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Langmuir (unit)

Langmuir (unit) is a science topic covered in the lgStudy science library. This page brings together a partial reference excerpt, illustrations, worked examples, real-world applications and a short study plan, so you can understand Langmuir (unit) rather than just read about it. In short: The langmuir (symbol: L) is a unit of exposure (or gas dose) to a surface (e.g. of a crystal) and is used in ultra-high vacuum (UHV) surface physics to study the adsorption of gases. It is a practical unit, and is not dimensionally homogeneous, and so is used only in this field.

Key takeaways

  • Langmuir (unit) belongs to science; place it in that map before memorising details.
  • Learn the definition first, then one example that makes the definition concrete.
  • Connect Langmuir (unit) to a quantity you can measure, compute or draw — that is where exam questions come from.
  • Reproduce the core statement of Langmuir (unit) from memory before moving on to harder problems.

Reference excerpt

The langmuir (symbol: L) is a unit of exposure (or gas dose) to a surface (e.g. of a crystal) and is used in ultra-high vacuum (UHV) surface physics to study the adsorption of gases. It is a practical unit, and is not dimensionally homogeneous, and so is used only in this field. It is named after American physicist Irving Langmuir.

Definition The langmuir is defined by multiplying the pressure of the gas by the time of exposure. One langmuir corresponds to an exposure of 10−6 Torr during one second. For example, exposing a surface to a gas pressure of 10−8 Torr for 100 seconds corresponds to 1 L. Similarly, keeping the pressure of oxygen gas at 2.5·10−6 Torr for 40 seconds will give a dose of 100 L.

Conversion Since both different pressures and exposure times can give the same langmuir (see definition) it can be difficult to convert Langmuir (L) to exposure pressure × time (Torr·s) and vice versa. The following equation can be used to convert between the two easily: x y [ L ] = x × 10 − n [ T o r r ] ⋅ y × 10 n − 6 [ s ] {\displaystyle xy[{\rm {L}}]=x\times 10^{-n}[{\rm {Torr}}]\cdot y\times 10^{n-6}[{\rm {s}}]} Here, x {\displaystyle x} and y {\displaystyle y} are any two numbers whose product equals the desired Langmuir value, n {\displaystyle n} is an integer allowing different magnitudes of pressure or exposure time to be used in conversion. The units are represented in the [square brackets]. Using the prior example, for a dose of 100 L a pressure of 2.5 × 10−6 Torr can be applied for 40 seconds, thus, x = 2.5 {\displaystyle x=2.5} , y = 40 {\displaystyle y=40} and n = 6 {\displaystyle n=6} . However, this dose could also be gained with 8 × 10−8 Torr for 1250 seconds, here x = 8 {\displaystyle x=8} , y = 12.5 {\displaystyle y=12.5} , n = 8 {\displaystyle n=8} . In both scenarios x y = 100 {\displaystyle xy=100} .

Derivation Exposure of a surface in surface physics is a type of fluence, that is the integral of number flux (JN) with respect to exposed time (t) to give a number of particles per unit area (Φ):

Φ = ∫ J N d t . {\displaystyle \Phi =\int {J_{N}}\,{\rm {d}}t.}

The number flux for an ideal gas, that is the number of gas molecules passing through (in a single direction) a surface of unit area in unit time, can be derived from kinetic theory:

J N = C u ¯ 4 , {\displaystyle J_{N}={\frac {C{\bar {u}}}{4}},}

where C is the number density of the gas, and u ¯ {\displaystyle {\bar {u}}} is the mean speed of the molecules (not the root-mean-square speed, although the two are related). The number density of an ideal gas depends on the thermodynamic temperature (T) and the pressure (p):

C = N V = p k T . {\displaystyle C={\frac {N}{V}}={\frac {p}{kT}}.}

The mean speed of the gas molecules can also be derived from kinetic theory:

u ¯ = 8 k T π m , {\displaystyle {\bar {u}}={\sqrt {\frac {8kT}{\pi m}}},}

where m is the mass of a gas molecule. Hence

J N = C u ¯ 4 = p 1 2 π k T m . {\displaystyle J_{N}={\frac {C{\bar {u}}}{4}}=p{\sqrt {\frac {1}{2\pi kTm}}}.}

The proportionality between number flux and pressure is only strictly valid for a given temperature and a given molecular mass of adsorbing gas. However, the dependence is only on the square roots of m and T. Gas adsorption experiments typically operate around ambient temperature with light gases. Hence, the langmuir remains useful as a practical unit.

… excerpt ends here. Continue reading the full article.

Worked examples

Example 1 — a first encounter with Langmuir (unit)

Start with the simplest possible case. Write down what Langmuir (unit) claims or describes in one sentence, then invent the smallest concrete situation in which that sentence is true. In science, the smallest case is usually a single object, a single equation or a single measurement. Check that every symbol or term in your sentence has a meaning in that case.

Example 2 — changing one variable

Take the situation from Example 1 and change exactly one quantity: double it, halve it, or set it to zero. Predict what should happen to Langmuir (unit) before you calculate. Comparing your prediction with the result is the fastest way to find out whether you understand the idea or only the words.

Example 3 — an exam-style question

Typical questions about Langmuir (unit) ask you to (a) state it precisely, (b) apply it to given data, and (c) explain a limitation. Practise writing all three answers in under five minutes; the third part is what separates a full-mark answer from an average one.

Applications of Langmuir (unit)

In research
Langmuir (unit) appears in science research whenever the underlying quantities have to be modelled precisely. Papers usually cite it as a starting assumption and then explore where it breaks down.
In technology and industry
Engineering practice reuses Langmuir (unit) in design rules, simulations and safety margins. Knowing the idea lets you read a specification sheet and understand why the numbers look the way they do.
In the classroom
Langmuir (unit) is common in secondary-school and first-year university syllabi. It links to neighbouring topics Gases, Surface science, Thin film deposition, so understanding it makes those chapters shorter.
In everyday life
Look for Langmuir (unit) outside the textbook — in sport, cooking, traffic, electronics or the sky above you. An example you found yourself is remembered far longer than one you were given.
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How to study Langmuir (unit) in 20 minutes

  1. Read the reference excerpt below once, without taking notes.
  2. Close the page and write down what Langmuir (unit) means in your own words.
  3. Compare your version with the excerpt and mark what you missed.
  4. Work through the three examples above with pen and paper.
  5. Explain Langmuir (unit) out loud to somebody else — or to Teacher Smith in the lgStudy chat.

Frequently asked questions

What is Langmuir (unit) in simple terms?

The langmuir (symbol: L) is a unit of exposure (or gas dose) to a surface (e.g. of a crystal) and is used in ultra-high vacuum (UHV) surface physics to study the adsorption of gases. It is a practical unit, and is not dimensionally homogeneous, and so is used only in this field.

Why does Langmuir (unit) matter?

Because it connects several science ideas at once: it gives you a definition you can apply, a quantity you can calculate, and a way to check whether a result is plausible.

How should I study Langmuir (unit)?

Read the excerpt, restate it from memory, then work through the examples and applications listed on this page. The five-step study plan above takes about twenty minutes.

What does this page cover?

It gives you a compact reference excerpt plus original lgStudy explanations, examples, applications and study material on Langmuir (unit).

Tags

  • Gases
  • Surface science
  • Thin film deposition
  • Units of amount of substance
  • Vacuum

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