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Temperature dependence of viscosity

Temperature dependence of viscosity is a science topic covered in the lgStudy science library. This page brings together a partial reference excerpt, illustrations, worked examples, real-world applications and a short study plan, so you can understand Temperature dependence of viscosity rather than just read about it. In short: Viscosity depends strongly on temperature. In liquids it usually decreases with increasing temperature, whereas, in most gases, viscosity increases with increasing temperature.

Key takeaways

  • Temperature dependence of viscosity belongs to science; place it in that map before memorising details.
  • Learn the definition first, then one example that makes the definition concrete.
  • Connect Temperature dependence of viscosity to a quantity you can measure, compute or draw — that is where exam questions come from.
  • Reproduce the core statement of Temperature dependence of viscosity from memory before moving on to harder problems.

Reference excerpt

Viscosity depends strongly on temperature. In liquids it usually decreases with increasing temperature, whereas, in most gases, viscosity increases with increasing temperature. This article discusses several models of this dependence, ranging from rigorous first-principles calculations for monatomic gases, to empirical correlations for liquids. Understanding the temperature dependence of viscosity is important for many applications, for instance engineering lubricants that perform well under varying temperature conditions (such as in a car engine), since the performance of a lubricant depends in part on its viscosity. Engineering problems of this type fall under the purview of tribology. Here dynamic viscosity is denoted by μ {\displaystyle \mu } and kinematic viscosity by ν {\displaystyle \nu } . The formulas given are valid only for an absolute temperature scale; therefore, unless stated otherwise temperatures are in kelvins.

Physical causes Viscosity in gases arises from molecules traversing layers of flow and transferring momentum between layers. This transfer of momentum can be thought of as a frictional force between layers of flow. Since the momentum transfer is caused by free motion of gas molecules between collisions, increasing thermal agitation of the molecules results in a larger viscosity. Hence, gaseous viscosity increases with temperature. In liquids, viscous forces are caused by molecules exerting attractive forces on each other across layers of flow. Increasing temperature results in a decrease in viscosity because a larger temperature means particles have greater thermal energy and are more easily able to overcome the attractive forces binding them together. An everyday example of this viscosity decrease is cooking oil moving more fluidly in a hot frying pan than in a cold one.

Gases

The kinetic theory of gases allows accurate calculation of the temperature-variation of gaseous viscosity. The theoretical basis of the kinetic theory is given by the Boltzmann equation and Chapman–Enskog theory, which allow accurate statistical modeling of molecular trajectories. In particular, given a model for intermolecular interactions, one can calculate with high precision the viscosity of monatomic and other simple gases (for more complex gases, such as those composed of polar molecules, additional assumptions must be introduced which reduce the accuracy of the theory). The viscosity predictions for four molecular models are discussed below. The predictions of the first three models (hard-sphere, power-law, and Sutherland) can be simply expressed in terms of elementary functions. The Lennard–Jones model predicts a more complicated T {\displaystyle T} -dependence, but is more accurate than the other three models and is widely used in engineering practice.

Hard-sphere kinetic theory If one models gas molecules as elastic hard spheres (with mass m {\displaystyle m} and diameter σ {\displaystyle \sigma } ), then elementary kinetic theory predicts that viscosity increases with the square root of absolute temperature T {\displaystyle T} :

μ = 1.016 ⋅ 5 16 σ 2 ( k B m T π ) 1 / 2 {\displaystyle \mu =1.016\cdot {\frac {5}{16\sigma ^{2}}}\left({\frac {k_{\rm {B}}mT}{\pi }}\right)^{1/2}}

where k B {\displaystyle k_{\text{B}}} is the Boltzmann constant. While correctly predicting the increase of gaseous viscosity with temperature, the T 1 / 2 {\displaystyle T^{1/2}} trend is not accurate; the viscosity of real gases increases more rapidly than this. Capturing the actual T {\displaystyle T} dependence requires more realistic models of molecular interactions, in particular the inclusion of attractive interactions which are present in all real gases.

Power-law force A modest improvement over the hard-sphere model is a repulsive inverse power-law force, where the force between two molecules separated by distance r {\displaystyle r} is proportional to 1 / r α {\displaystyle 1/r^{\alpha }} , where α {\displaystyle \alpha } is an empirical parameter. This is not a realistic model for real-world gases (except possibly at high temperature), but provides a simple illustration of how changing intermolecular interactions affects the predicted temperature dependence of viscosity. In this case, kinetic theory predicts an increase in temperature as T s {\displaystyle T^{s}} , where s = ( 1 / 2 ) + 2 / ( α − 1 ) {\displaystyle s=(1/2)+2/(\alpha -1)} . More precisely, if μ ′ {\displaystyle \mu '} is the known viscosity at temperature T ′ {\displaystyle T'} , then

… excerpt ends here. Continue reading the full article.

Worked examples

Example 1 — a first encounter with Temperature dependence of viscosity

Start with the simplest possible case. Write down what Temperature dependence of viscosity claims or describes in one sentence, then invent the smallest concrete situation in which that sentence is true. In science, the smallest case is usually a single object, a single equation or a single measurement. Check that every symbol or term in your sentence has a meaning in that case.

Example 2 — changing one variable

Take the situation from Example 1 and change exactly one quantity: double it, halve it, or set it to zero. Predict what should happen to Temperature dependence of viscosity before you calculate. Comparing your prediction with the result is the fastest way to find out whether you understand the idea or only the words.

Example 3 — an exam-style question

Typical questions about Temperature dependence of viscosity ask you to (a) state it precisely, (b) apply it to given data, and (c) explain a limitation. Practise writing all three answers in under five minutes; the third part is what separates a full-mark answer from an average one.

Applications of Temperature dependence of viscosity

In research
Temperature dependence of viscosity appears in science research whenever the underlying quantities have to be modelled precisely. Papers usually cite it as a starting assumption and then explore where it breaks down.
In technology and industry
Engineering practice reuses Temperature dependence of viscosity in design rules, simulations and safety margins. Knowing the idea lets you read a specification sheet and understand why the numbers look the way they do.
In the classroom
Temperature dependence of viscosity is common in secondary-school and first-year university syllabi. It links to neighbouring topics Non-Newtonian fluids, so understanding it makes those chapters shorter.
In everyday life
Look for Temperature dependence of viscosity outside the textbook — in sport, cooking, traffic, electronics or the sky above you. An example you found yourself is remembered far longer than one you were given.
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How to study Temperature dependence of viscosity in 20 minutes

  1. Read the reference excerpt below once, without taking notes.
  2. Close the page and write down what Temperature dependence of viscosity means in your own words.
  3. Compare your version with the excerpt and mark what you missed.
  4. Work through the three examples above with pen and paper.
  5. Explain Temperature dependence of viscosity out loud to somebody else — or to Teacher Smith in the lgStudy chat.

Frequently asked questions

What is Temperature dependence of viscosity in simple terms?

Viscosity depends strongly on temperature. In liquids it usually decreases with increasing temperature, whereas, in most gases, viscosity increases with increasing temperature.

Why does Temperature dependence of viscosity matter?

Because it connects several science ideas at once: it gives you a definition you can apply, a quantity you can calculate, and a way to check whether a result is plausible.

How should I study Temperature dependence of viscosity?

Read the excerpt, restate it from memory, then work through the examples and applications listed on this page. The five-step study plan above takes about twenty minutes.

What does this page cover?

It gives you a compact reference excerpt plus original lgStudy explanations, examples, applications and study material on Temperature dependence of viscosity.

Tags

  • Non-Newtonian fluids

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