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Parabolic trajectory

Parabolic trajectory is a astronomy topic covered in the lgStudy science library. This page brings together a partial reference excerpt, illustrations, worked examples, real-world applications and a short study plan, so you can understand Parabolic trajectory rather than just read about it. In short: In astrodynamics or celestial mechanics a parabolic trajectory is a Kepler orbit with the eccentricity (e) equal to 1 and is an unbound orbit that is exactly on the border between elliptical and hyperbolic. When moving away from the source it is called an escape orbit, otherwise a capture orbit.

Parabolic trajectory — main illustration
Parabolic trajectory — illustration

Key takeaways

  • Parabolic trajectory belongs to astronomy; place it in that map before memorising details.
  • Learn the definition first, then one example that makes the definition concrete.
  • Connect Parabolic trajectory to a quantity you can measure, compute or draw — that is where exam questions come from.
  • Reproduce the core statement of Parabolic trajectory from memory before moving on to harder problems.

Reference excerpt

In astrodynamics or celestial mechanics a parabolic trajectory is a Kepler orbit with the eccentricity (e) equal to 1 and is an unbound orbit that is exactly on the border between elliptical and hyperbolic. When moving away from the source it is called an escape orbit, otherwise a capture orbit. It is also sometimes referred to as a C 3 = 0 {\displaystyle C_{3}=0} orbit (see characteristic energy). Under standard assumptions a body traveling along an escape orbit will coast along a parabolic trajectory to infinity, with velocity relative to the central body tending to zero, and therefore will never return. Parabolic trajectories are minimum-energy escape trajectories, separating positive-energy hyperbolic trajectories from negative-energy elliptic orbits.

History In 1609, Galileo wrote in his 102nd folio (MS. Gal 72) about parabolic trajectory calculations, later found in Discorsi e dimostrazioni matematiche intorno a due nuove scienze as projectiles impetus.

Velocity The orbital velocity ( v {\displaystyle v} ) of a body travelling along a parabolic trajectory can be computed as:

v = 2 μ r {\displaystyle v={\sqrt {2\mu \over r}}}

where:

r {\displaystyle r} is the radial distance of the orbiting body from the central body,

μ {\displaystyle \mu } is the standard gravitational parameter. At any position the orbiting body has the escape velocity for that position. If a body has an escape velocity with respect to the Earth, this is not enough to escape the Solar System, so near the Earth the orbit resembles a parabola, but further away it bends into an elliptical orbit around the Sun. This velocity ( v {\displaystyle v} ) is closely related to the orbital velocity of a body in a circular orbit of the radius equal to the radial position of orbiting body on the parabolic trajectory:

v = 2 v o {\displaystyle v={\sqrt {2}}\,v_{o}}

where:

v o {\displaystyle v_{o}} is orbital velocity of a body in circular orbit.

Equation of motion For a body moving along this kind of trajectory the orbital equation is:

r = h 2 μ 1 1 + cos ⁡ ν {\displaystyle r={h^{2} \over \mu }{1 \over {1+\cos \nu }}}

where:

r {\displaystyle r\,} is the radial distance of the orbiting body from the central body,

h {\displaystyle h\,} is the specific angular momentum of the orbiting body,

ν {\displaystyle \nu \,} is the true anomaly of the orbiting body,

μ {\displaystyle \mu \,} is the standard gravitational parameter.

Energy Under standard assumptions, the specific orbital energy ( ϵ {\displaystyle \epsilon } ) of a parabolic trajectory is zero, so the orbital energy conservation equation for this trajectory takes the form:

ϵ = v 2 2 − μ r = 0 {\displaystyle \epsilon ={v^{2} \over 2}-{\mu \over r}=0}

where:

v {\displaystyle v\,} is the orbital velocity of the orbiting body,

r {\displaystyle r\,} is the radial distance of the orbiting body from the central body,

μ {\displaystyle \mu \,} is the standard gravitational parameter. This is entirely equivalent to the characteristic energy (square of the speed at infinity) being 0:

C 3 = 0 {\displaystyle C_{3}=0}

Barker's equation Barker's equation relates the time of flight t {\displaystyle t} to the true anomaly ν {\displaystyle \nu } of a parabolic trajectory:

t − T = 1 2 p 3 μ ( D + 1 3 D 3 ) {\displaystyle t-T={\frac {1}{2}}{\sqrt {\frac {p^{3}}{\mu }}}\left(D+{\frac {1}{3}}D^{3}\right)}

where:

D = tan ⁡ ν 2 {\displaystyle D=\tan {\frac {\nu }{2}}} is an auxiliary variable

T {\displaystyle T} is the time of periapsis passage

μ {\displaystyle \mu } is the standard gravitational parameter

… excerpt ends here. Continue reading the full article.

Illustrations

Parabolic trajectory: The green path in this image is an example of a parabolic trajectory.
The green path in this image is an example of a parabolic trajectory.
Parabolic trajectory: A parabolic trajectory is depicted in the bottom-left quadrant of this diagram, where the gravitational potential well of the central mass shows potential energy, and the kinetic energy of the parabolic trajectory is shown in red. The height of the kinetic energy decreases asymptotically toward zero as the speed decreases and distance increases according to Kepler's laws.
A parabolic trajectory is depicted in the bottom-left quadrant of this diagram, where the gravitational potential well of the central mass shows potential energy, and the kinetic energy of the parabolic trajectory is shown in red. The height of the kinetic energy decreases asymptotically toward zero as the speed decreases and distance increases according to Kepler's laws.
Parabolic trajectory illustration

Worked examples

Example 1 — a first encounter with Parabolic trajectory

Start with the simplest possible case. Write down what Parabolic trajectory claims or describes in one sentence, then invent the smallest concrete situation in which that sentence is true. In astronomy, the smallest case is usually a single object, a single equation or a single measurement. Check that every symbol or term in your sentence has a meaning in that case.

Example 2 — changing one variable

Take the situation from Example 1 and change exactly one quantity: double it, halve it, or set it to zero. Predict what should happen to Parabolic trajectory before you calculate. Comparing your prediction with the result is the fastest way to find out whether you understand the idea or only the words.

Example 3 — an exam-style question

Typical questions about Parabolic trajectory ask you to (a) state it precisely, (b) apply it to given data, and (c) explain a limitation. Practise writing all three answers in under five minutes; the third part is what separates a full-mark answer from an average one.

Applications of Parabolic trajectory

In research
Parabolic trajectory appears in astronomy research whenever the underlying quantities have to be modelled precisely. Papers usually cite it as a starting assumption and then explore where it breaks down.
In technology and industry
Engineering practice reuses Parabolic trajectory in design rules, simulations and safety margins. Knowing the idea lets you read a specification sheet and understand why the numbers look the way they do.
In the classroom
Parabolic trajectory is common in secondary-school and first-year university syllabi. It links to neighbouring topics Orbits, so understanding it makes those chapters shorter.
In everyday life
Look for Parabolic trajectory outside the textbook — in sport, cooking, traffic, electronics or the sky above you. An example you found yourself is remembered far longer than one you were given.

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How to study Parabolic trajectory in 20 minutes

  1. Read the reference excerpt below once, without taking notes.
  2. Close the page and write down what Parabolic trajectory means in your own words.
  3. Compare your version with the excerpt and mark what you missed.
  4. Work through the three examples above with pen and paper.
  5. Explain Parabolic trajectory out loud to somebody else — or to Teacher Smith in the lgStudy chat.

Frequently asked questions

What is Parabolic trajectory in simple terms?

In astrodynamics or celestial mechanics a parabolic trajectory is a Kepler orbit with the eccentricity (e) equal to 1 and is an unbound orbit that is exactly on the border between elliptical and hyperbolic. When moving away from the source it is called an escape orbit, otherwise a capture orbit.

Why does Parabolic trajectory matter?

Because it connects several astronomy ideas at once: it gives you a definition you can apply, a quantity you can calculate, and a way to check whether a result is plausible.

How should I study Parabolic trajectory?

Read the excerpt, restate it from memory, then work through the examples and applications listed on this page. The five-step study plan above takes about twenty minutes.

What does this page cover?

It gives you a compact reference excerpt plus original lgStudy explanations, examples, applications and study material on Parabolic trajectory.

Tags

  • Orbits

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