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Pilling–Bedworth ratio

Pilling–Bedworth ratio is a science topic covered in the lgStudy science library. This page brings together a partial reference excerpt, illustrations, worked examples, real-world applications and a short study plan, so you can understand Pilling–Bedworth ratio rather than just read about it. In short: In corrosion of metals, the Pilling–Bedworth ratio (P–B ratio) is the ratio of the volume of the elementary cell of a metal oxide to the volume of the elementary cell of the corresponding metal (from which the oxide is created). On the basis of the P–B ratio, it can be judged whether the metal is likely to passivate in dry air by creation of a protective oxide layer.

Pilling–Bedworth ratio — main illustration
Pilling–Bedworth ratio — illustration

Key takeaways

  • Pilling–Bedworth ratio belongs to science; place it in that map before memorising details.
  • Learn the definition first, then one example that makes the definition concrete.
  • Connect Pilling–Bedworth ratio to a quantity you can measure, compute or draw — that is where exam questions come from.
  • Reproduce the core statement of Pilling–Bedworth ratio from memory before moving on to harder problems.

Reference excerpt

In corrosion of metals, the Pilling–Bedworth ratio (P–B ratio) is the ratio of the volume of the elementary cell of a metal oxide to the volume of the elementary cell of the corresponding metal (from which the oxide is created). On the basis of the P–B ratio, it can be judged whether the metal is likely to passivate in dry air by creation of a protective oxide layer.

Definition The P–B ratio is defined as

R P B = V oxide n ⋅ V metal = M oxide ⋅ ρ metal n ⋅ M metal ⋅ ρ oxide , {\displaystyle R_{PB}={\frac {V_{\text{oxide}}}{n\cdot V_{\text{metal}}}}={\frac {M_{\text{oxide}}\cdot \rho _{\text{metal}}}{n\cdot M_{\text{metal}}\cdot \rho _{\text{oxide}}}},}

where

M {\displaystyle M} is the atomic or molecular mass,

n {\displaystyle n} is the number of atoms of metal per molecule of the oxide,

ρ {\displaystyle \rho } is the density,

V {\displaystyle V} is the molar volume.

History N.B. Pilling and R.E. Bedworth suggested in 1923 that metals can be classed into two categories: those that form protective oxides, and those that cannot. They ascribed the protectiveness of the oxide to the volume the oxide takes in comparison to the volume of the metal used to produce this oxide in a corrosion process in dry air. The oxide layer would be unprotective if the ratio is less than unity because the film that forms on the metal surface is porous and/or cracked. Conversely, the metals with the ratio higher than 1 tend to be protective because they form an effective barrier that prevents the gas from further oxidizing the metal.

Application

On the basis of measurements, the following connection can be shown:

RPB < 1: the oxide coating layer is too thin, likely broken and provides no protective effect (for example magnesium) RPB > 2: the oxide coating chips off and provides no protective effect (example iron) 1 < RPB < 2: the oxide coating is passivating and provides a protecting effect against further surface oxidation (examples aluminium, titanium, chromium-containing steels). However, the exceptions to the above P–B ratio rules are numerous. Many of the exceptions can be attributed to the mechanism of the oxide growth: the underlying assumption in the P–B ratio is that oxygen needs to diffuse through the oxide layer to the metal surface; in reality, it is often the metal ion that diffuses to the air-oxide interface. The P–B ratio is important when modelling the oxidation of nuclear fuel cladding tubes, which are typically made of Zirconium alloys, as it defines how much of the cladding that is consumed and weakened due to oxidation. The P–B ratio of Zirconium alloys can vary between 1.48 and 1.56, meaning that the oxide is more voluminous than the consumed metal.

Values

References

Worked examples

Example 1 — a first encounter with Pilling–Bedworth ratio

Start with the simplest possible case. Write down what Pilling–Bedworth ratio claims or describes in one sentence, then invent the smallest concrete situation in which that sentence is true. In science, the smallest case is usually a single object, a single equation or a single measurement. Check that every symbol or term in your sentence has a meaning in that case.

Example 2 — changing one variable

Take the situation from Example 1 and change exactly one quantity: double it, halve it, or set it to zero. Predict what should happen to Pilling–Bedworth ratio before you calculate. Comparing your prediction with the result is the fastest way to find out whether you understand the idea or only the words.

Example 3 — an exam-style question

Typical questions about Pilling–Bedworth ratio ask you to (a) state it precisely, (b) apply it to given data, and (c) explain a limitation. Practise writing all three answers in under five minutes; the third part is what separates a full-mark answer from an average one.

Applications of Pilling–Bedworth ratio

In research
Pilling–Bedworth ratio appears in science research whenever the underlying quantities have to be modelled precisely. Papers usually cite it as a starting assumption and then explore where it breaks down.
In technology and industry
Engineering practice reuses Pilling–Bedworth ratio in design rules, simulations and safety margins. Knowing the idea lets you read a specification sheet and understand why the numbers look the way they do.
In the classroom
Pilling–Bedworth ratio is common in secondary-school and first-year university syllabi. It links to neighbouring topics Corrosion prevention, so understanding it makes those chapters shorter.
In everyday life
Look for Pilling–Bedworth ratio outside the textbook — in sport, cooking, traffic, electronics or the sky above you. An example you found yourself is remembered far longer than one you were given.
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How to study Pilling–Bedworth ratio in 20 minutes

  1. Read the reference excerpt below once, without taking notes.
  2. Close the page and write down what Pilling–Bedworth ratio means in your own words.
  3. Compare your version with the excerpt and mark what you missed.
  4. Work through the three examples above with pen and paper.
  5. Explain Pilling–Bedworth ratio out loud to somebody else — or to Teacher Smith in the lgStudy chat.

Frequently asked questions

What is Pilling–Bedworth ratio in simple terms?

In corrosion of metals, the Pilling–Bedworth ratio (P–B ratio) is the ratio of the volume of the elementary cell of a metal oxide to the volume of the elementary cell of the corresponding metal (from which the oxide is created). On the basis of the P–B ratio, it can be judged whether the metal is l…

Why does Pilling–Bedworth ratio matter?

Because it connects several science ideas at once: it gives you a definition you can apply, a quantity you can calculate, and a way to check whether a result is plausible.

How should I study Pilling–Bedworth ratio?

Read the excerpt, restate it from memory, then work through the examples and applications listed on this page. The five-step study plan above takes about twenty minutes.

What does this page cover?

It gives you a compact reference excerpt plus original lgStudy explanations, examples, applications and study material on Pilling–Bedworth ratio.

Tags

  • Corrosion prevention

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