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Raoult's law

Raoult's law is a physics topic covered in the lgStudy science library. This page brings together a partial reference excerpt, illustrations, worked examples, real-world applications and a short study plan, so you can understand Raoult's law rather than just read about it. In short: Raoult's law ( law) is a relation of physical chemistry, with implications in thermodynamics. Proposed by French chemist François-Marie Raoult in 1887, it states that the partial pressure of each component of an ideal mixture of liquids is equal to the vapor pressure of the pure component (liquid or solid) multiplied by its mole fraction in the mixture.

Raoult's law — main illustration
Raoult's law — illustration

Key takeaways

  • Raoult's law belongs to physics; place it in that map before memorising details.
  • Learn the definition first, then one example that makes the definition concrete.
  • Connect Raoult's law to a quantity you can measure, compute or draw — that is where exam questions come from.
  • Reproduce the core statement of Raoult's law from memory before moving on to harder problems.

Reference excerpt

Raoult's law ( law) is a relation of physical chemistry, with implications in thermodynamics. Proposed by French chemist François-Marie Raoult in 1887, it states that the partial pressure of each component of an ideal mixture of liquids is equal to the vapor pressure of the pure component (liquid or solid) multiplied by its mole fraction in the mixture. In consequence, the relative lowering of vapor pressure of a dilute solution of nonvolatile solute is equal to the mole fraction of solute in the solution. Mathematically, Raoult's law for a single component in an ideal solution is stated as

p i = p i ⋆ x i {\displaystyle p_{i}=p_{i}^{\star }x_{i}}

where p i {\displaystyle p_{i}} is the partial pressure of the component i {\displaystyle i} in the gaseous mixture above the solution, p i ⋆ {\displaystyle p_{i}^{\star }} is the equilibrium vapor pressure of the pure component i {\displaystyle i} , and x i {\displaystyle x_{i}} is the mole fraction of the component i {\displaystyle i} in the liquid or solid solution. Where two volatile liquids A and B are mixed with each other to form a solution, the vapor phase consists of both components of the solution. Once the components in the solution have reached equilibrium, the total vapor pressure of the solution can be determined by combining Raoult's law with Dalton's law of partial pressures to give

p = p A ⋆ x A + p B ⋆ x B + ⋯ . {\displaystyle p=p_{\text{A}}^{\star }x_{\text{A}}+p_{\text{B}}^{\star }x_{\text{B}}+\cdots .}

In other words, the vapor pressure of the solution is the mole-weighted mean of the individual vapour pressures:

p = p A ⋆ n A + p B ⋆ n B + ⋯ n A + n B + ⋯ {\displaystyle p={\dfrac {p_{\text{A}}^{\star }n_{\text{A}}+p_{\text{B}}^{\star }n_{\text{B}}+\cdots }{n_{\text{A}}+n_{\text{B}}+\cdots }}}

If a non-volatile solute B (it has zero vapor pressure, so does not evaporate) is dissolved into a solvent A to form an ideal solution, the vapor pressure of the solution will be lower than that of the solvent. In an ideal solution of a nonvolatile solute, the decrease in vapor pressure is directly proportional to the mole fraction of solute:

p = p A ⋆ x A , {\displaystyle p=p_{\text{A}}^{\star }x_{\text{A}},}

Δ p = p A ⋆ − p = p A ⋆ ( 1 − x A ) = p A ⋆ x B . {\displaystyle \Delta p=p_{\text{A}}^{\star }-p=p_{\text{A}}^{\star }(1-x_{\text{A}})=p_{\text{A}}^{\star }x_{\text{B}}.}

If the solute associates or dissociates in the solution (such as an electrolyte/salt), the expression of the law includes the van 't Hoff factor as a correction factor. That is, the mole fraction must be calculated using the actual number of particles in solution.

Principles

… excerpt ends here. Continue reading the full article.

Illustrations

Raoult's law: Negative deviation from Raoult's law
Negative deviation from Raoult's law
Raoult's law: Positive deviation from Raoult's law
Positive deviation from Raoult's law

Worked examples

Example 1 — a first encounter with Raoult's law

Start with the simplest possible case. Write down what Raoult's law claims or describes in one sentence, then invent the smallest concrete situation in which that sentence is true. In physics, the smallest case is usually a single object, a single equation or a single measurement. Check that every symbol or term in your sentence has a meaning in that case.

Example 2 — changing one variable

Take the situation from Example 1 and change exactly one quantity: double it, halve it, or set it to zero. Predict what should happen to Raoult's law before you calculate. Comparing your prediction with the result is the fastest way to find out whether you understand the idea or only the words.

Example 3 — an exam-style question

Typical questions about Raoult's law ask you to (a) state it precisely, (b) apply it to given data, and (c) explain a limitation. Practise writing all three answers in under five minutes; the third part is what separates a full-mark answer from an average one.

Applications of Raoult's law

In research
Raoult's law appears in physics research whenever the underlying quantities have to be modelled precisely. Papers usually cite it as a starting assumption and then explore where it breaks down.
In technology and industry
Engineering practice reuses Raoult's law in design rules, simulations and safety margins. Knowing the idea lets you read a specification sheet and understand why the numbers look the way they do.
In the classroom
Raoult's law is common in secondary-school and first-year university syllabi. It links to neighbouring topics Distillation, Engineering thermodynamics, Equilibrium chemistry, so understanding it makes those chapters shorter.
In everyday life
Look for Raoult's law outside the textbook — in sport, cooking, traffic, electronics or the sky above you. An example you found yourself is remembered far longer than one you were given.

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How to study Raoult's law in 20 minutes

  1. Read the reference excerpt below once, without taking notes.
  2. Close the page and write down what Raoult's law means in your own words.
  3. Compare your version with the excerpt and mark what you missed.
  4. Work through the three examples above with pen and paper.
  5. Explain Raoult's law out loud to somebody else — or to Teacher Smith in the lgStudy chat.

Frequently asked questions

What is Raoult's law in simple terms?

Raoult's law ( law) is a relation of physical chemistry, with implications in thermodynamics. Proposed by French chemist François-Marie Raoult in 1887, it states that the partial pressure of each component of an ideal mixture of liquids is equal to the vapor pressure of the pure component (liquid o…

Why does Raoult's law matter?

Because it connects several physics ideas at once: it gives you a definition you can apply, a quantity you can calculate, and a way to check whether a result is plausible.

How should I study Raoult's law?

Read the excerpt, restate it from memory, then work through the examples and applications listed on this page. The five-step study plan above takes about twenty minutes.

What does this page cover?

It gives you a compact reference excerpt plus original lgStudy explanations, examples, applications and study material on Raoult's law.

Tags

  • Distillation
  • Engineering thermodynamics
  • Equilibrium chemistry
  • Physical chemistry
  • Solutions

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