) The proof (given below) actually goes through for any σ {\displaystyle \sigma } that induces a nilpotent operator on the Lie algebra of G.
The Lang–Steinberg theorem Steinberg (1968) gave a useful improvement to the theorem. Suppose that F is an endomorphism of an algebraic group G. The Lang map is the map from G to G taking g to g−1F(g). The Lang–Steinberg theorem states that if F is surjective and has a finite number of fixed points, and G is a connected affine algebraic group over an algebraically closed field, then the Lang map is surjective.
Proof of Lang's theorem Define:
f a : G → G , f a ( x ) = x − 1 a σ ( x ) . {\displaystyle f_{a}:G\to G,\quad f_{a}(x)=x^{-1}a\sigma (x).}
Then, by identifying the tangent space at a with the tangent space at the identity element, we have:
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