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Vitali covering lemma

Vitali covering lemma is a science topic covered in the lgStudy science library. This page brings together a partial reference excerpt, illustrations, worked examples, real-world applications and a short study plan, so you can understand Vitali covering lemma rather than just read about it. In short: In mathematics, the Vitali covering lemma is a combinatorial and geometric result commonly used in measure theory of Euclidean spaces. This lemma is an intermediate step, of independent interest, in the proof of the Vitali covering theorem.

Vitali covering lemma — main illustration
Vitali covering lemma — illustration

Key takeaways

  • Vitali covering lemma belongs to science; place it in that map before memorising details.
  • Learn the definition first, then one example that makes the definition concrete.
  • Connect Vitali covering lemma to a quantity you can measure, compute or draw — that is where exam questions come from.
  • Reproduce the core statement of Vitali covering lemma from memory before moving on to harder problems.

Reference excerpt

In mathematics, the Vitali covering lemma is a combinatorial and geometric result commonly used in measure theory of Euclidean spaces. This lemma is an intermediate step, of independent interest, in the proof of the Vitali covering theorem. The covering theorem is credited to the Italian mathematician Giuseppe Vitali. The theorem states that it is possible to cover, up to a Lebesgue-negligible set, a given subset E of Rd by a disjoint family extracted from a Vitali covering of E.

Vitali covering lemma

There are two basic versions of the lemma, a finite version and an infinite version. Both lemmas can be proved in the general setting of a metric space, typically these results are applied to the special case of the Euclidean space R d {\displaystyle \mathbb {R} ^{d}} . In both theorems we will use the following notation: if B = B ( x , r ) {\textstyle B=B(x,r)} is a ball and c ≥ 0 {\displaystyle c\geq 0} , we will write c B {\displaystyle cB} for the ball B ( x , c r ) {\textstyle B(x,cr)} .

Finite version

Infinite version The following proof is based on (Evans & Gariepy 1992, section 1.5.1). Remarks

In the infinite version, the initial collection of balls can be countable or uncountable. In a separable metric space, any pairwise disjoint collection of balls must be countable. In a non-separable space, the same argument shows a pairwise disjoint subfamily exists, but that family need not be countable. The result may fail if the radii are not bounded: consider the family of all balls centered at 0 in Rd; any disjoint subfamily consists of only one ball B, and 5 B does not contain all the balls in this family. The constant 5 is not optimal. If the scale c−n, c > 1, is used instead of 2−n for defining Fn, the final value is 1 + 2c instead of 5. Any constant larger than 3 gives a correct statement of the lemma, but not 3. Using a finer analysis, when the original collection F is a Vitali covering of a subset E of Rd, one shows that the subcollection G, defined in the above proof, covers E up to a Lebesgue-negligible set.

Applications and method of use An application of the Vitali lemma is in proving the Hardy–Littlewood maximal inequality. As in this proof, the Vitali lemma is frequently used when we are, for instance, considering the d-dimensional Lebesgue measure, λ d {\displaystyle \lambda _{d}} , of a set E ⊂ Rd, which we know is contained in the union of a certain collection of balls { B j : j ∈ J } {\displaystyle \{B_{j}:j\in J\}} , each of which has a measure we can more easily compute, or has a special property one would like to exploit. Hence, if we compute the measure of this union, we will have an upper bound on the measure of E. However, it is difficult to compute the measure of the union of all these balls if they overlap. By the Vitali lemma, we may choose a subcollection { B j : j ∈ J ′ } {\displaystyle \left\{B_{j}:j\in J'\right\}} which is disjoint and such that ⋃ j ∈ J ′ 5 B j ⊃ ⋃ j ∈ J B j ⊃ E {\textstyle \bigcup _{j\in J'}5B_{j}\supset \bigcup _{j\in J}B_{j}\supset E} . Therefore,

λ d ( E ) ≤ λ d ( ⋃ j ∈ J B j ) ≤ λ d ( ⋃ j ∈ J ′ 5 B j ) ≤ ∑ j ∈ J ′ λ d ( 5 B j ) . {\displaystyle \lambda _{d}(E)\leq \lambda _{d}{\biggl (}\bigcup _{j\in J}B_{j}{\biggr )}\leq \lambda _{d}{\biggl (}\bigcup _{j\in J'}5B_{j}{\biggr )}\leq \sum _{j\in J'}\lambda _{d}(5B_{j}).}

Now, since increasing the radius of a d-dimensional ball by a factor of five increases its volume by a factor of 5d, we know that

… excerpt ends here. Continue reading the full article.

Illustrations

Vitali covering lemma: On the top: a collection of balls; the green balls are the disjoint subcollection. On the bottom: the subcollection with three times the radius covers all the balls.
On the top: a collection of balls; the green balls are the disjoint subcollection. On the bottom: the subcollection with three times the radius covers all the balls.
Vitali covering lemma: A given ball 
  
    
      
        
          B
          
            i
          
        
      
    
    {\displaystyle B_{i}}
  
 (colored red) must intersect some selected balls (colored green). Of these, pick the green ball 
  
    
      
        
          B
          
            
              j
              
                k
              
            
          
        
      
    
    {\displaystyle B_{j_{k}}}
  
 with the lowest index 
  
    
      
        k
      
    
    {\displaystyle k}
  
. It must necessarily have radius 
  
    
      
        r
        (
        
          B
          
            
              j
              
                k
              
            
          
        
        )
        ≥
        r
        (
        
          B
          
            i
          
        
        )
      
    
    {\displaystyle r(B_{j_{k}})\geq r(B_{i})}
  
 by construction.
A given ball B i {\displaystyle B_{i}} (colored red) must intersect some selected balls (colored green). Of these, pick the green ball B j k {\displaystyle B_{j_{k}}} with the lowest index k {\displaystyle k} . It must necessarily have radius r ( B j k ) ≥ r ( B i ) {\displaystyle r(B_{j_{k}})\geq r(B_{i})} by construction.

Worked examples

Example 1 — a first encounter with Vitali covering lemma

Start with the simplest possible case. Write down what Vitali covering lemma claims or describes in one sentence, then invent the smallest concrete situation in which that sentence is true. In science, the smallest case is usually a single object, a single equation or a single measurement. Check that every symbol or term in your sentence has a meaning in that case.

Example 2 — changing one variable

Take the situation from Example 1 and change exactly one quantity: double it, halve it, or set it to zero. Predict what should happen to Vitali covering lemma before you calculate. Comparing your prediction with the result is the fastest way to find out whether you understand the idea or only the words.

Example 3 — an exam-style question

Typical questions about Vitali covering lemma ask you to (a) state it precisely, (b) apply it to given data, and (c) explain a limitation. Practise writing all three answers in under five minutes; the third part is what separates a full-mark answer from an average one.

Applications of Vitali covering lemma

In research
Vitali covering lemma appears in science research whenever the underlying quantities have to be modelled precisely. Papers usually cite it as a starting assumption and then explore where it breaks down.
In technology and industry
Engineering practice reuses Vitali covering lemma in design rules, simulations and safety margins. Knowing the idea lets you read a specification sheet and understand why the numbers look the way they do.
In the classroom
Vitali covering lemma is common in secondary-school and first-year university syllabi. It links to neighbouring topics Covering lemmas, Measure theory, Real analysis, so understanding it makes those chapters shorter.
In everyday life
Look for Vitali covering lemma outside the textbook — in sport, cooking, traffic, electronics or the sky above you. An example you found yourself is remembered far longer than one you were given.
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How to study Vitali covering lemma in 20 minutes

  1. Read the reference excerpt below once, without taking notes.
  2. Close the page and write down what Vitali covering lemma means in your own words.
  3. Compare your version with the excerpt and mark what you missed.
  4. Work through the three examples above with pen and paper.
  5. Explain Vitali covering lemma out loud to somebody else — or to Teacher Smith in the lgStudy chat.

Frequently asked questions

What is Vitali covering lemma in simple terms?

In mathematics, the Vitali covering lemma is a combinatorial and geometric result commonly used in measure theory of Euclidean spaces. This lemma is an intermediate step, of independent interest, in the proof of the Vitali covering theorem.

Why does Vitali covering lemma matter?

Because it connects several science ideas at once: it gives you a definition you can apply, a quantity you can calculate, and a way to check whether a result is plausible.

How should I study Vitali covering lemma?

Read the excerpt, restate it from memory, then work through the examples and applications listed on this page. The five-step study plan above takes about twenty minutes.

What does this page cover?

It gives you a compact reference excerpt plus original lgStudy explanations, examples, applications and study material on Vitali covering lemma.

Tags

  • Covering lemmas
  • Measure theory
  • Real analysis

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