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Stokes' paradox

Stokes' paradox is a mathematics topic covered in the lgStudy science library. This page brings together a partial reference excerpt, illustrations, worked examples, real-world applications and a short study plan, so you can understand Stokes' paradox rather than just read about it. In short: In the science of fluid flow, Stokes' paradox is the phenomenon that there can be no creeping flow of a fluid around a disk in two dimensions; or, equivalently, the fact there is no non-trivial steady-state solution for the Stokes equations around an infinitely long cylinder. This is opposed to the 3-dimensional case, where Stokes' method provides a solution to the problem of flow around a sphere.

Key takeaways

  • Stokes' paradox belongs to mathematics; place it in that map before memorising details.
  • Learn the definition first, then one example that makes the definition concrete.
  • Connect Stokes' paradox to a quantity you can measure, compute or draw — that is where exam questions come from.
  • Reproduce the core statement of Stokes' paradox from memory before moving on to harder problems.

Reference excerpt

In the science of fluid flow, Stokes' paradox is the phenomenon that there can be no creeping flow of a fluid around a disk in two dimensions; or, equivalently, the fact there is no non-trivial steady-state solution for the Stokes equations around an infinitely long cylinder. This is opposed to the 3-dimensional case, where Stokes' method provides a solution to the problem of flow around a sphere. Stokes' paradox was resolved by Carl Wilhelm Oseen in 1910, by introducing the Oseen equations which improve upon the Stokes equations – by adding convective acceleration.

Derivation The velocity vector u {\displaystyle \mathbf {u} } of the fluid may be written in terms of the stream function ψ {\displaystyle \psi } as

u = ( ∂ ψ ∂ y , − ∂ ψ ∂ x ) . {\displaystyle \mathbf {u} =\left({\frac {\partial \psi }{\partial y}},-{\frac {\partial \psi }{\partial x}}\right).}

The stream function in a Stokes flow problem, ψ {\displaystyle \psi } satisfies the biharmonic equation. By regarding the ( x , y ) {\displaystyle (x,y)} -plane as the complex plane, the problem may be dealt with using methods of complex analysis. In this approach, ψ {\displaystyle \psi } is either the real or imaginary part of

z ¯ f ( z ) + g ( z ) {\displaystyle {\bar {z}}f(z)+g(z)} . Here z = x + i y {\displaystyle z=x+iy} , where i {\displaystyle i} is the imaginary unit, z ¯ = x − i y {\displaystyle {\bar {z}}=x-iy} , and f ( z ) , g ( z ) {\displaystyle f(z),g(z)} are holomorphic functions outside of the disk. We will take the real part without loss of generality. Now the function u {\displaystyle u} , defined by u = u x + i u y {\displaystyle u=u_{x}+iu_{y}} is introduced. u {\displaystyle u} can be written as u = − 2 i ∂ ψ ∂ z ¯ {\displaystyle u=-2i{\frac {\partial \psi }{\partial {\bar {z}}}}} , or 1 2 i u = ∂ ψ ∂ z ¯ {\displaystyle {\frac {1}{2}}iu={\frac {\partial \psi }{\partial {\bar {z}}}}} (using the Wirtinger derivatives). This is calculated to be equal to

1 2 i u = f ( z ) + z f ′ ¯ ( z ) + g ′ ¯ ( z ) . {\displaystyle {\frac {1}{2}}iu=f(z)+z{\bar {f\prime }}(z)+{\bar {g\prime }}(z).}

Without loss of generality, the disk may be assumed to be the unit disk, consisting of all complex numbers z of absolute value smaller or equal to 1. The boundary conditions are:

lim z → ∞ u = 1 , {\displaystyle \lim _{z\to \infty }u=1,}

u = 0 , {\displaystyle u=0,}

whenever | z | = 1 {\displaystyle |z|=1} , and by representing the functions f , g {\displaystyle f,g} as Laurent series:

… excerpt ends here. Continue reading the full article.

Worked examples

Example 1 — a first encounter with Stokes' paradox

Start with the simplest possible case. Write down what Stokes' paradox claims or describes in one sentence, then invent the smallest concrete situation in which that sentence is true. In mathematics, the smallest case is usually a single object, a single equation or a single measurement. Check that every symbol or term in your sentence has a meaning in that case.

Example 2 — changing one variable

Take the situation from Example 1 and change exactly one quantity: double it, halve it, or set it to zero. Predict what should happen to Stokes' paradox before you calculate. Comparing your prediction with the result is the fastest way to find out whether you understand the idea or only the words.

Example 3 — an exam-style question

Typical questions about Stokes' paradox ask you to (a) state it precisely, (b) apply it to given data, and (c) explain a limitation. Practise writing all three answers in under five minutes; the third part is what separates a full-mark answer from an average one.

Applications of Stokes' paradox

In research
Stokes' paradox appears in mathematics research whenever the underlying quantities have to be modelled precisely. Papers usually cite it as a starting assumption and then explore where it breaks down.
In technology and industry
Engineering practice reuses Stokes' paradox in design rules, simulations and safety margins. Knowing the idea lets you read a specification sheet and understand why the numbers look the way they do.
In the classroom
Stokes' paradox is common in secondary-school and first-year university syllabi. It links to neighbouring topics Equations of fluid dynamics, Fluid dynamics, so understanding it makes those chapters shorter.
In everyday life
Look for Stokes' paradox outside the textbook — in sport, cooking, traffic, electronics or the sky above you. An example you found yourself is remembered far longer than one you were given.
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How to study Stokes' paradox in 20 minutes

  1. Read the reference excerpt below once, without taking notes.
  2. Close the page and write down what Stokes' paradox means in your own words.
  3. Compare your version with the excerpt and mark what you missed.
  4. Work through the three examples above with pen and paper.
  5. Explain Stokes' paradox out loud to somebody else — or to Teacher Smith in the lgStudy chat.

Frequently asked questions

What is Stokes' paradox in simple terms?

In the science of fluid flow, Stokes' paradox is the phenomenon that there can be no creeping flow of a fluid around a disk in two dimensions; or, equivalently, the fact there is no non-trivial steady-state solution for the Stokes equations around an infinitely long cylinder. This is opposed to the…

Why does Stokes' paradox matter?

Because it connects several mathematics ideas at once: it gives you a definition you can apply, a quantity you can calculate, and a way to check whether a result is plausible.

How should I study Stokes' paradox?

Read the excerpt, restate it from memory, then work through the examples and applications listed on this page. The five-step study plan above takes about twenty minutes.

What does this page cover?

It gives you a compact reference excerpt plus original lgStudy explanations, examples, applications and study material on Stokes' paradox.

Tags

  • Equations of fluid dynamics
  • Fluid dynamics

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