In homological algebra, Zeeman's comparison theorem, introduced by Christopher Zeeman, gives conditions for a morphism of spectral sequences to be an isomorphism.
Statement
Illustrative example As an illustration, we sketch the proof of Borel's theorem, which says the cohomology ring of a classifying space is a polynomial ring. First of all, with G as a Lie group and with Q {\displaystyle \mathbb {Q} } as coefficient ring, we have the Serre spectral sequence E 2 p , q {\displaystyle E_{2}^{p,q}} for the fibration G → E G → B G {\displaystyle G\to EG\to BG} . We have: E ∞ ≃ Q {\displaystyle E_{\infty }\simeq \mathbb {Q} } since EG is contractible. We also have a theorem of Hopf stating that H ∗ ( G ; Q ) ≃ Λ ( u 1 , … , u n ) {\displaystyle H^{*}(G;\mathbb {Q} )\simeq \Lambda (u_{1},\dots ,u_{n})} , an exterior algebra generated by finitely many homogeneous elements. Next, we let E ( i ) {\displaystyle E(i)} be the spectral sequence whose second page is E ( i ) 2 = Λ ( x i ) ⊗ Q [ y i ] {\displaystyle E(i)_{2}=\Lambda (x_{i})\otimes \mathbb {Q} [y_{i}]} and whose nontrivial differentials on the r-th page are given by d ( x i ) = y i {\displaystyle d(x_{i})=y_{i}} and the graded Leibniz rule. Let
′ E r = ⊗ i E r ( i ) {\displaystyle {}^{\prime }E_{r}=\otimes _{i}E_{r}(i)} . Since the cohomology commutes with tensor products as we are working over a field,
′ E r {\displaystyle {}^{\prime }E_{r}} is again a spectral sequence such that
′ E ∞ ≃ Q ⊗ ⋯ ⊗ Q ≃ Q {\displaystyle {}^{\prime }E_{\infty }\simeq \mathbb {Q} \otimes \dots \otimes \mathbb {Q} \simeq \mathbb {Q} } . Then we let
f :
′ E r → E r , x i ↦ u i . {\displaystyle f:{}^{\prime }E_{r}\to E_{r},\,x_{i}\mapsto u_{i}.}
Note, by definition, f gives the isomorphism
′ E r 0 , q ≃ E r 0 , q = H q ( G ; Q ) . {\displaystyle {}^{\prime }E_{r}^{0,q}\simeq E_{r}^{0,q}=H^{q}(G;\mathbb {Q} ).} A crucial point is that f is a "ring homomorphism"; this rests on the technical conditions that u i {\displaystyle u_{i}} are "transgressive" (cf. Hatcher for detailed discussion on this matter.) After this technical point is taken care, we conclude: E 2 p , 0 ≃
′ E 2 p , 0 {\displaystyle E_{2}^{p,0}\simeq {}^{\prime }E_{2}^{p,0}} as ring by the comparison theorem; that is, E 2 p , 0 = H p ( B G ; Q ) ≃ Q [ y 1 , … , y n ] . {\displaystyle E_{2}^{p,0}=H^{p}(BG;\mathbb {Q} )\simeq \mathbb {Q} [y_{1},\dots ,y_{n}].}
References
… excerpt ends here. Continue reading the full article.
