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Perron's formula

Perron's formula is a mathematics topic covered in the lgStudy science library. This page brings together a partial reference excerpt, illustrations, worked examples, real-world applications and a short study plan, so you can understand Perron's formula rather than just read about it. In short: In mathematics, and more particularly in analytic number theory, Perron's formula is a formula discovered by Oskar Perron to calculate the sum of an arithmetic function, by means of an inverse Mellin transform. Statement Let { a ( n ) } {\displaystyle \{a(n)\}} be an arithmetic function, and let g ( s ) = ∑ n = 1 ∞ a ( n ) n s {\displaystyle g(s)=\sum _{n=1}^{\infty }{\frac {a(n)}{n^{s}}}} be the corresponding Diric…

Key takeaways

  • Perron's formula belongs to mathematics; place it in that map before memorising details.
  • Learn the definition first, then one example that makes the definition concrete.
  • Connect Perron's formula to a quantity you can measure, compute or draw — that is where exam questions come from.
  • Reproduce the core statement of Perron's formula from memory before moving on to harder problems.

Reference excerpt

In mathematics, and more particularly in analytic number theory, Perron's formula is a formula discovered by Oskar Perron to calculate the sum of an arithmetic function, by means of an inverse Mellin transform.

Statement Let { a ( n ) } {\displaystyle \{a(n)\}} be an arithmetic function, and let

g ( s ) = ∑ n = 1 ∞ a ( n ) n s {\displaystyle g(s)=\sum _{n=1}^{\infty }{\frac {a(n)}{n^{s}}}}

be the corresponding Dirichlet series. Presume the Dirichlet series to be uniformly convergent for ℜ ( s ) > σ {\displaystyle \Re (s)>\sigma } . Then Perron's formula is

A ( x ) = ∑ n ≤ x ′ a ( n ) = 1 2 π i ∫ c − i ∞ c + i ∞ g ( z ) x z z d z . {\displaystyle A(x)={\sum _{n\leq x}}'a(n)={\frac {1}{2\pi i}}\int _{c-i\infty }^{c+i\infty }g(z){\frac {x^{z}}{z}}\,dz.}

Here, the prime on the summation indicates that the last term of the sum must be multiplied by 1/2 when x is an integer. The integral is not a convergent Lebesgue integral; it is understood as the Cauchy principal value. The formula requires that c > 0, c > σ, and x > 0.

Proof An easy sketch of the proof comes from taking Abel's sum formula

g ( s ) = ∑ n = 1 ∞ a ( n ) n s = s ∫ 1 ∞ A ( x ) x − ( s + 1 ) d x . {\displaystyle g(s)=\sum _{n=1}^{\infty }{\frac {a(n)}{n^{s}}}=s\int _{1}^{\infty }A(x)x^{-(s+1)}dx.}

This is nothing but a Laplace transform under the variable change x = e t . {\displaystyle x=e^{t}.} Inverting it one gets Perron's formula. Proofs of Perron's formula have been published by Tom M. Apostol and by Gérald Tenenbaum.

Examples Because of its general relationship to Dirichlet series, the formula is commonly applied to many number-theoretic sums. Thus, for example, one has the famous integral representation for the Riemann zeta function:

ζ ( s ) = s ∫ 1 ∞ ⌊ x ⌋ x s + 1 d x {\displaystyle \zeta (s)=s\int _{1}^{\infty }{\frac {\lfloor x\rfloor }{x^{s+1}}}\,dx}

and a similar formula for Dirichlet L-functions:

L ( s , χ ) = s ∫ 1 ∞ A ( x ) x s + 1 d x {\displaystyle L(s,\chi )=s\int _{1}^{\infty }{\frac {A(x)}{x^{s+1}}}\,dx}

where

A ( x ) = ∑ n ≤ x χ ( n ) {\displaystyle A(x)=\sum _{n\leq x}\chi (n)}

and χ ( n ) {\displaystyle \chi (n)} is a Dirichlet character. Other examples appear in the articles on the Mertens function and the von Mangoldt function.

Generalizations Perron's formula is a special case of the formula

∑ n = 1 ∞ a ( n ) f ( n / x ) = 1 2 π i ∫ c − i ∞ c + i ∞ F ( s ) G ( s ) x s d s {\displaystyle \sum _{n=1}^{\infty }a(n)f(n/x)={\frac {1}{2\pi i}}\int _{c-i\infty }^{c+i\infty }F(s)G(s)x^{s}ds}

where

… excerpt ends here. Continue reading the full article.

Worked examples

Example 1 — a first encounter with Perron's formula

Start with the simplest possible case. Write down what Perron's formula claims or describes in one sentence, then invent the smallest concrete situation in which that sentence is true. In mathematics, the smallest case is usually a single object, a single equation or a single measurement. Check that every symbol or term in your sentence has a meaning in that case.

Example 2 — changing one variable

Take the situation from Example 1 and change exactly one quantity: double it, halve it, or set it to zero. Predict what should happen to Perron's formula before you calculate. Comparing your prediction with the result is the fastest way to find out whether you understand the idea or only the words.

Example 3 — an exam-style question

Typical questions about Perron's formula ask you to (a) state it precisely, (b) apply it to given data, and (c) explain a limitation. Practise writing all three answers in under five minutes; the third part is what separates a full-mark answer from an average one.

Applications of Perron's formula

In research
Perron's formula appears in mathematics research whenever the underlying quantities have to be modelled precisely. Papers usually cite it as a starting assumption and then explore where it breaks down.
In technology and industry
Engineering practice reuses Perron's formula in design rules, simulations and safety margins. Knowing the idea lets you read a specification sheet and understand why the numbers look the way they do.
In the classroom
Perron's formula is common in secondary-school and first-year university syllabi. It links to neighbouring topics Calculus, Integral transforms, Summability methods, so understanding it makes those chapters shorter.
In everyday life
Look for Perron's formula outside the textbook — in sport, cooking, traffic, electronics or the sky above you. An example you found yourself is remembered far longer than one you were given.

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How to study Perron's formula in 20 minutes

  1. Read the reference excerpt below once, without taking notes.
  2. Close the page and write down what Perron's formula means in your own words.
  3. Compare your version with the excerpt and mark what you missed.
  4. Work through the three examples above with pen and paper.
  5. Explain Perron's formula out loud to somebody else — or to Teacher Smith in the lgStudy chat.

Frequently asked questions

What is Perron's formula in simple terms?

In mathematics, and more particularly in analytic number theory, Perron's formula is a formula discovered by Oskar Perron to calculate the sum of an arithmetic function, by means of an inverse Mellin transform. Statement Let { a ( n ) } {\displaystyle \{a(n)\}} be an arithmetic function, and let g…

Why does Perron's formula matter?

Because it connects several mathematics ideas at once: it gives you a definition you can apply, a quantity you can calculate, and a way to check whether a result is plausible.

How should I study Perron's formula?

Read the excerpt, restate it from memory, then work through the examples and applications listed on this page. The five-step study plan above takes about twenty minutes.

What does this page cover?

It gives you a compact reference excerpt plus original lgStudy explanations, examples, applications and study material on Perron's formula.

Tags

  • Calculus
  • Integral transforms
  • Summability methods
  • Theorems in analytic number theory

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