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physics

Polarizability

Polarizability is a physics topic covered in the lgStudy science library. This page brings together a partial reference excerpt, illustrations, worked examples, real-world applications and a short study plan, so you can understand Polarizability rather than just read about it. In short: Polarizability usually refers to the tendency of matter, when subjected to an electric field, to acquire an electric dipole moment in proportion to that applied field. It is a property of particles with an electric charge.

Polarizability — main illustration
Polarizability — illustration

Key takeaways

  • Polarizability belongs to physics; place it in that map before memorising details.
  • Learn the definition first, then one example that makes the definition concrete.
  • Connect Polarizability to a quantity you can measure, compute or draw — that is where exam questions come from.
  • Reproduce the core statement of Polarizability from memory before moving on to harder problems.

Reference excerpt

Polarizability usually refers to the tendency of matter, when subjected to an electric field, to acquire an electric dipole moment in proportion to that applied field. It is a property of particles with an electric charge. When subject to an electric field, the negatively charged electrons and positively charged atomic nuclei are subject to opposite forces and undergo charge separation. Polarizability is responsible for a material's dielectric constant and, at high (optical) frequencies, its refractive index. The polarizability of an atom or molecule is defined as the ratio of its induced dipole moment to the local electric field; in a crystalline solid, one considers the dipole moment per unit cell. Note that the local electric field seen by a molecule is generally different from the macroscopic electric field that would be measured externally. This discrepancy is taken into account by the Clausius–Mossotti relation (below) which connects the bulk behaviour (polarization density due to an external electric field according to the electric susceptibility χ = ε r − 1 {\displaystyle \chi =\varepsilon _{\mathrm {r} }-1} ) with the molecular polarizability α {\displaystyle \alpha } due to the local field. Magnetic polarizability likewise refers to the tendency for a magnetic dipole moment to appear in proportion to an external magnetic field. Electric and magnetic polarizabilities determine the dynamical response of a bound system (such as a molecule or crystal) to external fields, and provide insight into a molecule's internal structure. "Polarizability" should not be confused with the intrinsic magnetic or electric dipole moment of an atom, molecule, or bulk substance; these do not depend on the presence of an external field.

Electric polarizability

Definition Electric polarizability is the relative tendency of a charge distribution, like the electron cloud of an atom or molecule, to be distorted from its normal shape by an external electric field. The polarizability α {\displaystyle \alpha } in isotropic media is defined as the ratio of the induced dipole moment p {\displaystyle \mathbf {p} } of an atom to the electric field E {\displaystyle \mathbf {E} } that produces this dipole moment.

α = | p | | E | {\displaystyle \alpha ={\frac {\left|\mathbf {p} \right|}{\left|\mathbf {E} \right|}}}

Polarizability has the SI units of C·m2·V−1 = A2·s4·kg−1 while its cgs unit is cm3. Usually it is expressed in cgs units as a so-called polarizability volume, sometimes expressed in Å3 = 10−24 cm3. One can convert from SI units ( α {\displaystyle \alpha } ) to cgs units ( α ′ {\displaystyle \alpha '} ) as follows:

α ′ ( c m 3 ) = 10 6 4 π ε 0 α ( C ⋅ m 2 ⋅ V − 1 ) = 10 6 4 π ε 0 α ( F ⋅ m 2 ) ≈ 8.988 × 10 15 × α ( F ⋅ m 2 ) {\displaystyle \alpha '(\mathrm {cm} ^{3})={\frac {10^{6}}{4\pi \varepsilon _{0}}}\alpha (\mathrm {C{\cdot }m^{2}{\cdot }V^{-1}} )={\frac {10^{6}}{4\pi \varepsilon _{0}}}\alpha (\mathrm {F{\cdot }m^{2}} )\approx 8.988{\times }{10}^{15}\times \alpha (\mathrm {F{\cdot }m^{2}} )}

where ε 0 {\displaystyle \varepsilon _{0}} , the vacuum permittivity, is ≈8.854 × 10−12 (F/m). If the polarizability volume in cgs units is denoted α ′ {\displaystyle \alpha '} the relation can be expressed generally (in SI) as α = 4 π ε 0 α ′ {\displaystyle \alpha =4\pi \varepsilon _{0}\alpha '} . The polarizability of individual particles is related to the average electric susceptibility of the medium by the Clausius–Mossotti relation:

… excerpt ends here. Continue reading the full article.

Worked examples

Example 1 — a first encounter with Polarizability

Start with the simplest possible case. Write down what Polarizability claims or describes in one sentence, then invent the smallest concrete situation in which that sentence is true. In physics, the smallest case is usually a single object, a single equation or a single measurement. Check that every symbol or term in your sentence has a meaning in that case.

Example 2 — changing one variable

Take the situation from Example 1 and change exactly one quantity: double it, halve it, or set it to zero. Predict what should happen to Polarizability before you calculate. Comparing your prediction with the result is the fastest way to find out whether you understand the idea or only the words.

Example 3 — an exam-style question

Typical questions about Polarizability ask you to (a) state it precisely, (b) apply it to given data, and (c) explain a limitation. Practise writing all three answers in under five minutes; the third part is what separates a full-mark answer from an average one.

Applications of Polarizability

In research
Polarizability appears in physics research whenever the underlying quantities have to be modelled precisely. Papers usually cite it as a starting assumption and then explore where it breaks down.
In technology and industry
Engineering practice reuses Polarizability in design rules, simulations and safety margins. Knowing the idea lets you read a specification sheet and understand why the numbers look the way they do.
In the classroom
Polarizability is common in secondary-school and first-year university syllabi. It links to neighbouring topics Atomic physics, Chemical physics, Electric and magnetic fields in matter, so understanding it makes those chapters shorter.
In everyday life
Look for Polarizability outside the textbook — in sport, cooking, traffic, electronics or the sky above you. An example you found yourself is remembered far longer than one you were given.

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How to study Polarizability in 20 minutes

  1. Read the reference excerpt below once, without taking notes.
  2. Close the page and write down what Polarizability means in your own words.
  3. Compare your version with the excerpt and mark what you missed.
  4. Work through the three examples above with pen and paper.
  5. Explain Polarizability out loud to somebody else — or to Teacher Smith in the lgStudy chat.

Frequently asked questions

What is Polarizability in simple terms?

Polarizability usually refers to the tendency of matter, when subjected to an electric field, to acquire an electric dipole moment in proportion to that applied field. It is a property of particles with an electric charge.

Why does Polarizability matter?

Because it connects several physics ideas at once: it gives you a definition you can apply, a quantity you can calculate, and a way to check whether a result is plausible.

How should I study Polarizability?

Read the excerpt, restate it from memory, then work through the examples and applications listed on this page. The five-step study plan above takes about twenty minutes.

What does this page cover?

It gives you a compact reference excerpt plus original lgStudy explanations, examples, applications and study material on Polarizability.

Tags

  • Atomic physics
  • Chemical physics
  • Electric and magnetic fields in matter
  • Polarization (waves)

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