The mass–action ratio, often denoted by Γ {\displaystyle \Gamma } , is the ratio of the product concentrations, p, to reactant concentrations, s. The concentrations may or may not be at equilibrium.
Γ = p 1 p 2 … s 1 s 2 … {\displaystyle \Gamma ={\frac {p_{1}p_{2}\ldots }{s_{1}s_{2}\ldots }}}
This assumes that the stoichiometric amounts are all unity. If not, then each concentration must be raised to the power of its corresponding stoichiometric amount. If the product and reactant concentrations are at equilibrium then the mass–action ratio will equal the equilibrium constant. At equilibrium:
Γ = K e q {\displaystyle \Gamma =K_{eq}}
The ratio of the mass–action ratio to the equilibrium constant is often called the disequilibrium ratio, denoted by the symbol ρ {\displaystyle \rho } .
ρ = Γ K e q {\displaystyle \rho ={\frac {\Gamma }{K_{eq}}}}
and is a useful measure for indicating how far from equilibrium a given reaction is. The ratio is always greater than zero, and at equilibrium, the ratio is one: ρ = 1 {\displaystyle \rho =1} . When the reaction is out of equilibrium, ρ ≠ 1 {\displaystyle \rho \neq 1} . When ρ < 1 {\displaystyle \rho <1} , the reaction is out of equilibrium with a forward rate higher than the reverse rate, and the reaction has a negative free energy (i.e., a spontaneous, exergonic reaction), as explained below. For a uni-molecular reaction such as A ⇌ B {\displaystyle A\rightleftharpoons B} , where the net reaction rate is given by the reversible mass-action ratio:
v = k 1 A − k 2 B = v f − v r {\displaystyle v=k_{1}A-k_{2}B=v_{f}-v_{r}} At thermodynamic equilibrium the rate equals zero, that is 0 = k 1 A e q − k 2 B e q {\textstyle 0=k_{1}A_{eq}-{k_{2}B_{eq}}} . Rearranging gives:
k 1 k 2 = B e q A e q = K e q {\displaystyle {\frac {k_{1}}{k_{2}}}={\frac {B_{eq}}{A_{eq}}}=K_{eq}} but ρ = Γ K e q {\textstyle \rho ={\frac {\Gamma }{K_{eq}}}} , therefore ρ = Γ k 2 k 1 {\displaystyle \rho =\Gamma {\frac {k_{2}}{k_{1}}}} and therefore ρ = B A k 2 k 1 = v r v f {\displaystyle \rho ={\frac {B}{A}}{\frac {k_{2}}{k_{1}}}={\frac {v_{r}}{v_{f}}}} In other words, the disequilibrium ratio is the ratio of the reverse to the forward rate. When the reverse rate, v r {\textstyle v_{r}} is less than the forward rate, the ratio is less than one, ρ < 1 {\textstyle \rho <1} , indicating that the net reaction is from left to right.
Relationship to Free Energy The thermodynamic equation of the chemical equilibrium states that
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