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Rate equation

Rate equation is a chemistry topic covered in the lgStudy science library. This page brings together a partial reference excerpt, illustrations, worked examples, real-world applications and a short study plan, so you can understand Rate equation rather than just read about it. In short: In chemistry, the rate equation (also known as the rate law or empirical differential rate equation) is an empirical differential mathematical expression for the reaction rate of a given reaction in terms of concentrations of chemical species and constant parameters (normally rate coefficients and partial orders of reaction) only. For many reactions, the initial rate is given by a power law such as v 0 = k [ A ] x […

Rate equation — main illustration
Rate equation — illustration

Key takeaways

  • Rate equation belongs to chemistry; place it in that map before memorising details.
  • Learn the definition first, then one example that makes the definition concrete.
  • Connect Rate equation to a quantity you can measure, compute or draw — that is where exam questions come from.
  • Reproduce the core statement of Rate equation from memory before moving on to harder problems.

Reference excerpt

In chemistry, the rate equation (also known as the rate law or empirical differential rate equation) is an empirical differential mathematical expression for the reaction rate of a given reaction in terms of concentrations of chemical species and constant parameters (normally rate coefficients and partial orders of reaction) only. For many reactions, the initial rate is given by a power law such as

v 0 = k [ A ] x [ B ] y {\displaystyle v_{0}\;=\;k[\mathrm {A} ]^{x}[\mathrm {B} ]^{y}}

where ⁠ [ A ] {\displaystyle [\mathrm {A} ]} ⁠ and ⁠ [ B ] {\displaystyle [\mathrm {B} ]} ⁠ are the molar concentrations of the species ⁠ A {\displaystyle \mathrm {A} } ⁠ and ⁠ B , {\displaystyle \mathrm {B} ,} ⁠ usually in moles per liter (molarity, ⁠ M {\displaystyle M} ⁠). The exponents ⁠ x {\displaystyle x} ⁠ and ⁠ y {\displaystyle y} ⁠ are the partial orders of reaction for ⁠ A {\displaystyle \mathrm {A} } ⁠ and ⁠ B {\displaystyle \mathrm {B} } ⁠, respectively, and the overall reaction order is the sum of the exponents. These are often positive integers, but they may also be zero, fractional, or negative. The order of reaction is a number which quantifies the degree to which the rate of a chemical reaction depends on concentrations of the reactants. In other words, the order of reaction is the exponent to which the concentration of a particular reactant is raised. The constant ⁠ k {\displaystyle k} ⁠ is the reaction rate constant or rate coefficient and at very few places velocity constant or specific rate of reaction. Its value may depend on conditions such as temperature, ionic strength, surface area of an adsorbent, or light irradiation. If the reaction goes to completion, the rate equation for the reaction rate v = k [ A ] x [ B ] y {\displaystyle v\;=\;k[{\ce {A}}]^{x}[{\ce {B}}]^{y}} applies throughout the course of the reaction. Elementary (single-step) reactions and reaction steps have reaction orders equal to the stoichiometric coefficients for each reactant. The overall reaction order, i.e. the sum of stoichiometric coefficients of reactants, is always equal to the molecularity of the elementary reaction. However, complex (multi-step) reactions may or may not have reaction orders equal to their stoichiometric coefficients. This implies that the order and the rate equation of a given reaction cannot be reliably deduced from the stoichiometry and must be determined experimentally, since an unknown reaction mechanism could be either elementary or complex. When the experimental rate equation has been determined, it is often of use for deduction of the reaction mechanism. In highly dilute solutions, such as at concentrations below the micromolar level, molecular collisions are primarily governed by diffusion. Under these conditions, the apparent reaction order deviates from the stoichiometric expectation because reactant molecules require additional time to traverse longer distances before encountering one another. This behavior can be described by Fick's laws of diffusion and is consistent with fractal reaction kinetics, which yield fractional reaction orders. The rate equation of a reaction with an assumed multi-step mechanism can often be derived theoretically using quasi-steady state assumptions from the underlying elementary reactions, and compared with the experimental rate equation as a test of the assumed mechanism. The equation may involve a fractional order, and may depend on the concentration of an intermediate species. A reaction can also have an undefined reaction order with respect to a reactant if the rate is not simply proportional to some power of the concentration of that reactant; for example, one cannot talk about reaction order in the rate equation for a bimolecular reaction between adsorbed molecules:

v 0 = k K 1 K 2 C A C B ( 1 + K 1 C A + K 2 C B ) 2 . {\displaystyle v_{0}=k{\frac {K_{1}K_{2}C_{A}C_{B}}{(1+K_{1}C_{A}+K_{2}C_{B})^{2}}}.}

Definition

Consider a typical chemical reaction in which two reactants A and B combine to form a product C:

… excerpt ends here. Continue reading the full article.

Illustrations

Rate equation: Time course of two first order, competitive reactions with differing rate constants.
Time course of two first order, competitive reactions with differing rate constants.

Worked examples

Example 1 — a first encounter with Rate equation

Start with the simplest possible case. Write down what Rate equation claims or describes in one sentence, then invent the smallest concrete situation in which that sentence is true. In chemistry, the smallest case is usually a single object, a single equation or a single measurement. Check that every symbol or term in your sentence has a meaning in that case.

Example 2 — changing one variable

Take the situation from Example 1 and change exactly one quantity: double it, halve it, or set it to zero. Predict what should happen to Rate equation before you calculate. Comparing your prediction with the result is the fastest way to find out whether you understand the idea or only the words.

Example 3 — an exam-style question

Typical questions about Rate equation ask you to (a) state it precisely, (b) apply it to given data, and (c) explain a limitation. Practise writing all three answers in under five minutes; the third part is what separates a full-mark answer from an average one.

Applications of Rate equation

In research
Rate equation appears in chemistry research whenever the underlying quantities have to be modelled precisely. Papers usually cite it as a starting assumption and then explore where it breaks down.
In technology and industry
Engineering practice reuses Rate equation in design rules, simulations and safety margins. Knowing the idea lets you read a specification sheet and understand why the numbers look the way they do.
In the classroom
Rate equation is common in secondary-school and first-year university syllabi. It links to neighbouring topics Chemical kinetics, Chemical reaction engineering, so understanding it makes those chapters shorter.
In everyday life
Look for Rate equation outside the textbook — in sport, cooking, traffic, electronics or the sky above you. An example you found yourself is remembered far longer than one you were given.

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How to study Rate equation in 20 minutes

  1. Read the reference excerpt below once, without taking notes.
  2. Close the page and write down what Rate equation means in your own words.
  3. Compare your version with the excerpt and mark what you missed.
  4. Work through the three examples above with pen and paper.
  5. Explain Rate equation out loud to somebody else — or to Teacher Smith in the lgStudy chat.

Frequently asked questions

What is Rate equation in simple terms?

In chemistry, the rate equation (also known as the rate law or empirical differential rate equation) is an empirical differential mathematical expression for the reaction rate of a given reaction in terms of concentrations of chemical species and constant parameters (normally rate coefficients and…

Why does Rate equation matter?

Because it connects several chemistry ideas at once: it gives you a definition you can apply, a quantity you can calculate, and a way to check whether a result is plausible.

How should I study Rate equation?

Read the excerpt, restate it from memory, then work through the examples and applications listed on this page. The five-step study plan above takes about twenty minutes.

What does this page cover?

It gives you a compact reference excerpt plus original lgStudy explanations, examples, applications and study material on Rate equation.

Tags

  • Chemical kinetics
  • Chemical reaction engineering

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