In elementary algebra, root rationalisation (or rationalization) is a process by which radicals in the denominator of an algebraic fraction are eliminated. If the denominator is a monomial in some radical, say a x n k , {\displaystyle a{\sqrt[{n}]{x}}^{k},} with k < n, rationalisation consists of multiplying the numerator and the denominator by x n n − k {\displaystyle {\sqrt[{n}]{x}}^{n-k}} , and replacing x n n {\displaystyle {\sqrt[{n}]{x}}^{n}} by x (this is allowed, as, by definition, a nth root of x is a number that has x as its nth power). If k ≥ n, one writes k = qn + r with 0 ≤ r < n (Euclidean division), and x n k = x q x n r ; {\displaystyle {\sqrt[{n}]{x}}^{k}=x^{q}{\sqrt[{n}]{x}}^{r};} then one proceeds as above by multiplying by x n n − r . {\displaystyle {\sqrt[{n}]{x}}^{n-r}.}
If the denominator is linear in some square root, say a + b x , {\displaystyle a+b{\sqrt {x}},} rationalisation consists of multiplying the numerator and the denominator by the conjugate a − b x , {\displaystyle a-b{\sqrt {x}},} and expanding the product in the denominator. This technique may be extended to any algebraic denominator, by multiplying the numerator and the denominator by all algebraic conjugates of the denominator, and expanding the new denominator into the norm of the old denominator. However, except in special cases, the resulting fractions may have huge numerators and denominators, and, therefore, the technique is generally used only in the above elementary cases.
Rationalisation of a monomial square root and cube root For the fundamental technique, the numerator and denominator must be multiplied by the same factor. Example 1:
10 5 {\displaystyle {\frac {10}{\sqrt {5}}}}
To rationalise this kind of expression, bring in the factor 5 {\displaystyle {\sqrt {5}}} :
10 5 = 10 5 ⋅ 5 5 = 10 5 ( 5 ) 2 {\displaystyle {\frac {10}{\sqrt {5}}}={\frac {10}{\sqrt {5}}}\cdot {\frac {\sqrt {5}}{\sqrt {5}}}={\frac {10{\sqrt {5}}}{\left({\sqrt {5}}\right)^{2}}}}
The square root disappears from the denominator, because ( 5 ) 2 = 5 {\displaystyle \left({\sqrt {5}}\right)^{2}=5} by definition of a square root:
10 5 ( 5 ) 2 = 10 5 5 = 2 5 , {\displaystyle {\frac {10{\sqrt {5}}}{\left({\sqrt {5}}\right)^{2}}}={\frac {10{\sqrt {5}}}{5}}=2{\sqrt {5}},}
which is the result of the rationalisation. Example 2:
10 a 3 {\displaystyle {\frac {10}{\sqrt[{3}]{a}}}}
To rationalise this radical, bring in the factor a 3 2 {\displaystyle {\sqrt[{3}]{a}}^{2}} :
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