In mathematical analysis a pseudo-differential operator is an extension of the concept of differential operator. Pseudo-differential operators are used extensively in the theory of partial differential equations and quantum field theory, e.g. in mathematical models that include ultrametric pseudo-differential equations in a non-Archimedean space.
History The study of pseudo-differential operators began in the mid 1960s with the work of Kohn, Nirenberg, Hörmander, Unterberger and Bokobza. They played an influential role in the second proof of the Atiyah–Singer index theorem via K-theory. Atiyah and Singer thanked Hörmander for assistance with understanding the theory of pseudo-differential operators.
Motivation
Linear differential operators with constant coefficients Consider a linear differential operator with constant coefficients,
P ( D ) := ∑ α a α D α {\displaystyle P(D):=\sum _{\alpha }a_{\alpha }\,D^{\alpha }}
which acts on smooth functions u {\displaystyle u} with compact support in Rn. This operator can be written as a composition of a Fourier transform, a simple multiplication by the polynomial function (called the symbol)
P ( ξ ) = ∑ α a α ξ α , {\displaystyle P(\xi )=\sum _{\alpha }a_{\alpha }\,\xi ^{\alpha },}
and an inverse Fourier transform, in the form:
Here, α = ( α 1 , … , α n ) {\displaystyle \alpha =(\alpha _{1},\ldots ,\alpha _{n})} is a multi-index, a α {\displaystyle a_{\alpha }} are complex numbers, and
D α = ( − i ∂ 1 ) α 1 ⋯ ( − i ∂ n ) α n {\displaystyle D^{\alpha }=(-i\partial _{1})^{\alpha _{1}}\cdots (-i\partial _{n})^{\alpha _{n}}}
is an iterated partial derivative, where ∂j means differentiation with respect to the j-th variable. We introduce the constants − i {\displaystyle -i} to facilitate the calculation of Fourier transforms.
Derivation of formula (1) The Fourier transform of a smooth function u, compactly supported in Rn, is
u ^ ( ξ ) := ∫ e − i y ξ u ( y ) d y {\displaystyle {\hat {u}}(\xi ):=\int e^{-iy\xi }u(y)\,dy}
and Fourier's inversion formula gives
u ( x ) = 1 ( 2 π ) n ∫ e i x ξ u ^ ( ξ ) d ξ = 1 ( 2 π ) n ∬ e i ( x − y ) ξ u ( y ) d y d ξ {\displaystyle u(x)={\frac {1}{(2\pi )^{n}}}\int e^{ix\xi }{\hat {u}}(\xi )d\xi ={\frac {1}{(2\pi )^{n}}}\iint e^{i(x-y)\xi }u(y)\,dy\,d\xi }
By applying P(D) to this representation of u and using
P ( D x ) e i ( x − y ) ξ = e i ( x − y ) ξ P ( ξ ) {\displaystyle P(D_{x})\,e^{i(x-y)\xi }=e^{i(x-y)\xi }\,P(\xi )}
one obtains formula (1).
Representation of solutions to partial differential equations To solve the partial differential equation
P ( D ) u = f {\displaystyle P(D)\,u=f}
we (formally) apply the Fourier transform on both sides and obtain the algebraic equation
P ( ξ ) u ^ ( ξ ) = f ^ ( ξ ) . {\displaystyle P(\xi )\,{\hat {u}}(\xi )={\hat {f}}(\xi ).}
… excerpt ends here. Continue reading the full article.
