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Lewis's triviality result

Lewis's triviality result is a mathematics topic covered in the lgStudy science library. This page brings together a partial reference excerpt, illustrations, worked examples, real-world applications and a short study plan, so you can understand Lewis's triviality result rather than just read about it. In short: In the mathematical theory of probability, Lewis's triviality result (named after David Lewis) is a theorem about the impossibility of systematically equating the conditional probability P ( B ∣ A ) {\displaystyle P(B\mid A)} with the probability of a so-called conditional event, A → B {\displaystyle A\rightarrow B} . Conditional probability and conditional events The statement "The probability that if A {\displayst…

Lewis's triviality result — main illustration
Lewis's triviality result — illustration

Key takeaways

  • Lewis's triviality result belongs to mathematics; place it in that map before memorising details.
  • Learn the definition first, then one example that makes the definition concrete.
  • Connect Lewis's triviality result to a quantity you can measure, compute or draw — that is where exam questions come from.
  • Reproduce the core statement of Lewis's triviality result from memory before moving on to harder problems.

Reference excerpt

In the mathematical theory of probability, Lewis's triviality result (named after David Lewis) is a theorem about the impossibility of systematically equating the conditional probability P ( B ∣ A ) {\displaystyle P(B\mid A)} with the probability of a so-called conditional event, A → B {\displaystyle A\rightarrow B} .

Conditional probability and conditional events The statement "The probability that if A {\displaystyle A} , then B {\displaystyle B} , is 20%" means (put intuitively) that event B {\displaystyle B} may be expected to occur in 20% of the outcomes where event A {\displaystyle A} occurs. The standard formal expression of this is P ( B ∣ A ) = 0.20 {\displaystyle P(B\mid A)=0.20} , where the conditional probability P ( B ∣ A ) {\displaystyle P(B\mid A)} equals, by definition, P ( A ∩ B ) / P ( A ) {\displaystyle P(A\cap B)/P(A)} . Beginning in the 1960s, several philosophical logicians—most notably Ernest Adams and Robert Stalnaker—floated the idea that one might also write P ( A → B ) = 0.20 {\displaystyle P(A\rightarrow B)=0.20} , where A → B {\displaystyle A\rightarrow B} is the conditional event "If A {\displaystyle A} , then B {\displaystyle B} ". That is, given events A {\displaystyle A} and B {\displaystyle B} , one might suppose there is an event, A → B {\displaystyle A\rightarrow B} , such that P ( A → B ) {\displaystyle P(A\rightarrow B)} could be counted on to equal P ( B ∣ A ) {\displaystyle P(B\mid A)} , so long as P ( A ) > 0 {\displaystyle P(A)>0} . Part of the appeal of this move would be the possibility of embedding conditional expressions within more complex constructions. One could write, say, P ( A ∪ ( B → C ) ) = 0.75 {\displaystyle P(A\cup (B\rightarrow C))=0.75} , to express someone's high subjective degree of confidence ("75% sure") that either A {\displaystyle A} , or else if B {\displaystyle B} , then C {\displaystyle C} . Compound constructions containing conditional expressions might also be useful in the programming of automated decision-making systems.

How might such a convention be combined with standard probability theory? The most direct extension of the standard theory would be to treat A → B {\displaystyle A\rightarrow B} as an event like any other, i.e., as a set of outcomes. Adding A → B {\displaystyle A\rightarrow B} to the familiar Venn- or Euler diagram of A {\displaystyle A} and B {\displaystyle B} would then result in something like Fig. 1, where s , t , … , z {\displaystyle s,t,\ldots ,z} are probabilities allocated to the eight respective regions, such that s + t + ⋯ + z = 1 {\displaystyle s+t+\cdots +z=1} . For P ( A → B ) {\displaystyle P(A\rightarrow B)} to equal P ( B ∣ A ) {\displaystyle P(B\mid A)} requires that t + v + w + y = ( s + t ) / ( s + t + x + y ) {\displaystyle t+v+w+y=(s+t)/(s+t+x+y)} , i.e., that the probability inside the A → B {\displaystyle A\rightarrow B} region equal the A ∩ B {\displaystyle A\cap B} region's proportional share of the probability inside the A {\displaystyle A} region. In general the equality will of course not be true, so that making it reliably true requires a new constraint on probability functions: in addition to satisfying Kolmogorov's probability axioms, they must also satisfy a new constraint, namely that P ( A → B ) = P ( B ∣ A ) {\displaystyle P(A\rightarrow B)=P(B\mid A)} for any events A {\displaystyle A} and B {\displaystyle B} such that P ( A ) > 0 {\displaystyle P(A)>0} .

… excerpt ends here. Continue reading the full article.

Illustrations

Lewis's triviality result: Fig. 2 – A diagram of disjoint 
  
    
      
        A
      
    
    {\displaystyle A}
  
 and 
  
    
      
        B
      
    
    {\displaystyle B}
  
, and 
  
    
      
        (
        A
        ∪
        B
        )
        →
        A
      
    
    {\displaystyle (A\cup B)\rightarrow A}
  
.
Fig. 2 – A diagram of disjoint A {\displaystyle A} and B {\displaystyle B} , and ( A ∪ B ) → A {\displaystyle (A\cup B)\rightarrow A} .

Worked examples

Example 1 — a first encounter with Lewis's triviality result

Start with the simplest possible case. Write down what Lewis's triviality result claims or describes in one sentence, then invent the smallest concrete situation in which that sentence is true. In mathematics, the smallest case is usually a single object, a single equation or a single measurement. Check that every symbol or term in your sentence has a meaning in that case.

Example 2 — changing one variable

Take the situation from Example 1 and change exactly one quantity: double it, halve it, or set it to zero. Predict what should happen to Lewis's triviality result before you calculate. Comparing your prediction with the result is the fastest way to find out whether you understand the idea or only the words.

Example 3 — an exam-style question

Typical questions about Lewis's triviality result ask you to (a) state it precisely, (b) apply it to given data, and (c) explain a limitation. Practise writing all three answers in under five minutes; the third part is what separates a full-mark answer from an average one.

Applications of Lewis's triviality result

In research
Lewis's triviality result appears in mathematics research whenever the underlying quantities have to be modelled precisely. Papers usually cite it as a starting assumption and then explore where it breaks down.
In technology and industry
Engineering practice reuses Lewis's triviality result in design rules, simulations and safety margins. Knowing the idea lets you read a specification sheet and understand why the numbers look the way they do.
In the classroom
Lewis's triviality result is common in secondary-school and first-year university syllabi. It links to neighbouring topics Conditional probability, Logic, so understanding it makes those chapters shorter.
In everyday life
Look for Lewis's triviality result outside the textbook — in sport, cooking, traffic, electronics or the sky above you. An example you found yourself is remembered far longer than one you were given.
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How to study Lewis's triviality result in 20 minutes

  1. Read the reference excerpt below once, without taking notes.
  2. Close the page and write down what Lewis's triviality result means in your own words.
  3. Compare your version with the excerpt and mark what you missed.
  4. Work through the three examples above with pen and paper.
  5. Explain Lewis's triviality result out loud to somebody else — or to Teacher Smith in the lgStudy chat.

Frequently asked questions

What is Lewis's triviality result in simple terms?

In the mathematical theory of probability, Lewis's triviality result (named after David Lewis) is a theorem about the impossibility of systematically equating the conditional probability P ( B ∣ A ) {\displaystyle P(B\mid A)} with the probability of a so-called conditional event, A → B {\displaysty…

Why does Lewis's triviality result matter?

Because it connects several mathematics ideas at once: it gives you a definition you can apply, a quantity you can calculate, and a way to check whether a result is plausible.

How should I study Lewis's triviality result?

Read the excerpt, restate it from memory, then work through the examples and applications listed on this page. The five-step study plan above takes about twenty minutes.

What does this page cover?

It gives you a compact reference excerpt plus original lgStudy explanations, examples, applications and study material on Lewis's triviality result.

Tags

  • Conditional probability
  • Logic

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