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Mellin inversion theorem

Mellin inversion theorem is a mathematics topic covered in the lgStudy science library. This page brings together a partial reference excerpt, illustrations, worked examples, real-world applications and a short study plan, so you can understand Mellin inversion theorem rather than just read about it. In short: In mathematics, the Mellin inversion formula (named after Hjalmar Mellin) tells us conditions under which the inverse Mellin transform, or equivalently the inverse two-sided Laplace transform, are defined and recover the transformed function. Method If φ ( s ) {\displaystyle \varphi (s)} is analytic in the strip ⁠ a < ℜ ( s ) < b {\displaystyle a<\Re (s)<b} ⁠, and if it tends to zero uniformly as ℑ ( s ) → ± ∞ {\dis…

Key takeaways

  • Mellin inversion theorem belongs to mathematics; place it in that map before memorising details.
  • Learn the definition first, then one example that makes the definition concrete.
  • Connect Mellin inversion theorem to a quantity you can measure, compute or draw — that is where exam questions come from.
  • Reproduce the core statement of Mellin inversion theorem from memory before moving on to harder problems.

Reference excerpt

In mathematics, the Mellin inversion formula (named after Hjalmar Mellin) tells us conditions under which the inverse Mellin transform, or equivalently the inverse two-sided Laplace transform, are defined and recover the transformed function.

Method If φ ( s ) {\displaystyle \varphi (s)} is analytic in the strip ⁠ a < ℜ ( s ) < b {\displaystyle a<\Re (s)<b} ⁠, and if it tends to zero uniformly as ℑ ( s ) → ± ∞ {\displaystyle \Im (s)\to \pm \infty } for any real value ⁠ c {\displaystyle c} ⁠ between ⁠ a {\displaystyle a} ⁠ and ⁠ b {\displaystyle b} ⁠, with its integral along such a line converging absolutely, then if

f ( x ) = { M − 1 φ } = 1 2 π i ∫ c − i ∞ c + i ∞ x − s φ ( s ) d s {\displaystyle f(x)=\{{\mathcal {M}}^{-1}\varphi \}={\frac {1}{2\pi i}}\int _{c-i\infty }^{c+i\infty }x^{-s}\varphi (s)\,ds}

we have that

φ ( s ) = { M f } = ∫ 0 ∞ x s − 1 f ( x ) d x . {\displaystyle \varphi (s)=\{{\mathcal {M}}f\}=\int _{0}^{\infty }x^{s-1}f(x)\,dx.}

Conversely, suppose f ( x ) {\displaystyle f(x)} is piecewise continuous on the positive real numbers, taking a value halfway between the limit values at any jump discontinuities, and suppose the integral

φ ( s ) = ∫ 0 ∞ x s − 1 f ( x ) d x {\displaystyle \varphi (s)=\int _{0}^{\infty }x^{s-1}f(x)\,dx}

is absolutely convergent when ⁠ a < ℜ ( s ) < b {\displaystyle a<\Re (s)<b} ⁠. Then f {\displaystyle f} is recoverable via the inverse Mellin transform from its Mellin transform ⁠ φ {\displaystyle \varphi } ⁠. These results can be obtained by relating the Mellin transform to the Fourier transform by a change of variables and then applying an appropriate version of the Fourier inversion theorem.

Boundedness condition The boundedness condition on φ ( s ) {\displaystyle \varphi (s)} can be strengthened if f ( x ) {\displaystyle f(x)} is continuous. If φ ( s ) {\displaystyle \varphi (s)} is analytic in the strip ⁠ a < ℜ ( s ) < b {\displaystyle a<\Re (s)<b} ⁠, and if ⁠ | φ ( s ) | < K | s | − 2 {\displaystyle \vert \varphi (s)\vert <K\vert s\vert ^{-2}} ⁠, where ⁠ K {\displaystyle K} ⁠ is a positive constant, then f ( x ) {\displaystyle f(x)} as defined by the inversion integral exists and is continuous; moreover the Mellin transform of f {\displaystyle f} is φ {\displaystyle \varphi } for at least ⁠ a < ℜ ( s ) < b {\displaystyle a<\Re (s)<b} ⁠. On the other hand, if we are willing to accept an original f {\displaystyle f} which is a generalized function, we may relax the boundedness condition on φ {\displaystyle \varphi } to simply make it of polynomial growth in any closed strip contained in the open strip ⁠ a < ℜ ( s ) < b {\displaystyle a<\Re (s)<b} ⁠. We may also define a Banach space version of this theorem. If we call by L ν , p ( R + ) {\displaystyle L_{\nu ,p}(R^{+})} the weighted Lp space of complex valued functions f {\displaystyle f} on the positive reals such that

… excerpt ends here. Continue reading the full article.

Worked examples

Example 1 — a first encounter with Mellin inversion theorem

Start with the simplest possible case. Write down what Mellin inversion theorem claims or describes in one sentence, then invent the smallest concrete situation in which that sentence is true. In mathematics, the smallest case is usually a single object, a single equation or a single measurement. Check that every symbol or term in your sentence has a meaning in that case.

Example 2 — changing one variable

Take the situation from Example 1 and change exactly one quantity: double it, halve it, or set it to zero. Predict what should happen to Mellin inversion theorem before you calculate. Comparing your prediction with the result is the fastest way to find out whether you understand the idea or only the words.

Example 3 — an exam-style question

Typical questions about Mellin inversion theorem ask you to (a) state it precisely, (b) apply it to given data, and (c) explain a limitation. Practise writing all three answers in under five minutes; the third part is what separates a full-mark answer from an average one.

Applications of Mellin inversion theorem

In research
Mellin inversion theorem appears in mathematics research whenever the underlying quantities have to be modelled precisely. Papers usually cite it as a starting assumption and then explore where it breaks down.
In technology and industry
Engineering practice reuses Mellin inversion theorem in design rules, simulations and safety margins. Knowing the idea lets you read a specification sheet and understand why the numbers look the way they do.
In the classroom
Mellin inversion theorem is common in secondary-school and first-year university syllabi. It links to neighbouring topics Integral transforms, Laplace transforms, Theorems in complex analysis, so understanding it makes those chapters shorter.
In everyday life
Look for Mellin inversion theorem outside the textbook — in sport, cooking, traffic, electronics or the sky above you. An example you found yourself is remembered far longer than one you were given.

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How to study Mellin inversion theorem in 20 minutes

  1. Read the reference excerpt below once, without taking notes.
  2. Close the page and write down what Mellin inversion theorem means in your own words.
  3. Compare your version with the excerpt and mark what you missed.
  4. Work through the three examples above with pen and paper.
  5. Explain Mellin inversion theorem out loud to somebody else — or to Teacher Smith in the lgStudy chat.

Frequently asked questions

What is Mellin inversion theorem in simple terms?

In mathematics, the Mellin inversion formula (named after Hjalmar Mellin) tells us conditions under which the inverse Mellin transform, or equivalently the inverse two-sided Laplace transform, are defined and recover the transformed function. Method If φ ( s ) {\displaystyle \varphi (s)} is analyti…

Why does Mellin inversion theorem matter?

Because it connects several mathematics ideas at once: it gives you a definition you can apply, a quantity you can calculate, and a way to check whether a result is plausible.

How should I study Mellin inversion theorem?

Read the excerpt, restate it from memory, then work through the examples and applications listed on this page. The five-step study plan above takes about twenty minutes.

What does this page cover?

It gives you a compact reference excerpt plus original lgStudy explanations, examples, applications and study material on Mellin inversion theorem.

Tags

  • Integral transforms
  • Laplace transforms
  • Theorems in complex analysis

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