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Levinson's theorem

Levinson's theorem is a mathematics topic covered in the lgStudy science library. This page brings together a partial reference excerpt, illustrations, worked examples, real-world applications and a short study plan, so you can understand Levinson's theorem rather than just read about it. In short: Levinson's theorem is an important theorem of scattering theory. In non-relativistic quantum mechanics, it relates the number of bound states in channels with a definite orbital momentum to the difference in phase of a scattered wave at infinite and zero momenta.

Key takeaways

  • Levinson's theorem belongs to mathematics; place it in that map before memorising details.
  • Learn the definition first, then one example that makes the definition concrete.
  • Connect Levinson's theorem to a quantity you can measure, compute or draw — that is where exam questions come from.
  • Reproduce the core statement of Levinson's theorem from memory before moving on to harder problems.

Reference excerpt

Levinson's theorem is an important theorem of scattering theory. In non-relativistic quantum mechanics, it relates the number of bound states in channels with a definite orbital momentum to the difference in phase of a scattered wave at infinite and zero momenta. It was published by Norman Levinson in 1949.

The theorem applies to a wide range of potentials that increase limitedly at zero distance and decrease sufficiently fast as the distance grows.

Statement of theorem The difference in the ℓ {\displaystyle \ell } -wave phase shift of a scattered wave at infinite momentum, φ ( + ∞ ) {\displaystyle \varphi (+\infty )} , and zero momentum, φ ( 0 ) {\displaystyle \varphi (0)} , for a spherically symmetric potential V ( r ) {\displaystyle V(r)} is related to the number of bound states n b {\displaystyle n_{b}} by:

φ ( + ∞ ) − φ ( 0 ) = − π ( 1 2 n 0 + n b ) {\displaystyle \varphi (+\infty )-\varphi (0)=-\pi \left({\frac {1}{2}}n_{0}+n_{b}\right)} , where n 0 = 0 {\displaystyle n_{0}=0} or 1 {\displaystyle 1} . The scenario n 0 = 1 {\displaystyle n_{0}=1} is uncommon and can only occur in s {\displaystyle s} -wave scattering, if a bound state with zero energy exists. The following conditions are sufficient to guarantee the theorem:

V ( r ) {\displaystyle V(r)} continuous in ( 0 , + ∞ ) {\displaystyle (0,+\infty )} except for a finite number of finite discontinuities,

V ( r ) = O ( r − 3 / 2 + ε ) as r → 0 , ε > 0 , {\displaystyle V(r)=O(r^{-3/2+\varepsilon })~{\text{ as }}~r\rightarrow 0,~~\varepsilon >0,}

V ( r ) = O ( r − 3 − ε ) as r → ∞ , ε > 0. {\displaystyle V(r)=O(r^{-3-\varepsilon })~{\text{ as }}~r\rightarrow \infty ,~~\varepsilon >0.}

Generalizations of Levinson's theorem include tensor forces, nonlocal potentials, and relativistic effects. In relativistic scattering theory, essential information about the system is contained in the Jost function, whose analytical properties are well defined and can be used to prove and generalize Levinson's theorem. The presence of Castillejo, Dalitz and Dyson (CDD) poles

and Jaffe and Low primitives

which correspond to zeros of the Jost function at the unitary cut modifies the theorem. In general case, the phase difference at infinite and zero particle momenta is determined by the number of bound states, n b {\displaystyle n_{b}} , the number of primitives, n p {\displaystyle n_{p}} , and the number of CDD poles, n CDD {\displaystyle n_{\text{CDD}}} :

φ ( + ∞ ) − φ ( 0 ) = − π ( 1 2 n 0 + n b + n p − n CDD ) {\displaystyle \varphi (+\infty )-\varphi (0)=-\pi \left({\frac {1}{2}}n_{0}+n_{b}+n_{p}-n_{\text{CDD}}\right)} . The bound states and primitives give a negative contribution to the phase asymptotics, while the CDD poles give a positive contribution. In the context of potential scattering, a decrease (increase) in the scattering phase shift due to greater particle momentum is interpreted as the action of a repulsive (attractive) potential. The following universal properties of the Jost function, ω J ( s ) {\displaystyle \omega _{J}(s)} , are essential to guarantee the generalized theorem:

… excerpt ends here. Continue reading the full article.

Worked examples

Example 1 — a first encounter with Levinson's theorem

Start with the simplest possible case. Write down what Levinson's theorem claims or describes in one sentence, then invent the smallest concrete situation in which that sentence is true. In mathematics, the smallest case is usually a single object, a single equation or a single measurement. Check that every symbol or term in your sentence has a meaning in that case.

Example 2 — changing one variable

Take the situation from Example 1 and change exactly one quantity: double it, halve it, or set it to zero. Predict what should happen to Levinson's theorem before you calculate. Comparing your prediction with the result is the fastest way to find out whether you understand the idea or only the words.

Example 3 — an exam-style question

Typical questions about Levinson's theorem ask you to (a) state it precisely, (b) apply it to given data, and (c) explain a limitation. Practise writing all three answers in under five minutes; the third part is what separates a full-mark answer from an average one.

Applications of Levinson's theorem

In research
Levinson's theorem appears in mathematics research whenever the underlying quantities have to be modelled precisely. Papers usually cite it as a starting assumption and then explore where it breaks down.
In technology and industry
Engineering practice reuses Levinson's theorem in design rules, simulations and safety margins. Knowing the idea lets you read a specification sheet and understand why the numbers look the way they do.
In the classroom
Levinson's theorem is common in secondary-school and first-year university syllabi. It links to neighbouring topics Theorems in quantum mechanics, so understanding it makes those chapters shorter.
In everyday life
Look for Levinson's theorem outside the textbook — in sport, cooking, traffic, electronics or the sky above you. An example you found yourself is remembered far longer than one you were given.
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How to study Levinson's theorem in 20 minutes

  1. Read the reference excerpt below once, without taking notes.
  2. Close the page and write down what Levinson's theorem means in your own words.
  3. Compare your version with the excerpt and mark what you missed.
  4. Work through the three examples above with pen and paper.
  5. Explain Levinson's theorem out loud to somebody else — or to Teacher Smith in the lgStudy chat.

Frequently asked questions

What is Levinson's theorem in simple terms?

Levinson's theorem is an important theorem of scattering theory. In non-relativistic quantum mechanics, it relates the number of bound states in channels with a definite orbital momentum to the difference in phase of a scattered wave at infinite and zero momenta.

Why does Levinson's theorem matter?

Because it connects several mathematics ideas at once: it gives you a definition you can apply, a quantity you can calculate, and a way to check whether a result is plausible.

How should I study Levinson's theorem?

Read the excerpt, restate it from memory, then work through the examples and applications listed on this page. The five-step study plan above takes about twenty minutes.

What does this page cover?

It gives you a compact reference excerpt plus original lgStudy explanations, examples, applications and study material on Levinson's theorem.

Tags

  • Theorems in quantum mechanics

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