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Poisson kernel

Poisson kernel is a mathematics topic covered in the lgStudy science library. This page brings together a partial reference excerpt, illustrations, worked examples, real-world applications and a short study plan, so you can understand Poisson kernel rather than just read about it. In short: In mathematics, and specifically in potential theory, the Poisson kernel is an integral kernel, used for solving the two-dimensional Laplace equation, given Dirichlet boundary conditions on the unit disk. The kernel can be understood as the derivative of the Green's function for the Laplace equation.

Key takeaways

  • Poisson kernel belongs to mathematics; place it in that map before memorising details.
  • Learn the definition first, then one example that makes the definition concrete.
  • Connect Poisson kernel to a quantity you can measure, compute or draw — that is where exam questions come from.
  • Reproduce the core statement of Poisson kernel from memory before moving on to harder problems.

Reference excerpt

In mathematics, and specifically in potential theory, the Poisson kernel is an integral kernel, used for solving the two-dimensional Laplace equation, given Dirichlet boundary conditions on the unit disk. The kernel can be understood as the derivative of the Green's function for the Laplace equation. It is named for Siméon Poisson. Poisson kernels commonly find applications in control theory and two-dimensional problems in electrostatics. In practice, the definition of Poisson kernels are often extended to n-dimensional problems.

Two-dimensional Poisson kernels

On the unit disc In the complex plane, the Poisson kernel for the unit disc is given by

P r ( θ ) = ∑ n = − ∞ ∞ r | n | e i n θ = 1 − r 2 1 − 2 r cos ⁡ θ + r 2 = Re ⁡ ( 1 + r e i θ 1 − r e i θ ) , 0 ≤ r < 1. {\displaystyle P_{r}(\theta )=\sum _{n=-\infty }^{\infty }r^{|n|}e^{in\theta }={\frac {1-r^{2}}{1-2r\cos \theta +r^{2}}}=\operatorname {Re} \left({\frac {1+re^{i\theta }}{1-re^{i\theta }}}\right),\ \ \ 0\leq r<1.}

This can be thought of in two ways: either as a function of r and θ, or as a family of functions of θ indexed by r. If D = { z : | z | < 1 } {\displaystyle D=\{z:|z|<1\}} is the open unit disc in C, T is the boundary of the disc, and f a function on T that lies in L1(T), then the function u given by

u ( r e i θ ) = 1 2 π ∫ − π π P r ( θ − t ) f ( e i t ) d t , 0 ≤ r < 1 {\displaystyle u(re^{i\theta })={\frac {1}{2\pi }}\int _{-\pi }^{\pi }P_{r}(\theta -t)f(e^{it})\,\mathrm {d} t,\quad 0\leq r<1}

is harmonic in D and has a radial limit that agrees with f almost everywhere on the boundary T of the disc. That the boundary value of u is f can be argued using the fact that as r → 1, the functions Pr(θ) form an approximate unit in the convolution algebra L1(T). As linear operators, they tend to the Dirac delta function pointwise on Lp(T). By the maximum principle, u is the only such harmonic function on D. Convolutions with this approximate unit gives an example of a summability kernel for the Fourier series of a function in L1(T) (Katznelson 1976). Let f ∈ L1(T) have Fourier series {fk}. After the Fourier transform, convolution with Pr(θ) becomes multiplication by the sequence {r|k|} ∈ ℓ1(Z). Taking the inverse Fourier transform of the resulting product {r|k|fk} gives the Abel means Arf of f:

A r f ( e 2 π i x ) = ∑ k ∈ Z f k r | k | e 2 π i k x . {\displaystyle A_{r}f(e^{2\pi ix})=\sum _{k\in \mathbb {Z} }f_{k}r^{|k|}e^{2\pi ikx}.}

Rearranging this absolutely convergent series shows that f is the boundary value of g + h, where g (resp. h) is a holomorphic (resp. antiholomorphic) function on D. When one also asks for the harmonic extension to be holomorphic, then the solutions are elements of a Hardy space. This is true when the negative Fourier coefficients of f all vanish. In particular, the Poisson kernel is commonly used to demonstrate the equivalence of the Hardy spaces on the unit disk, and the unit circle. The space of functions that are the limits on T of functions in Hp(z) may be called Hp(T). It is a closed subspace of Lp(T) (at least for p ≥ 1). Since Lp(T) is a Banach space (for 1 ≤ p ≤ ∞), so is Hp(T).

On the upper half-plane The unit disk may be conformally mapped to the upper half-plane by means of certain Möbius transformations. Since the conformal map of a harmonic function is also harmonic, the Poisson kernel carries over to the upper half-plane. In this case, the Poisson integral equation takes the form

… excerpt ends here. Continue reading the full article.

Worked examples

Example 1 — a first encounter with Poisson kernel

Start with the simplest possible case. Write down what Poisson kernel claims or describes in one sentence, then invent the smallest concrete situation in which that sentence is true. In mathematics, the smallest case is usually a single object, a single equation or a single measurement. Check that every symbol or term in your sentence has a meaning in that case.

Example 2 — changing one variable

Take the situation from Example 1 and change exactly one quantity: double it, halve it, or set it to zero. Predict what should happen to Poisson kernel before you calculate. Comparing your prediction with the result is the fastest way to find out whether you understand the idea or only the words.

Example 3 — an exam-style question

Typical questions about Poisson kernel ask you to (a) state it precisely, (b) apply it to given data, and (c) explain a limitation. Practise writing all three answers in under five minutes; the third part is what separates a full-mark answer from an average one.

Applications of Poisson kernel

In research
Poisson kernel appears in mathematics research whenever the underlying quantities have to be modelled precisely. Papers usually cite it as a starting assumption and then explore where it breaks down.
In technology and industry
Engineering practice reuses Poisson kernel in design rules, simulations and safety margins. Knowing the idea lets you read a specification sheet and understand why the numbers look the way they do.
In the classroom
Poisson kernel is common in secondary-school and first-year university syllabi. It links to neighbouring topics Fourier analysis, Harmonic functions, Potential theory, so understanding it makes those chapters shorter.
In everyday life
Look for Poisson kernel outside the textbook — in sport, cooking, traffic, electronics or the sky above you. An example you found yourself is remembered far longer than one you were given.
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How to study Poisson kernel in 20 minutes

  1. Read the reference excerpt below once, without taking notes.
  2. Close the page and write down what Poisson kernel means in your own words.
  3. Compare your version with the excerpt and mark what you missed.
  4. Work through the three examples above with pen and paper.
  5. Explain Poisson kernel out loud to somebody else — or to Teacher Smith in the lgStudy chat.

Frequently asked questions

What is Poisson kernel in simple terms?

In mathematics, and specifically in potential theory, the Poisson kernel is an integral kernel, used for solving the two-dimensional Laplace equation, given Dirichlet boundary conditions on the unit disk. The kernel can be understood as the derivative of the Green's function for the Laplace equatio…

Why does Poisson kernel matter?

Because it connects several mathematics ideas at once: it gives you a definition you can apply, a quantity you can calculate, and a way to check whether a result is plausible.

How should I study Poisson kernel?

Read the excerpt, restate it from memory, then work through the examples and applications listed on this page. The five-step study plan above takes about twenty minutes.

What does this page cover?

It gives you a compact reference excerpt plus original lgStudy explanations, examples, applications and study material on Poisson kernel.

Tags

  • Fourier analysis
  • Harmonic functions
  • Potential theory

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