The state-transition equation is defined as the solution of the linear homogeneous state equation. The linear time-invariant state equation given by
d x ( t ) d t = A x ( t ) + B u ( t ) + E w ( t ) , {\displaystyle {\frac {d\mathbf {x} (t)}{dt}}=\mathbf {Ax} (t)+\mathbf {Bu} (t)+\mathbf {Ew} (t),}
with state vector x, control vector u, vector w of additive disturbances, and fixed matrices A, B, E can be solved by using either the classical method of solving linear differential equations or the Laplace transform method. The Laplace transform solution is presented in the following equations. The Laplace transform of the above equation yields
s X ( s ) − x ( 0 ) = A X ( s ) + B U ( s ) + E W ( s ) {\displaystyle s\mathbf {X} (s)-\mathbf {x} (0)=\mathbf {AX} (s)+\mathbf {BU} (s)+\mathbf {EW} (s)}
where x(0) denotes initial-state vector evaluated at t = 0. Solving for X(s) gives
X ( s ) = ( s I − A ) − 1 x ( 0 ) + ( s I − A ) − 1 [ B U ( s ) + E W ( s ) ] . {\displaystyle \mathbf {X} (s)=(s\mathbf {I} -\mathbf {A} )^{-1}\mathbf {x} (0)+(s\mathbf {I} -\mathbf {A} )^{-1}[\mathbf {BU} (s)+\mathbf {EW} (s)].}
So, the state-transition equation can be obtained by taking inverse Laplace transform as
x ( t ) = L − 1 { ( s I − A ) − 1 } x ( 0 ) + L − 1 { ( s I − A ) − 1 [ B U ( s ) + E W ( s ) ] } = Φ ( t ) x ( 0 ) + ∫ 0 t Φ ( t − τ ) [ B u ( τ ) + E w ( τ ) ] d t {\displaystyle {\begin{aligned}x(t)&={\mathcal {L}}^{-1}{\Bigl \{}(s\mathbf {I} -\mathbf {A} )^{-1}{\Bigr \}}\mathbf {x} (0)+{\mathcal {L}}^{-1}{\Bigl \{}(s\mathbf {I} -\mathbf {A} )^{-1}[\mathbf {BU} (s)+\mathbf {EW} (s)]{\Bigr \}}\\&=\mathbf {\Phi } (t)\mathbf {x} (0)+\int _{0}^{t}\mathbf {\Phi } (t-\tau )[\mathbf {Bu} (\tau )+\mathbf {Ew} (\tau )]dt\end{aligned}}}
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