In graph theory, the matching polytope of a given graph is a geometric object representing the possible matchings in the graph. It is a convex polytope each of whose corners corresponds to a matching. It has great theoretical importance in the theory of matching.
Preliminaries
Incidence vectors and matrices Let G = (V, E) be a graph with n = |V| nodes and m = |E| edges. For every subset U of vertices, its incidence vector 1U is a vector of size n, in which element v is 1 if node v is in U, and 0 otherwise. Similarly, for every subset F of edges, its incidence vector 1F is a vector of size m, in which element e is 1 if edge e is in F, and 0 otherwise. For every node v in V, the set of edges in E adjacent to v is denoted by E(v). Therefore, each vector 1E(v) is a 1-by-m vector in which element e is 1 if edge e is adjacent to v, and 0 otherwise. The incidence matrix of the graph, denoted by AG, is an n-by-m matrix in which each row v is the incidence vector 1E(V). In other words, each element v,e in the matrix is 1 if node v is adjacent to edge e, and 0 otherwise. Below are three examples of incidence matrices: the triangle graph (a cycle of length 3), a square graph (a cycle of length 4), and the complete graph on 4 vertices.
Linear programs For every subset F of edges, the dot product 1E(v) · 1F represents the number of edges in F that are adjacent to v. Therefore, the following statements are equivalent:
A subset F of edges represents a matching in G; For every node v in V: 1E(v) · 1F ≤ 1. AG · 1F ≤ 1V. The cardinality of a set F of edges is the dot product 1E · 1F . Therefore, a maximum cardinality matching in G is given by the following integer linear program: Maximize 1E · x Subject to: x in {0,1}m
__________ AG · x ≤ 1V.
Fractional matching polytope The fractional matching polytope of a graph G, denoted FMP(G), is the polytope defined by the relaxation of the above linear program, in which each x may be a fraction and not just an integer:Maximize 1E · x Subject to: x ≥ 0E
__________ AG · x ≤ 1V.This is a linear program. It has m "at-least-0" constraints and n "less-than-one" constraints. The set of its feasible solutions is a convex polytope. Each point in this polytope is a fractional matching. For example, in the triangle graph there are 3 edges, and the corresponding linear program has the following 6 constraints: Maximize x1+x2+x3 Subject to: x1≥0, x2≥0, x3≥0.
__________ x1+x2≤1, x2+x3≤1, x3+x1≤1.This set of inequalities represents a polytope in R3 - the 3-dimensional Euclidean space. The polytope has five corners (extreme points). These are the points that attain equality in 3 out of the 6 defining inequalities. The corners are (0,0,0), (1,0,0), (0,1,0), (0,0,1), and (1/2,1/2,1/2). The first corner (0,0,0) represents the trivial (empty) matching. The next three corners (1,0,0), (0,1,0), (0,0,1) represent the three matchings of size 1. The fifth corner (1/2,1/2,1/2) does not represent a matching - it represents a fractional matching in which each edge is "half in, half out". Note that this is the largest fractional matching in this graph - its weight is 3/2, in contrast to the three integral matchings whose size is only 1. As another example, in the 4-cycle there are 4 edges. The corresponding LP has 4+4=8 constraints. The FMP is a convex polytope in R4. The corners of this polytope are (0,0,0,0), (1,0,0,0), (0,1,0,0), (0,0,1,0), (0,0,0,1), (1,0,1,0), (0,1,0,1). Each of the last 2 corners represents matching of size 2, which is a maximum matching. Note that in this case all corners have integer coordinates.
Integral matching polytope The integral matching polytope (usually called just the matching polytope) of a graph G, denoted MP(G), is a polytope whose corners are the incidence vectors of the integral matchings in G. MP(G) is always contained in FMP(G). In the above examples:
The MP of the triangle graph is strictly contained in its FMP, since the MP does not contain the non-integral corner (1/2, 1/2, 1/2). The MP of the 4-cycle graph is identical to its FMP, since all the corners of the FMP are integral.
The matching polytopes in a bipartite graph The above example is a special case of the following general theorem:G is a bipartite graph if-and-only-if MP(G) = FMP(G) if-and-only-if all corners of FMP(G) have only integer coordinates.This theorem can be proved in several ways.
Proof using matrices When G is bipartite, its incidence matrix AG is totally unimodular - every square submatrix of it has determinant 0, +1 or −1. The proof is by induction on k - the size of the submatrix (which we denote by K). The base k = 1 follows from the definition of AG - every element in it is either 0 or 1. For k>1 there are several cases:
If K has a column consisting only of zeros, then det K = 0. If K has a column with a single 1, then det K can be expanded about this column and it equals either +1 or -1 times a determinant of a (k − 1) by (k − 1) matrix, which by the induction assumption is 0 or +1 or −1. Otherwise, each column in K has two 1s. Since the graph is bipartite, the rows can be partitioned into two subsets, such that in each column, one 1 is in the top subset and the other 1 is in the bottom subset. This means that the sum of the top subset and the sum of the bottom subset are both equal to 1E minus a vector of |E| ones. This means that the rows of K are linearly dependent, so det K = 0. As an example, in the 4-cycle (which is bipartite), the det AG = 1. In contrast, in the 3-cycle (which is not bipartite), det AG = 2. Each corner of FMP(G) satisfies a set of m linearly-independent inequalities with equality. Therefore, to calculate the corner coordinates we have to solve a system of equations defined by a square submatrix of AG. By Cramer's rule, the solution is a rational number in which the denominator is the determinant of this submatrix. This determinant must by +1 or −1; therefore the solution is an integer vector. Therefore all corner coordinates are integers. By the n "less-than-one" constraints, the corner coordinates are either 0 or 1; therefore each corner is the incidence vector of an integral matching in G. Hence FMP(G) = MP(G).
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