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Sedimentation equilibrium

Sedimentation equilibrium is a chemistry topic covered in the lgStudy science library. This page brings together a partial reference excerpt, illustrations, worked examples, real-world applications and a short study plan, so you can understand Sedimentation equilibrium rather than just read about it. In short: Sedimentation equilibrium in a suspension of different particles, such as molecules, exists when the rate of transport of each material in any one direction due to sedimentation equals the rate of transport in the opposite direction due to diffusion. Sedimentation is due to an external force, such as gravity or centrifugal force in a centrifuge.

Key takeaways

  • Sedimentation equilibrium belongs to chemistry; place it in that map before memorising details.
  • Learn the definition first, then one example that makes the definition concrete.
  • Connect Sedimentation equilibrium to a quantity you can measure, compute or draw — that is where exam questions come from.
  • Reproduce the core statement of Sedimentation equilibrium from memory before moving on to harder problems.

Reference excerpt

Sedimentation equilibrium in a suspension of different particles, such as molecules, exists when the rate of transport of each material in any one direction due to sedimentation equals the rate of transport in the opposite direction due to diffusion. Sedimentation is due to an external force, such as gravity or centrifugal force in a centrifuge. It was discovered for colloids by Jean Baptiste Perrin for which he received the Nobel Prize in Physics in 1926.

Colloid In a colloid, the colloidal particles are said to be in sedimentation equilibrium if the rate of sedimentation is equal to the rate of movement from Brownian motion. For dilute colloids, this is described using the Laplace-Perrin distribution law:

Φ ( z ) = Φ 0 exp ⁡ ( − m ∗ g k B T z ) = Φ 0 e − z / l g {\displaystyle \Phi (z)=\Phi _{0}\exp {\biggl (}-{\frac {m^{*}g}{k_{B}T}}z{\biggr )}=\Phi _{0}e^{-z/l_{g}}}

where

Φ ( z ) {\displaystyle \Phi (z)} is the colloidal particle volume fraction as a function of vertical distance z {\displaystyle z} above reference point z = 0 {\displaystyle z=0} ,

Φ 0 {\displaystyle \Phi _{0}} is the colloidal particle volume fraction at reference point z = 0 {\displaystyle z=0} ,

m ∗ {\displaystyle m^{*}} is the buoyant mass of the colloidal particles,

g {\displaystyle g} is the standard acceleration due to gravity,

k B {\displaystyle k_{B}} is the Boltzmann constant,

T {\displaystyle T} is the absolute temperature, and l g {\displaystyle l_{g}} is the sedimentation length. The buoyant mass is calculated using m ∗ = Δ ρ V P = 4 3 π Δ ρ R 3 {\displaystyle m^{*}=\Delta \rho V_{P}={\frac {4}{3}}\pi \Delta \rho R^{3}}

where Δ ρ {\displaystyle \Delta \rho } is the difference in mass density between the colloidal particles and the suspension medium, and V P {\displaystyle V_{P}} is the colloidal particle volume found using the volume of a sphere ( R {\displaystyle R} is the radius of the colloidal particle).

Sedimentation length The Laplace-Perrin distribution law can be rearranged to give the sedimentation length l g {\displaystyle l_{g}} . The sedimentation length describes the probability of finding a colloidal particle at a height z {\displaystyle z} above the point of reference z = 0 {\displaystyle z=0} . At the length l g {\displaystyle l_{g}} above the reference point, the concentration of colloidal particles decreases by a factor of e {\displaystyle e} .

l g = k B T m ∗ g {\displaystyle l_{g}={\frac {k_{B}T}{m^{*}g}}}

If the sedimentation length is much greater than the diameter d {\displaystyle d} of the colloidal particles ( l g >> d {\displaystyle l_{g}>>d} ), the particles can diffuse a distance greater than this diameter, and the substance remains a suspension. However, if the sedimentation length is less than the diameter ( l g < d {\displaystyle l_{g}<d} ), the particles can only diffuse by a much shorter length. They will sediment under the influence of gravity and settle to the bottom of the container. The substance can no longer be considered a colloidal suspension. It may become a colloidal suspension again if an action to undertaken to suspend the colloidal particles again, such as stirring the colloid.

… excerpt ends here. Continue reading the full article.

Worked examples

Example 1 — a first encounter with Sedimentation equilibrium

Start with the simplest possible case. Write down what Sedimentation equilibrium claims or describes in one sentence, then invent the smallest concrete situation in which that sentence is true. In chemistry, the smallest case is usually a single object, a single equation or a single measurement. Check that every symbol or term in your sentence has a meaning in that case.

Example 2 — changing one variable

Take the situation from Example 1 and change exactly one quantity: double it, halve it, or set it to zero. Predict what should happen to Sedimentation equilibrium before you calculate. Comparing your prediction with the result is the fastest way to find out whether you understand the idea or only the words.

Example 3 — an exam-style question

Typical questions about Sedimentation equilibrium ask you to (a) state it precisely, (b) apply it to given data, and (c) explain a limitation. Practise writing all three answers in under five minutes; the third part is what separates a full-mark answer from an average one.

Applications of Sedimentation equilibrium

In research
Sedimentation equilibrium appears in chemistry research whenever the underlying quantities have to be modelled precisely. Papers usually cite it as a starting assumption and then explore where it breaks down.
In technology and industry
Engineering practice reuses Sedimentation equilibrium in design rules, simulations and safety margins. Knowing the idea lets you read a specification sheet and understand why the numbers look the way they do.
In the classroom
Sedimentation equilibrium is common in secondary-school and first-year university syllabi. It links to neighbouring topics Biochemistry methods, so understanding it makes those chapters shorter.
In everyday life
Look for Sedimentation equilibrium outside the textbook — in sport, cooking, traffic, electronics or the sky above you. An example you found yourself is remembered far longer than one you were given.
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How to study Sedimentation equilibrium in 20 minutes

  1. Read the reference excerpt below once, without taking notes.
  2. Close the page and write down what Sedimentation equilibrium means in your own words.
  3. Compare your version with the excerpt and mark what you missed.
  4. Work through the three examples above with pen and paper.
  5. Explain Sedimentation equilibrium out loud to somebody else — or to Teacher Smith in the lgStudy chat.

Frequently asked questions

What is Sedimentation equilibrium in simple terms?

Sedimentation equilibrium in a suspension of different particles, such as molecules, exists when the rate of transport of each material in any one direction due to sedimentation equals the rate of transport in the opposite direction due to diffusion. Sedimentation is due to an external force, such…

Why does Sedimentation equilibrium matter?

Because it connects several chemistry ideas at once: it gives you a definition you can apply, a quantity you can calculate, and a way to check whether a result is plausible.

How should I study Sedimentation equilibrium?

Read the excerpt, restate it from memory, then work through the examples and applications listed on this page. The five-step study plan above takes about twenty minutes.

What does this page cover?

It gives you a compact reference excerpt plus original lgStudy explanations, examples, applications and study material on Sedimentation equilibrium.

Tags

  • Biochemistry methods

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