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Ostwald ripening

Ostwald ripening is a chemistry topic covered in the lgStudy science library. This page brings together a partial reference excerpt, illustrations, worked examples, real-world applications and a short study plan, so you can understand Ostwald ripening rather than just read about it. In short: Ostwald ripening is a phenomenon observed in solid solutions and liquid sols that involves the change of an inhomogeneous structure over time, in that small crystals or sol particles first dissolve and then redeposit onto larger crystals or sol particles. Dissolution of small crystals or sol particles and the redeposition of the dissolved species on the surfaces of larger crystals or sol particles was first describe…

Ostwald ripening — main illustration
Ostwald ripening — illustration

Key takeaways

  • Ostwald ripening belongs to chemistry; place it in that map before memorising details.
  • Learn the definition first, then one example that makes the definition concrete.
  • Connect Ostwald ripening to a quantity you can measure, compute or draw — that is where exam questions come from.
  • Reproduce the core statement of Ostwald ripening from memory before moving on to harder problems.

Reference excerpt

Ostwald ripening is a phenomenon observed in solid solutions and liquid sols that involves the change of an inhomogeneous structure over time, in that small crystals or sol particles first dissolve and then redeposit onto larger crystals or sol particles. Dissolution of small crystals or sol particles and the redeposition of the dissolved species on the surfaces of larger crystals or sol particles was first described by Wilhelm Ostwald in 1896. For colloidal systems, Ostwald ripening is also found in water-in-oil emulsions, while flocculation is found in oil-in-water emulsions.

Mechanism This thermodynamically-driven spontaneous process occurs because larger particles are more energetically favored than smaller particles. This stems from the fact that molecules on the surface of a particle are energetically less stable than the ones in the interior. Consider a cubic crystal of atoms: all the atoms inside are bonded to 6 neighbours and are quite stable, but atoms on the surface are only bonded to 5 neighbors or fewer, which makes these surface atoms less stable. Large particles are more energetically favorable since, continuing with this example, more atoms are bonded to 6 neighbors and fewer atoms are at the unfavorable surface. As the system tries to lower its overall energy, molecules on the surface of a small particle (energetically unfavorable, with only 3 or 4 or 5 bonded neighbors) will tend to detach from the particle and diffuse into the solution. Kelvin's equation describes the relationship between the radius of curvature and the chemical potential between the surface and the inner volume:

Δ μ = 2 σ ν a t r {\displaystyle \Delta \mu ={\frac {2\sigma \nu _{\mathrm {at} }}{r}}}

where μ {\displaystyle \mu } corresponds to the chemical potential, σ {\displaystyle \sigma } to the surface tension, ν a t {\displaystyle \nu _{\mathrm {at} }} to the atomic volume and r {\displaystyle r} to the radius of the particle. The chemical potential of an ideal solution can also be expressed as a function of the solute's concentration if liquid and solid phases are in equilibrium.

μ = k B T log ⁡ ( C e q ) {\displaystyle \mu =k_{\mathrm {B} }T\log(C_{\mathrm {eq} })}

where k B {\displaystyle k_{\mathrm {B} }} corresponds to the Boltzmann constant, T {\displaystyle T} to the temperature and C e q {\displaystyle C_{\mathrm {eq} }} to the solute concentration in a solution in which the solid and the liquid phase are in equilibrium. Combining both expressions the following equation is obtained:

k B T log ⁡ ( C e q C ∞ ) = 2 σ ν a t r → C e q ( r ) = C e q ( ∞ ) e 2 σ ν a t r k B T {\displaystyle k_{\mathrm {B} }T\log \left({\frac {C_{\mathrm {eq} }}{C_{\infty }}}\right)={\frac {2\sigma \nu _{\mathrm {at} }}{r}}\rightarrow C_{\mathrm {eq} }(r)=C_{\mathrm {eq} }(\infty )\mathrm {e} ^{\frac {2\sigma \nu _{\mathrm {at} }}{rk_{\mathrm {B} }T}}}

Thus, the equilibrium concentration, C e q {\displaystyle C_{eq}} , is lower around bigger particles than it is around smaller particles.

C e q ( r ) > C e q ( R ) {\displaystyle C_{\mathrm {eq} }(r)>C_{\mathrm {eq} }(R)}

… excerpt ends here. Continue reading the full article.

Illustrations

Ostwald ripening: Ostwald ripening in palladium nanoparticles dissolved in formaldehyde at 6 (a), 24 (b), 48 (c) and 72 hours (d). The small palladium particles are being consumed as the larger ones grow bigger.[1]
Ostwald ripening in palladium nanoparticles dissolved in formaldehyde at 6 (a), 24 (b), 48 (c) and 72 hours (d). The small palladium particles are being consumed as the larger ones grow bigger.[1]
Ostwald ripening: Cubic crystal structure (sodium chloride)
Cubic crystal structure (sodium chloride)
Ostwald ripening: Oil droplets in pastis mixed with water grow by Ostwald ripening.
Oil droplets in pastis mixed with water grow by Ostwald ripening.

Worked examples

Example 1 — a first encounter with Ostwald ripening

Start with the simplest possible case. Write down what Ostwald ripening claims or describes in one sentence, then invent the smallest concrete situation in which that sentence is true. In chemistry, the smallest case is usually a single object, a single equation or a single measurement. Check that every symbol or term in your sentence has a meaning in that case.

Example 2 — changing one variable

Take the situation from Example 1 and change exactly one quantity: double it, halve it, or set it to zero. Predict what should happen to Ostwald ripening before you calculate. Comparing your prediction with the result is the fastest way to find out whether you understand the idea or only the words.

Example 3 — an exam-style question

Typical questions about Ostwald ripening ask you to (a) state it precisely, (b) apply it to given data, and (c) explain a limitation. Practise writing all three answers in under five minutes; the third part is what separates a full-mark answer from an average one.

Applications of Ostwald ripening

In research
Ostwald ripening appears in chemistry research whenever the underlying quantities have to be modelled precisely. Papers usually cite it as a starting assumption and then explore where it breaks down.
In technology and industry
Engineering practice reuses Ostwald ripening in design rules, simulations and safety margins. Knowing the idea lets you read a specification sheet and understand why the numbers look the way they do.
In the classroom
Ostwald ripening is common in secondary-school and first-year university syllabi. It links to neighbouring topics Chemical engineering thermodynamics, Colloidal chemistry, Crystallographic defects, so understanding it makes those chapters shorter.
In everyday life
Look for Ostwald ripening outside the textbook — in sport, cooking, traffic, electronics or the sky above you. An example you found yourself is remembered far longer than one you were given.

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How to study Ostwald ripening in 20 minutes

  1. Read the reference excerpt below once, without taking notes.
  2. Close the page and write down what Ostwald ripening means in your own words.
  3. Compare your version with the excerpt and mark what you missed.
  4. Work through the three examples above with pen and paper.
  5. Explain Ostwald ripening out loud to somebody else — or to Teacher Smith in the lgStudy chat.

Frequently asked questions

What is Ostwald ripening in simple terms?

Ostwald ripening is a phenomenon observed in solid solutions and liquid sols that involves the change of an inhomogeneous structure over time, in that small crystals or sol particles first dissolve and then redeposit onto larger crystals or sol particles. Dissolution of small crystals or sol partic…

Why does Ostwald ripening matter?

Because it connects several chemistry ideas at once: it gives you a definition you can apply, a quantity you can calculate, and a way to check whether a result is plausible.

How should I study Ostwald ripening?

Read the excerpt, restate it from memory, then work through the examples and applications listed on this page. The five-step study plan above takes about twenty minutes.

What does this page cover?

It gives you a compact reference excerpt plus original lgStudy explanations, examples, applications and study material on Ostwald ripening.

Tags

  • Chemical engineering thermodynamics
  • Colloidal chemistry
  • Crystallographic defects
  • Physical chemistry
  • Precipitation

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