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Scott's trick

Scott's trick is a science topic covered in the lgStudy science library. This page brings together a partial reference excerpt, illustrations, worked examples, real-world applications and a short study plan, so you can understand Scott's trick rather than just read about it. In short: In set theory, Scott's trick is a method for giving a definition of equivalence classes for equivalence relations on a proper class (Jech 2003:65) by referring to levels of the cumulative hierarchy. The method relies on the axiom of regularity but not on the axiom of choice.

Key takeaways

  • Scott's trick belongs to science; place it in that map before memorising details.
  • Learn the definition first, then one example that makes the definition concrete.
  • Connect Scott's trick to a quantity you can measure, compute or draw — that is where exam questions come from.
  • Reproduce the core statement of Scott's trick from memory before moving on to harder problems.

Reference excerpt

In set theory, Scott's trick is a method for giving a definition of equivalence classes for equivalence relations on a proper class (Jech 2003:65) by referring to levels of the cumulative hierarchy. The method relies on the axiom of regularity but not on the axiom of choice. It can be used to define representatives for ordinal numbers in ZF, Zermelo–Fraenkel set theory without the axiom of choice (Forster 2003:182). The method was introduced by Dana Scott (1955). Beyond the problem of defining set representatives for ordinal numbers, Scott's trick can be used to obtain representatives for cardinal numbers and more generally for isomorphism types, for example, order types of linearly ordered sets (Jech 2003:65). It is credited to be indispensable (even in the presence of the axiom of choice) when taking ultrapowers of proper classes in model theory. (Kanamori 1994:47)

Application to cardinalities The use of Scott's trick for cardinal numbers shows how the method is typically employed. The initial definition of a cardinal number is an equivalence class of sets, where two sets are equivalent if there is a bijection between them. The difficulty is that almost every equivalence class of this relation is a proper class, and so the equivalence classes themselves cannot be directly manipulated in set theories, such as Zermelo–Fraenkel set theory, that only deal with sets. It is often desirable in the context of set theory to have sets that are representatives for the equivalence classes. These sets are then taken to "be" cardinal numbers, by definition. In Zermelo–Fraenkel set theory with the axiom of choice, one way of assigning representatives to cardinal numbers is to associate each cardinal number with the least ordinal number of the same cardinality. These special ordinals are the ℵ numbers. But if the axiom of choice is not assumed, for some cardinal numbers it may not be possible to find such an ordinal number, and thus the cardinal numbers of those sets have no ordinal number as representatives. Scott's trick assigns representatives differently, using the fact that for every set A {\displaystyle A} there is a least rank V α {\displaystyle V_{\alpha }} in the cumulative hierarchy when some set of the same cardinality as A {\displaystyle A} appears. Thus one may define the representative of the cardinal number of A {\displaystyle A} to be the set of all sets of rank V α {\displaystyle V_{\alpha }} that have the same cardinality as A {\displaystyle A} . This definition assigns a representative to every cardinal number even when not every set can be well-ordered (an assumption equivalent to the axiom of choice). It can be carried out in Zermelo–Fraenkel set theory, without using the axiom of choice, but making essential use of the axiom of regularity.

Scott's trick in general Let ∼ {\displaystyle \sim } be an equivalence relation of sets. Let a {\displaystyle a} be a set and [ a ] {\displaystyle [a]} its equivalence class with respect to ∼ {\displaystyle \sim } . If V ∩ [ a ] {\displaystyle V\cap [a]} is non-empty, we can define a set, which represents [ a ] {\displaystyle [a]} , even if [ a ] {\displaystyle [a]} is a proper class. Namely, there exists a least ordinal α {\displaystyle \alpha } , such that V α ∩ [ a ] {\displaystyle V_{\alpha }\cap [a]} is non-empty. This intersection is a set, so we can take it as the representative of [ a ] {\displaystyle [a]} . We didn't use regularity for this construction. The axiom of regularity is equivalent to a ∈ V {\displaystyle a\in V} for all sets a {\displaystyle a} (see Regularity, the cumulative hierarchy and types). So in particular, if we assume the axiom of regularity, then V ∩ [ a ] {\displaystyle V\cap [a]} will be non-empty for all sets a {\displaystyle a} and equivalence relations ∼ {\displaystyle \sim } , since a ∈ V ∩ [ a ] {\displaystyle a\in V\cap [a]} . To summarize: given the axiom of regularity, we can find representatives of every equivalence class, for any equivalence relation.

References Thomas Forster (2003), Logic, Induction and Sets, Cambridge University Press. ISBN 0-521-53361-9 Thomas Jech, Set Theory, 3rd millennium (revised) ed., 2003, Springer Monographs in Mathematics, Springer, ISBN 3-540-44085-2 Akihiro Kanamori: The Higher Infinite. Large Cardinals in Set Theory from their Beginnings., Perspectives in Mathematical Logic. Springer-Verlag, Berlin, 1994. xxiv+536 pp. Scott, Dana (1955), "Definitions by abstraction in axiomatic set theory" (PDF), Bulletin of the American Mathematical Society, 61 (5): 442, doi:10.1090/S0002-9904-1955-09941-5

Worked examples

Example 1 — a first encounter with Scott's trick

Start with the simplest possible case. Write down what Scott's trick claims or describes in one sentence, then invent the smallest concrete situation in which that sentence is true. In science, the smallest case is usually a single object, a single equation or a single measurement. Check that every symbol or term in your sentence has a meaning in that case.

Example 2 — changing one variable

Take the situation from Example 1 and change exactly one quantity: double it, halve it, or set it to zero. Predict what should happen to Scott's trick before you calculate. Comparing your prediction with the result is the fastest way to find out whether you understand the idea or only the words.

Example 3 — an exam-style question

Typical questions about Scott's trick ask you to (a) state it precisely, (b) apply it to given data, and (c) explain a limitation. Practise writing all three answers in under five minutes; the third part is what separates a full-mark answer from an average one.

Applications of Scott's trick

In research
Scott's trick appears in science research whenever the underlying quantities have to be modelled precisely. Papers usually cite it as a starting assumption and then explore where it breaks down.
In technology and industry
Engineering practice reuses Scott's trick in design rules, simulations and safety margins. Knowing the idea lets you read a specification sheet and understand why the numbers look the way they do.
In the classroom
Scott's trick is common in secondary-school and first-year university syllabi. It links to neighbouring topics Set theory, so understanding it makes those chapters shorter.
In everyday life
Look for Scott's trick outside the textbook — in sport, cooking, traffic, electronics or the sky above you. An example you found yourself is remembered far longer than one you were given.

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How to study Scott's trick in 20 minutes

  1. Read the reference excerpt below once, without taking notes.
  2. Close the page and write down what Scott's trick means in your own words.
  3. Compare your version with the excerpt and mark what you missed.
  4. Work through the three examples above with pen and paper.
  5. Explain Scott's trick out loud to somebody else — or to Teacher Smith in the lgStudy chat.

Frequently asked questions

What is Scott's trick in simple terms?

In set theory, Scott's trick is a method for giving a definition of equivalence classes for equivalence relations on a proper class (Jech 2003:65) by referring to levels of the cumulative hierarchy. The method relies on the axiom of regularity but not on the axiom of choice.

Why does Scott's trick matter?

Because it connects several science ideas at once: it gives you a definition you can apply, a quantity you can calculate, and a way to check whether a result is plausible.

How should I study Scott's trick?

Read the excerpt, restate it from memory, then work through the examples and applications listed on this page. The five-step study plan above takes about twenty minutes.

What does this page cover?

It gives you a compact reference excerpt plus original lgStudy explanations, examples, applications and study material on Scott's trick.

Tags

  • Set theory

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